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Open Any file with specific Program?

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0

I want to set default a specific program for open ANY files absolutely ANY(*.*), any extension, any mime type. ABSOLUTELY ALL

I build a python program to automated choose the program for any file. the app-chooser.py content:

#!/usr/bin/python

import sys, os, os.path

filename = sys.argv[1];

extension = os.path.splitext(filename)[1];



if extension == ".txt":

  os.system("gedit " + filename);



if extension == ".mp4":

  os.system("vlc " + filename);



if extension == ".html":

  os.system("opera " + filename);



if extension == ".py":

  os.system("python " + filename);



if extension == ".sh":

  os.system("bash " + filename);



if extension == ".exe":

  os.system("wine " + filename);



exit()

The app-chooser.py are compiled in a standalone linux executable, located in "/usr/bin/app-chooser".

Here other example who i want:

xdg-mime default "app-chooser.py" */*

or

xdg-mime default "app-chooser.py" all/all

linux python gnome wildcards mime-types

share

asked 8 mins ago

vudaluzusavudaluzusa

1

New contributor

vudaluzusa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

0

I want to set default a specific program for open ANY files absolutely ANY(*.*), any extension, any mime type. ABSOLUTELY ALL

I build a python program to automated choose the program for any file. the app-chooser.py content:

#!/usr/bin/python

import sys, os, os.path

filename = sys.argv[1];

extension = os.path.splitext(filename)[1];



if extension == ".txt":

  os.system("gedit " + filename);



if extension == ".mp4":

  os.system("vlc " + filename);



if extension == ".html":

  os.system("opera " + filename);



if extension == ".py":

  os.system("python " + filename);



if extension == ".sh":

  os.system("bash " + filename);



if extension == ".exe":

  os.system("wine " + filename);



exit()

The app-chooser.py are compiled in a standalone linux executable, located in "/usr/bin/app-chooser".

Here other example who i want:

xdg-mime default "app-chooser.py" */*

or

xdg-mime default "app-chooser.py" all/all

linux python gnome wildcards mime-types

share

asked 8 mins ago

vudaluzusavudaluzusa

1

New contributor

vudaluzusa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

I want to set default a specific program for open ANY files absolutely ANY(*.*), any extension, any mime type. ABSOLUTELY ALL

I build a python program to automated choose the program for any file. the app-chooser.py content:

#!/usr/bin/python

import sys, os, os.path

filename = sys.argv[1];

extension = os.path.splitext(filename)[1];



if extension == ".txt":

  os.system("gedit " + filename);



if extension == ".mp4":

  os.system("vlc " + filename);



if extension == ".html":

  os.system("opera " + filename);



if extension == ".py":

  os.system("python " + filename);



if extension == ".sh":

  os.system("bash " + filename);



if extension == ".exe":

  os.system("wine " + filename);



exit()

The app-chooser.py are compiled in a standalone linux executable, located in "/usr/bin/app-chooser".

Here other example who i want:

xdg-mime default "app-chooser.py" */*

or

xdg-mime default "app-chooser.py" all/all

linux python gnome wildcards mime-types

share

asked 8 mins ago

vudaluzusavudaluzusa

1

New contributor

vudaluzusa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

#!/usr/bin/python

import sys, os, os.path

filename = sys.argv[1];

extension = os.path.splitext(filename)[1];



if extension == ".txt":

  os.system("gedit " + filename);



if extension == ".mp4":

  os.system("vlc " + filename);



if extension == ".html":

  os.system("opera " + filename);



if extension == ".py":

  os.system("python " + filename);



if extension == ".sh":

  os.system("bash " + filename);



if extension == ".exe":

  os.system("wine " + filename);



exit()

xdg-mime default "app-chooser.py" */*

xdg-mime default "app-chooser.py" all/all

share

asked 8 mins ago

vudaluzusavudaluzusa

1

New contributor

vudaluzusa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share

asked 8 mins ago

vudaluzusavudaluzusa

1

New contributor

vudaluzusa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 8 mins ago

vudaluzusavudaluzusa

1

New contributor

vudaluzusa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 8 mins ago

vudaluzusavudaluzusa

1