Decimal to roman pythonRoman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral...
Fully-Firstable Anagram Sets
Did Shadowfax go to Valinor?
What mechanic is there to disable a threat instead of killing it?
How much of data wrangling is a data scientist's job?
Where does SFDX store details about scratch orgs?
Why is the 'in' operator throwing an error with a string literal instead of logging false?
Can a rocket refuel on Mars from water?
Is it legal for company to use my work email to pretend I still work there?
Stopping power of mountain vs road bike
Theorems that impeded progress
90's TV series where a boy goes to another dimension through portal near power lines
Today is the Center
Do I have a twin with permutated remainders?
prove that the matrix A is diagonalizable
How to model explosives?
Why is it a bad idea to hire a hitman to eliminate most corrupt politicians?
What exploit are these user agents trying to use?
Is delete *p an alternative to delete [] p?
I'm flying to France today and my passport expires in less than 2 months
Arrow those variables!
What's the difference between 'rename' and 'mv'?
Infinite Abelian subgroup of infinite non Abelian group example
Why are electrically insulating heatsinks so rare? Is it just cost?
Combinations of multiple lists
Decimal to roman python
Roman Numeral to Decimal ConversionConverting Roman numerals to decimalRoman numeral converter in RubyRoman numerals to decimalRoman numeral to decimal converterCurrency converter in Python 2.7“Merchants Guide to Galaxy” challengeGreed Dice Scoring Game expanded - Python KoansArea and volume calculatorNumber of possible numbers in roman number string
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
$begingroup$
I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.
roman_dict = {1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
500: 'D', 900: 'CM', 1000: 'M'}
divide_list = [1000, 100, 10, 1]
def not_in_dict(fixed_decimal, divide_num):
sub_count = 0
sub_roman_multi = roman_dict[divide_num]
temp_decimal = fixed_decimal
while temp_decimal not in roman_dict:
temp_decimal -= divide_num
sub_count += 1
return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)
def decimal_to_roman(decimal):
original_decimal = decimal
roman = ""
for divide_num in divide_list:
if decimal >= divide_num:
reminder = decimal//divide_num
if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
roman += roman_dict[(reminder*divide_num)]
decimal -= reminder*divide_num
else:
roman += not_in_dict(reminder*divide_num, divide_num)
decimal -= (reminder*divide_num)
return str(original_decimal)+' = '+roman
python roman-numerals
edited 13 hours ago
Graipher
26.7k54092
asked 14 hours ago
OfeksOfeks
283
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.
roman_dict = {1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
500: 'D', 900: 'CM', 1000: 'M'}
divide_list = [1000, 100, 10, 1]
def not_in_dict(fixed_decimal, divide_num):
sub_count = 0
sub_roman_multi = roman_dict[divide_num]
temp_decimal = fixed_decimal
while temp_decimal not in roman_dict:
temp_decimal -= divide_num
sub_count += 1
return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)
def decimal_to_roman(decimal):
original_decimal = decimal
roman = ""
for divide_num in divide_list:
if decimal >= divide_num:
reminder = decimal//divide_num
if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
roman += roman_dict[(reminder*divide_num)]
decimal -= reminder*divide_num
else:
roman += not_in_dict(reminder*divide_num, divide_num)
decimal -= (reminder*divide_num)
return str(original_decimal)+' = '+roman
python roman-numerals
edited 13 hours ago
Graipher
26.7k54092
asked 14 hours ago
OfeksOfeks
283
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.
roman_dict = {1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
500: 'D', 900: 'CM', 1000: 'M'}
divide_list = [1000, 100, 10, 1]
def not_in_dict(fixed_decimal, divide_num):
sub_count = 0
sub_roman_multi = roman_dict[divide_num]
temp_decimal = fixed_decimal
while temp_decimal not in roman_dict:
temp_decimal -= divide_num
sub_count += 1
return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)
def decimal_to_roman(decimal):
original_decimal = decimal
roman = ""
for divide_num in divide_list:
if decimal >= divide_num:
reminder = decimal//divide_num
if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
roman += roman_dict[(reminder*divide_num)]
decimal -= reminder*divide_num
else:
roman += not_in_dict(reminder*divide_num, divide_num)
decimal -= (reminder*divide_num)
return str(original_decimal)+' = '+roman
python roman-numerals
edited 13 hours ago
Graipher
26.7k54092
asked 14 hours ago
OfeksOfeks
283
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I'm a beginner as you can see and I would like to know how I can improve my code. Studying for 6 months now. Thank you.
roman_dict = {1: 'I', 4: 'IV', 5: 'V', 9: 'IX', 10: 'X', 40: 'XL', 50: 'L', 90: 'XC', 100: 'C', 400: 'CD',
500: 'D', 900: 'CM', 1000: 'M'}
divide_list = [1000, 100, 10, 1]
def not_in_dict(fixed_decimal, divide_num):
sub_count = 0
sub_roman_multi = roman_dict[divide_num]
temp_decimal = fixed_decimal
while temp_decimal not in roman_dict:
temp_decimal -= divide_num
sub_count += 1
return roman_dict[temp_decimal]+(sub_count*sub_roman_multi)
def decimal_to_roman(decimal):
original_decimal = decimal
roman = ""
for divide_num in divide_list:
if decimal >= divide_num:
reminder = decimal//divide_num
if(reminder >= 1) and ((reminder*divide_num) in roman_dict):
roman += roman_dict[(reminder*divide_num)]
decimal -= reminder*divide_num
else:
roman += not_in_dict(reminder*divide_num, divide_num)
decimal -= (reminder*divide_num)
return str(original_decimal)+' = '+roman
python roman-numerals
python roman-numerals
edited 13 hours ago
Graipher
26.7k54092
asked 14 hours ago
OfeksOfeks
283
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 13 hours ago
Graipher
26.7k54092
asked 14 hours ago
OfeksOfeks
283
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 13 hours ago
Graipher
26.7k54092
edited 13 hours ago
Graipher
26.7k54092
edited 13 hours ago
Graipher
26.7k54092
26.7k54092
asked 14 hours ago
OfeksOfeks
283
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 14 hours ago
OfeksOfeks
283
asked 14 hours ago
OfeksOfeks
283
283
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Ofeks is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.
Instead of manually adding strings (something you should basically never do in in Python), use str.join.
ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
(90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
(5, 'V'), (4, 'IV'), (1, 'I')]
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
while x >= value:
x -= value
out.append(literal)
return "".join(out)
Instead of the while loop you can also use integer division like you did:
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
n = x // value # will be 0 if value is too large
out.extend([literal] * n) # will not do anything if n == 0
x -= n * value # will also not do anything if n == 0
return "".join(out)
answered 13 hours ago
GraipherGraipher
26.7k54092
$endgroup$
$begingroup$
wow. looks so easy now, thank you. that's great.
$endgroup$
– Ofeks
11 hours ago
$begingroup$
@Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
$endgroup$
– Graipher
11 hours ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "196"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Ofeks is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.
Instead of manually adding strings (something you should basically never do in in Python), use str.join.
ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
(90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
(5, 'V'), (4, 'IV'), (1, 'I')]
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
while x >= value:
x -= value
out.append(literal)
return "".join(out)
Instead of the while loop you can also use integer division like you did:
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
n = x // value # will be 0 if value is too large
out.extend([literal] * n) # will not do anything if n == 0
x -= n * value # will also not do anything if n == 0
return "".join(out)
answered 13 hours ago
GraipherGraipher
26.7k54092
$endgroup$
$begingroup$
wow. looks so easy now, thank you. that's great.
$endgroup$
– Ofeks
11 hours ago
$begingroup$
@Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
$endgroup$
– Graipher
11 hours ago
add a comment |
$begingroup$
If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.
Instead of manually adding strings (something you should basically never do in in Python), use str.join.
ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
(90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
(5, 'V'), (4, 'IV'), (1, 'I')]
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
while x >= value:
x -= value
out.append(literal)
return "".join(out)
Instead of the while loop you can also use integer division like you did:
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
n = x // value # will be 0 if value is too large
out.extend([literal] * n) # will not do anything if n == 0
x -= n * value # will also not do anything if n == 0
return "".join(out)
answered 13 hours ago
GraipherGraipher
26.7k54092
$endgroup$
$begingroup$
wow. looks so easy now, thank you. that's great.
$endgroup$
– Ofeks
11 hours ago
$begingroup$
@Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
$endgroup$
– Graipher
11 hours ago
add a comment |
$begingroup$
If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.
Instead of manually adding strings (something you should basically never do in in Python), use str.join.
ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
(90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
(5, 'V'), (4, 'IV'), (1, 'I')]
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
while x >= value:
x -= value
out.append(literal)
return "".join(out)
Instead of the while loop you can also use integer division like you did:
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
n = x // value # will be 0 if value is too large
out.extend([literal] * n) # will not do anything if n == 0
x -= n * value # will also not do anything if n == 0
return "".join(out)
answered 13 hours ago
GraipherGraipher
26.7k54092
$endgroup$
If you use a list of tuples instead of a dictionary and reverse the order, you can simply iterate over it. Your while loop also becomes a lot easier to understand and there is no longer any need to outsource it to another function that returns the literal and its count.
Instead of manually adding strings (something you should basically never do in in Python), use str.join.
ROMAN_LITERALS = [(1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'),
(90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'),
(5, 'V'), (4, 'IV'), (1, 'I')]
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
while x >= value:
x -= value
out.append(literal)
return "".join(out)
Instead of the while loop you can also use integer division like you did:
def decimal_to_roman(x):
out = []
for value, literal in ROMAN_LITERALS:
n = x // value # will be 0 if value is too large
out.extend([literal] * n) # will not do anything if n == 0
x -= n * value # will also not do anything if n == 0
return "".join(out)
answered 13 hours ago
GraipherGraipher
26.7k54092
edited 10 hours ago
answered 13 hours ago
GraipherGraipher
26.7k54092
answered 13 hours ago
GraipherGraipher
26.7k54092
answered 13 hours ago
GraipherGraipher
26.7k54092
26.7k54092
$begingroup$
wow. looks so easy now, thank you. that's great.
$endgroup$
– Ofeks
11 hours ago
$begingroup$
@Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
$endgroup$
– Graipher
11 hours ago
add a comment |
$begingroup$
wow. looks so easy now, thank you. that's great.
$endgroup$
– Ofeks
11 hours ago
$begingroup$
@Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
$endgroup$
– Graipher
11 hours ago
$begingroup$
wow. looks so easy now, thank you. that's great.
$endgroup$
– Ofeks
11 hours ago
$begingroup$
wow. looks so easy now, thank you. that's great.
$endgroup$
– Ofeks
11 hours ago
$begingroup$
@Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
$endgroup$
– Graipher
11 hours ago
$begingroup$
@Ofeks: If this helped you, consider accepting it as the correct answer (by clicking the checkmark to the left of the answer). It is customary to wait about 24 hours, though, to give everyon on the globe a chance to answer and not discourage other people from commenting.
$endgroup$
– Graipher
11 hours ago
add a comment |
Ofeks is a new contributor. Be nice, and check out our Code of Conduct.
Ofeks is a new contributor. Be nice, and check out our Code of Conduct.
Ofeks is a new contributor. Be nice, and check out our Code of Conduct.
Ofeks is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Code Review Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcodereview.stackexchange.com%2fquestions%2f216852%2fdecimal-to-roman-python%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
