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'Var' does not name a type!
Announcing the arrival of Valued Associate #679: Cesar Manara
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I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
edited yesterday
Michel Keijzers
7,13451939
asked yesterday
2012User2012User
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
edited yesterday
Michel Keijzers
7,13451939
asked yesterday
2012User2012User
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
float z=x*y;will work
– Juraj
11 hours ago
add a comment |
I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
edited yesterday
Michel Keijzers
7,13451939
asked yesterday
2012User2012User
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I don't have much experience in C++ programming. I'm getting this error
'z' does not name a type!!!
which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!
float x=10; float y=50; float z;
z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
arduino-uno programming c++ error
arduino-uno programming c++ error
edited yesterday
Michel Keijzers
7,13451939
asked yesterday
2012User2012User
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
Michel Keijzers
7,13451939
asked yesterday
2012User2012User
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
Michel Keijzers
7,13451939
edited yesterday
Michel Keijzers
7,13451939
edited yesterday
Michel Keijzers
7,13451939
7,13451939
asked yesterday
2012User2012User
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
2012User2012User
154
asked yesterday
2012User2012User
154
154
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
float z=x*y;will work
– Juraj
11 hours ago
add a comment |
float z=x*y;will work
– Juraj
11 hours ago
float z=x*y; will work– Juraj
11 hours ago
float z=x*y; will work– Juraj
11 hours ago
add a comment |
1 Answer
1
active
oldest
votes
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Update
What even is easier and also works (thanks to Ruslan and Juraj):
float x=10; float y=50; float z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
yesterday
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
23 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
19 hours ago
andfloat z=x*y;
– Juraj
11 hours ago
@Juraj: Thanks; I added it
– Michel Keijzers
9 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Update
What even is easier and also works (thanks to Ruslan and Juraj):
float x=10; float y=50; float z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
yesterday
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
23 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
19 hours ago
andfloat z=x*y;
– Juraj
11 hours ago
@Juraj: Thanks; I added it
– Michel Keijzers
9 hours ago
add a comment |
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Update
What even is easier and also works (thanks to Ruslan and Juraj):
float x=10; float y=50; float z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
yesterday
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
23 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
19 hours ago
andfloat z=x*y;
– Juraj
11 hours ago
@Juraj: Thanks; I added it
– Michel Keijzers
9 hours ago
add a comment |
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Update
What even is easier and also works (thanks to Ruslan and Juraj):
float x=10; float y=50; float z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).
Try the following:
float x=10; float y=50; float z;
void setup() {
// put your setup code here, to run once:
z=x*y;
}
void loop() {
// put your main code here, to run repeatedly:
}
Update
What even is easier and also works (thanks to Ruslan and Juraj):
float x=10; float y=50; float z=x*y;
void setup() {
// put your setup code here, to run once:
}
void loop() {
// put your main code here, to run repeatedly:
}
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
edited 9 hours ago
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
answered yesterday
Michel KeijzersMichel Keijzers
7,13451939
7,13451939
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
yesterday
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
23 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
19 hours ago
andfloat z=x*y;
– Juraj
11 hours ago
@Juraj: Thanks; I added it
– Michel Keijzers
9 hours ago
add a comment |
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
yesterday
1
You can put an expression outside a function (e.g.float z=x*y;does have an expressionx*yin it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).
– Ruslan
23 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
19 hours ago
andfloat z=x*y;
– Juraj
11 hours ago
@Juraj: Thanks; I added it
– Michel Keijzers
9 hours ago
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
yesterday
Thank you. pretty much basic thing that I didn't know about C++.
– 2012User
yesterday
1
1
You can put an expression outside a function (e.g.
float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).– Ruslan
23 hours ago
You can put an expression outside a function (e.g.
float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).– Ruslan
23 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
19 hours ago
@Ruslan Thanks for the clarification; I added the word statement in my answer.
– Michel Keijzers
19 hours ago
and
float z=x*y;– Juraj
11 hours ago
and
float z=x*y;– Juraj
11 hours ago
@Juraj: Thanks; I added it
– Michel Keijzers
9 hours ago
@Juraj: Thanks; I added it
– Michel Keijzers
9 hours ago
add a comment |
2012User is a new contributor. Be nice, and check out our Code of Conduct.
2012User is a new contributor. Be nice, and check out our Code of Conduct.
2012User is a new contributor. Be nice, and check out our Code of Conduct.
2012User is a new contributor. Be nice, and check out our Code of Conduct.
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float z=x*y;will work– Juraj
11 hours ago