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Autogenerate category based on unique combinations of cells
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This seems more confusing than it really is, but I have an Excel sheet that categorizes different combinations of answers.
Each category or tier is based on a unique combination of Yes and No answers between 7 columns.
e.g.:
I'm looking for a way where I can have a blank sheet, and when a user fills in the Yes/No answers, the Tier # will auto-generate based on their responses.
Right now the only possible solution in my limited knowledge is a really long nested IF statement.
Surely a better way exists in Excel? Thanks in advance!!
microsoft-excel worksheet-function
New contributor
add a comment |
This seems more confusing than it really is, but I have an Excel sheet that categorizes different combinations of answers.
Each category or tier is based on a unique combination of Yes and No answers between 7 columns.
e.g.:
I'm looking for a way where I can have a blank sheet, and when a user fills in the Yes/No answers, the Tier # will auto-generate based on their responses.
Right now the only possible solution in my limited knowledge is a really long nested IF statement.
Surely a better way exists in Excel? Thanks in advance!!
microsoft-excel worksheet-function
New contributor
add a comment |
This seems more confusing than it really is, but I have an Excel sheet that categorizes different combinations of answers.
Each category or tier is based on a unique combination of Yes and No answers between 7 columns.
e.g.:
I'm looking for a way where I can have a blank sheet, and when a user fills in the Yes/No answers, the Tier # will auto-generate based on their responses.
Right now the only possible solution in my limited knowledge is a really long nested IF statement.
Surely a better way exists in Excel? Thanks in advance!!
microsoft-excel worksheet-function
New contributor
This seems more confusing than it really is, but I have an Excel sheet that categorizes different combinations of answers.
Each category or tier is based on a unique combination of Yes and No answers between 7 columns.
e.g.:
I'm looking for a way where I can have a blank sheet, and when a user fills in the Yes/No answers, the Tier # will auto-generate based on their responses.
Right now the only possible solution in my limited knowledge is a really long nested IF statement.
Surely a better way exists in Excel? Thanks in advance!!
microsoft-excel worksheet-function
microsoft-excel worksheet-function
New contributor
New contributor
edited 9 hours ago
An Nuyen
New contributor
asked 10 hours ago
An NuyenAn Nuyen
11
11
New contributor
New contributor
add a comment |
add a comment |
1 Answer
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votes
This can be done in Excel 2016 with a helper column and TEXTJOIN
.
Assuming the list of Tiers is in Sheet2
, add a column with the following formula in it:
=TEXTJOIN(,TRUE,B2:H2)
Then in Sheet1
, add the following formula where you want the tier to appear:
=INDEX(Sheet2!A$2:A$6,(MATCH(TEXTJOIN(,TRUE,B2:H2),Sheet2!I$2:I$6,0)))
TEXTJOIN
will essentially convert all y/n
values into a single string. MATCH
will then look for the matching string on Sheet2
and INDEX
will return the corresponding tier.
There's definitely something useful about converting the line into a single string, but I can't quite get the =INDEX part you suggested to work...it basically just copies over the column of Tier names instead of selecting the appropriate/matching Tier.
– An Nuyen
9 hours ago
Quite correct: I forgot to make one of the references absolute. See my edited answer
– cybernetic.nomad
9 hours ago
add a comment |
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1 Answer
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1 Answer
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votes
This can be done in Excel 2016 with a helper column and TEXTJOIN
.
Assuming the list of Tiers is in Sheet2
, add a column with the following formula in it:
=TEXTJOIN(,TRUE,B2:H2)
Then in Sheet1
, add the following formula where you want the tier to appear:
=INDEX(Sheet2!A$2:A$6,(MATCH(TEXTJOIN(,TRUE,B2:H2),Sheet2!I$2:I$6,0)))
TEXTJOIN
will essentially convert all y/n
values into a single string. MATCH
will then look for the matching string on Sheet2
and INDEX
will return the corresponding tier.
There's definitely something useful about converting the line into a single string, but I can't quite get the =INDEX part you suggested to work...it basically just copies over the column of Tier names instead of selecting the appropriate/matching Tier.
– An Nuyen
9 hours ago
Quite correct: I forgot to make one of the references absolute. See my edited answer
– cybernetic.nomad
9 hours ago
add a comment |
This can be done in Excel 2016 with a helper column and TEXTJOIN
.
Assuming the list of Tiers is in Sheet2
, add a column with the following formula in it:
=TEXTJOIN(,TRUE,B2:H2)
Then in Sheet1
, add the following formula where you want the tier to appear:
=INDEX(Sheet2!A$2:A$6,(MATCH(TEXTJOIN(,TRUE,B2:H2),Sheet2!I$2:I$6,0)))
TEXTJOIN
will essentially convert all y/n
values into a single string. MATCH
will then look for the matching string on Sheet2
and INDEX
will return the corresponding tier.
There's definitely something useful about converting the line into a single string, but I can't quite get the =INDEX part you suggested to work...it basically just copies over the column of Tier names instead of selecting the appropriate/matching Tier.
– An Nuyen
9 hours ago
Quite correct: I forgot to make one of the references absolute. See my edited answer
– cybernetic.nomad
9 hours ago
add a comment |
This can be done in Excel 2016 with a helper column and TEXTJOIN
.
Assuming the list of Tiers is in Sheet2
, add a column with the following formula in it:
=TEXTJOIN(,TRUE,B2:H2)
Then in Sheet1
, add the following formula where you want the tier to appear:
=INDEX(Sheet2!A$2:A$6,(MATCH(TEXTJOIN(,TRUE,B2:H2),Sheet2!I$2:I$6,0)))
TEXTJOIN
will essentially convert all y/n
values into a single string. MATCH
will then look for the matching string on Sheet2
and INDEX
will return the corresponding tier.
This can be done in Excel 2016 with a helper column and TEXTJOIN
.
Assuming the list of Tiers is in Sheet2
, add a column with the following formula in it:
=TEXTJOIN(,TRUE,B2:H2)
Then in Sheet1
, add the following formula where you want the tier to appear:
=INDEX(Sheet2!A$2:A$6,(MATCH(TEXTJOIN(,TRUE,B2:H2),Sheet2!I$2:I$6,0)))
TEXTJOIN
will essentially convert all y/n
values into a single string. MATCH
will then look for the matching string on Sheet2
and INDEX
will return the corresponding tier.
edited 9 hours ago
answered 9 hours ago
cybernetic.nomadcybernetic.nomad
2,651617
2,651617
There's definitely something useful about converting the line into a single string, but I can't quite get the =INDEX part you suggested to work...it basically just copies over the column of Tier names instead of selecting the appropriate/matching Tier.
– An Nuyen
9 hours ago
Quite correct: I forgot to make one of the references absolute. See my edited answer
– cybernetic.nomad
9 hours ago
add a comment |
There's definitely something useful about converting the line into a single string, but I can't quite get the =INDEX part you suggested to work...it basically just copies over the column of Tier names instead of selecting the appropriate/matching Tier.
– An Nuyen
9 hours ago
Quite correct: I forgot to make one of the references absolute. See my edited answer
– cybernetic.nomad
9 hours ago
There's definitely something useful about converting the line into a single string, but I can't quite get the =INDEX part you suggested to work...it basically just copies over the column of Tier names instead of selecting the appropriate/matching Tier.
– An Nuyen
9 hours ago
There's definitely something useful about converting the line into a single string, but I can't quite get the =INDEX part you suggested to work...it basically just copies over the column of Tier names instead of selecting the appropriate/matching Tier.
– An Nuyen
9 hours ago
Quite correct: I forgot to make one of the references absolute. See my edited answer
– cybernetic.nomad
9 hours ago
Quite correct: I forgot to make one of the references absolute. See my edited answer
– cybernetic.nomad
9 hours ago
add a comment |
An Nuyen is a new contributor. Be nice, and check out our Code of Conduct.
An Nuyen is a new contributor. Be nice, and check out our Code of Conduct.
An Nuyen is a new contributor. Be nice, and check out our Code of Conduct.
An Nuyen is a new contributor. Be nice, and check out our Code of Conduct.
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