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How to run the “other” executable matching the same name found in PATH?
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Is there a concise way to call the "other" executable for find available in path that can be found with where?
C:repos>where find
C:WindowsSystem32find.exe
C:Program FilesGitusrbinfind.exe
C:UsersQwertycmdUnxUtils_wbinfind.exe
For example something like find~2 or wannabe whereget find -n 2 -- <arguments for find here>
windows bash unix-utils
asked yesterday
QwertyQwerty
299313
add a comment |
Is there a concise way to call the "other" executable for find available in path that can be found with where?
C:repos>where find
C:WindowsSystem32find.exe
C:Program FilesGitusrbinfind.exe
C:UsersQwertycmdUnxUtils_wbinfind.exe
For example something like find~2 or wannabe whereget find -n 2 -- <arguments for find here>
windows bash unix-utils
asked yesterday
QwertyQwerty
299313
add a comment |
Is there a concise way to call the "other" executable for find available in path that can be found with where?
C:repos>where find
C:WindowsSystem32find.exe
C:Program FilesGitusrbinfind.exe
C:UsersQwertycmdUnxUtils_wbinfind.exe
For example something like find~2 or wannabe whereget find -n 2 -- <arguments for find here>
windows bash unix-utils
asked yesterday
QwertyQwerty
299313
Is there a concise way to call the "other" executable for find available in path that can be found with where?
C:repos>where find
C:WindowsSystem32find.exe
C:Program FilesGitusrbinfind.exe
C:UsersQwertycmdUnxUtils_wbinfind.exe
For example something like find~2 or wannabe whereget find -n 2 -- <arguments for find here>
windows bash unix-utils
windows bash unix-utils
asked yesterday
QwertyQwerty
299313
asked yesterday
QwertyQwerty
299313
asked yesterday
QwertyQwerty
299313
asked yesterday
QwertyQwerty
299313
asked yesterday
QwertyQwerty
299313
299313
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Calling an executable without the full path will always find and use the first matching filename by searching the directories in $PATH. For your example, if you always want to use the git find, simply ensure that the path to it appears in your $PATH before the Windows find. If this is unsatisfactory or impossible (e.g., due to policy), you should either create an alias in bash for it, or always call it using the full pathname.
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
Alias is a great idea, thanks!
– Qwerty
yesterday
add a comment |
I will just put it here
$ alias whereget='_whereget() { A=$1; B=$2; shift 2; eval "$(where $B | head -$A | tail -1)" $@; }; _whereget'
$ whereget 2 find . -type d
Unfortunately this solution only works in bash, not in Windows cmd.
answered yesterday
QwertyQwerty
299313
The alias won't work either in a bash script.
– xenoid
yesterday
Interesting, it only works in the active console. Would you mind clarifying why? @xenoid
– Qwerty
20 hours ago
1
Because when you run a script, it's a new bash instance in which the alias is not defined (only properly exported environment variables are inherited from the parent). If your "source" the file, it is run in the same bash instance, and the alias is used. And I don't see a way to define the alias for a script, since on the interactive bash instances read the profile files (.bashrcand.bash_profile).
– xenoid
18 hours ago
Right, then I will put it to~/.bashrcfile
– Qwerty
16 hours ago
won't work, because, as I said .bashrc is only used by interactive shells. It is not run by instances ofbashthat are started to run scripts. And you can't use functions for the same reason.
– xenoid
16 hours ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
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active
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active
oldest
votes
Calling an executable without the full path will always find and use the first matching filename by searching the directories in $PATH. For your example, if you always want to use the git find, simply ensure that the path to it appears in your $PATH before the Windows find. If this is unsatisfactory or impossible (e.g., due to policy), you should either create an alias in bash for it, or always call it using the full pathname.
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
Alias is a great idea, thanks!
– Qwerty
yesterday
add a comment |
Calling an executable without the full path will always find and use the first matching filename by searching the directories in $PATH. For your example, if you always want to use the git find, simply ensure that the path to it appears in your $PATH before the Windows find. If this is unsatisfactory or impossible (e.g., due to policy), you should either create an alias in bash for it, or always call it using the full pathname.
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
Alias is a great idea, thanks!
– Qwerty
yesterday
add a comment |
Calling an executable without the full path will always find and use the first matching filename by searching the directories in $PATH. For your example, if you always want to use the git find, simply ensure that the path to it appears in your $PATH before the Windows find. If this is unsatisfactory or impossible (e.g., due to policy), you should either create an alias in bash for it, or always call it using the full pathname.
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
Calling an executable without the full path will always find and use the first matching filename by searching the directories in $PATH. For your example, if you always want to use the git find, simply ensure that the path to it appears in your $PATH before the Windows find. If this is unsatisfactory or impossible (e.g., due to policy), you should either create an alias in bash for it, or always call it using the full pathname.
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
answered yesterday
Jeff ZeitlinJeff Zeitlin
1,554618
1,554618
Alias is a great idea, thanks!
– Qwerty
yesterday
add a comment |
Alias is a great idea, thanks!
– Qwerty
yesterday
Alias is a great idea, thanks!
– Qwerty
yesterday
Alias is a great idea, thanks!
– Qwerty
yesterday
add a comment |
I will just put it here
$ alias whereget='_whereget() { A=$1; B=$2; shift 2; eval "$(where $B | head -$A | tail -1)" $@; }; _whereget'
$ whereget 2 find . -type d
Unfortunately this solution only works in bash, not in Windows cmd.
answered yesterday
QwertyQwerty
299313
The alias won't work either in a bash script.
– xenoid
yesterday
Interesting, it only works in the active console. Would you mind clarifying why? @xenoid
– Qwerty
20 hours ago
1
Because when you run a script, it's a new bash instance in which the alias is not defined (only properly exported environment variables are inherited from the parent). If your "source" the file, it is run in the same bash instance, and the alias is used. And I don't see a way to define the alias for a script, since on the interactive bash instances read the profile files (.bashrcand.bash_profile).
– xenoid
18 hours ago
Right, then I will put it to~/.bashrcfile
– Qwerty
16 hours ago
won't work, because, as I said .bashrc is only used by interactive shells. It is not run by instances ofbashthat are started to run scripts. And you can't use functions for the same reason.
– xenoid
16 hours ago
add a comment |
I will just put it here
$ alias whereget='_whereget() { A=$1; B=$2; shift 2; eval "$(where $B | head -$A | tail -1)" $@; }; _whereget'
$ whereget 2 find . -type d
Unfortunately this solution only works in bash, not in Windows cmd.
answered yesterday
QwertyQwerty
299313
The alias won't work either in a bash script.
– xenoid
yesterday
Interesting, it only works in the active console. Would you mind clarifying why? @xenoid
– Qwerty
20 hours ago
1
Because when you run a script, it's a new bash instance in which the alias is not defined (only properly exported environment variables are inherited from the parent). If your "source" the file, it is run in the same bash instance, and the alias is used. And I don't see a way to define the alias for a script, since on the interactive bash instances read the profile files (.bashrcand.bash_profile).
– xenoid
18 hours ago
Right, then I will put it to~/.bashrcfile
– Qwerty
16 hours ago
won't work, because, as I said .bashrc is only used by interactive shells. It is not run by instances ofbashthat are started to run scripts. And you can't use functions for the same reason.
– xenoid
16 hours ago
add a comment |
I will just put it here
$ alias whereget='_whereget() { A=$1; B=$2; shift 2; eval "$(where $B | head -$A | tail -1)" $@; }; _whereget'
$ whereget 2 find . -type d
Unfortunately this solution only works in bash, not in Windows cmd.
answered yesterday
QwertyQwerty
299313
I will just put it here
$ alias whereget='_whereget() { A=$1; B=$2; shift 2; eval "$(where $B | head -$A | tail -1)" $@; }; _whereget'
$ whereget 2 find . -type d
Unfortunately this solution only works in bash, not in Windows cmd.
answered yesterday
QwertyQwerty
299313
answered yesterday
QwertyQwerty
299313
answered yesterday
QwertyQwerty
299313
answered yesterday
QwertyQwerty
299313
299313
The alias won't work either in a bash script.
– xenoid
yesterday
Interesting, it only works in the active console. Would you mind clarifying why? @xenoid
– Qwerty
20 hours ago
1
Because when you run a script, it's a new bash instance in which the alias is not defined (only properly exported environment variables are inherited from the parent). If your "source" the file, it is run in the same bash instance, and the alias is used. And I don't see a way to define the alias for a script, since on the interactive bash instances read the profile files (.bashrcand.bash_profile).
– xenoid
18 hours ago
Right, then I will put it to~/.bashrcfile
– Qwerty
16 hours ago
won't work, because, as I said .bashrc is only used by interactive shells. It is not run by instances ofbashthat are started to run scripts. And you can't use functions for the same reason.
– xenoid
16 hours ago
add a comment |
The alias won't work either in a bash script.
– xenoid
yesterday
Interesting, it only works in the active console. Would you mind clarifying why? @xenoid
– Qwerty
20 hours ago
1
Because when you run a script, it's a new bash instance in which the alias is not defined (only properly exported environment variables are inherited from the parent). If your "source" the file, it is run in the same bash instance, and the alias is used. And I don't see a way to define the alias for a script, since on the interactive bash instances read the profile files (.bashrcand.bash_profile).
– xenoid
18 hours ago
Right, then I will put it to~/.bashrcfile
– Qwerty
16 hours ago
won't work, because, as I said .bashrc is only used by interactive shells. It is not run by instances ofbashthat are started to run scripts. And you can't use functions for the same reason.
– xenoid
16 hours ago
The alias won't work either in a bash script.
– xenoid
yesterday
The alias won't work either in a bash script.
– xenoid
yesterday
Interesting, it only works in the active console. Would you mind clarifying why? @xenoid
– Qwerty
20 hours ago
Interesting, it only works in the active console. Would you mind clarifying why? @xenoid
– Qwerty
20 hours ago
1
1
Because when you run a script, it's a new bash instance in which the alias is not defined (only properly exported environment variables are inherited from the parent). If your "source" the file, it is run in the same bash instance, and the alias is used. And I don't see a way to define the alias for a script, since on the interactive bash instances read the profile files (
.bashrc and .bash_profile).– xenoid
18 hours ago
Because when you run a script, it's a new bash instance in which the alias is not defined (only properly exported environment variables are inherited from the parent). If your "source" the file, it is run in the same bash instance, and the alias is used. And I don't see a way to define the alias for a script, since on the interactive bash instances read the profile files (
.bashrc and .bash_profile).– xenoid
18 hours ago
Right, then I will put it to
~/.bashrc file– Qwerty
16 hours ago
Right, then I will put it to
~/.bashrc file– Qwerty
16 hours ago
won't work, because, as I said .bashrc is only used by interactive shells. It is not run by instances of
bash that are started to run scripts. And you can't use functions for the same reason.– xenoid
16 hours ago
won't work, because, as I said .bashrc is only used by interactive shells. It is not run by instances of
bash that are started to run scripts. And you can't use functions for the same reason.– xenoid
16 hours ago
add a comment |
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