Creating one variable from a list of variables in R? Announcing the arrival of Valued...

Does Prince Arnaud cause someone holding the Princess to lose?

2 sample t test for sample sizes - 30,000 and 150,000

Why these surprising proportionalities of integrals involving odd zeta values?

Is Mathematical Biology analogous to Mathematical Physics?

Protagonist's race is hidden - should I reveal it?

Can 'non' with gerundive mean both lack of obligation and negative obligation?

What is the difference between 准时 and 按时?

Is there a verb for listening stealthily?

Unix AIX passing variable and arguments to expect and spawn

Lights are flickering on and off after accidentally bumping into light switch

Converting a text document with special format to Pandas DataFrame

Why did Bronn offer to be Tyrion Lannister's champion in trial by combat?

Is my guitar’s action too high?

How to ask rejected full-time candidates to apply to teach individual courses?

Why are two-digit numbers in Jonathan Swift's "Gulliver's Travels" (1726) written in "German style"?

Why does my GNOME settings mention "Moto C Plus"?

How to break 信じようとしていただけかも知れない into separate parts?

Coin Game with infinite paradox

How is an IPA symbol that lacks a name (e.g. ɲ) called?

How to create a command for the "strange m" symbol in latex?

How to leave only the following strings?

Why did Israel vote against lifting the American embargo on Cuba?

A journey... into the MIND

Trying to enter the Fox's den



Creating one variable from a list of variables in R?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!R dplyr/tidyr: “mutate” new columns with data from other observationsFunction for Tidy chisq.test Output for Visualizing or Filtering P-ValuesShiny: Create reactive filter using different variables.Create a Table with Alternating Total Rows Followed by Sub-Rows Using Dplyr and TidyverseUsing switch statement within dplyr's mutateConditional Recoding - Using a Vector of Columns within Mutate_at Together with If_else and Dplyr::RecodeCreating and using new variables in function in R: NSE programing error in the tidyversedplyr mutate-ifelse combination not creating correct conditional variableTidyverse — integrating mutate select and case when to likert scalesCan I create a new numerical variable using dplyr and <= and >= operators to subset values from an existing vector?





.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}







6















I have a sequence of variables in a dataframe (over 100) and I would like to create an indicator variable for if particular text patterns are present in any of the variables. Below is an example with three variables. One solution I've found is using tidyr::unite() followed by dplyr::mutate(), but I'm interested in a solution where I do not have to unite the variables.



c1<-c("T1", "X1", "T6", "R5")
c2<-c("R4", "C6", "C7", "X3")
c3<-c("C5", "C2", "X4", "T2")

df<-data.frame(c1, c2, c3)

c1 c2 c3
1 T1 R4 C5
2 X1 C6 C2
3 T6 C7 X4
4 R5 X3 T2

code.vec<-c("T1", "T2", "T3", "T4") #Text patterns of interest
code_regex<-paste(code.vec, collapse="|")

new<-df %>%
unite(all_c, c1:c3, remove=FALSE) %>%
mutate(indicator=if_else(grepl(code_regex, all_c), 1, 0)) %>%
select(-(all_c))

c1 c2 c3 indicator
1 T1 R4 C5 1
2 X1 C6 C2 0
3 T6 C7 X4 0
4 R5 X3 T2 1


Above is an example that produces the desired result, however I feel as if there should be a way of doing this in tidyverse without having to unite the variables. This is something that SAS handles very easily using an ARRAY statement and a DO loop, and I'm hoping R has a good way of handling this.



The real dataframe has many additional variables besides from the "c" fields to search, so a solution that involves searching every column would require subsetting the dataframe to first only contain the variables I want to search, and then joining the data back with the other variables.










share|improve this question

























  • You said you don't want to use unite, but it's worth noting that passing the argument remove = FALSE has unite create a column of the united variables leaving the others intact. Might be convenient in this case.

    – camille
    11 hours ago











  • Yes, it is convenient. And it does work. I just feel like there may be a simpler approach I'm missing that doesn't need to create a united variable.

    – patward5656
    11 hours ago


















6















I have a sequence of variables in a dataframe (over 100) and I would like to create an indicator variable for if particular text patterns are present in any of the variables. Below is an example with three variables. One solution I've found is using tidyr::unite() followed by dplyr::mutate(), but I'm interested in a solution where I do not have to unite the variables.



c1<-c("T1", "X1", "T6", "R5")
c2<-c("R4", "C6", "C7", "X3")
c3<-c("C5", "C2", "X4", "T2")

df<-data.frame(c1, c2, c3)

c1 c2 c3
1 T1 R4 C5
2 X1 C6 C2
3 T6 C7 X4
4 R5 X3 T2

code.vec<-c("T1", "T2", "T3", "T4") #Text patterns of interest
code_regex<-paste(code.vec, collapse="|")

new<-df %>%
unite(all_c, c1:c3, remove=FALSE) %>%
mutate(indicator=if_else(grepl(code_regex, all_c), 1, 0)) %>%
select(-(all_c))

c1 c2 c3 indicator
1 T1 R4 C5 1
2 X1 C6 C2 0
3 T6 C7 X4 0
4 R5 X3 T2 1


Above is an example that produces the desired result, however I feel as if there should be a way of doing this in tidyverse without having to unite the variables. This is something that SAS handles very easily using an ARRAY statement and a DO loop, and I'm hoping R has a good way of handling this.



The real dataframe has many additional variables besides from the "c" fields to search, so a solution that involves searching every column would require subsetting the dataframe to first only contain the variables I want to search, and then joining the data back with the other variables.










share|improve this question

























  • You said you don't want to use unite, but it's worth noting that passing the argument remove = FALSE has unite create a column of the united variables leaving the others intact. Might be convenient in this case.

    – camille
    11 hours ago











  • Yes, it is convenient. And it does work. I just feel like there may be a simpler approach I'm missing that doesn't need to create a united variable.

    – patward5656
    11 hours ago














6












6








6








I have a sequence of variables in a dataframe (over 100) and I would like to create an indicator variable for if particular text patterns are present in any of the variables. Below is an example with three variables. One solution I've found is using tidyr::unite() followed by dplyr::mutate(), but I'm interested in a solution where I do not have to unite the variables.



c1<-c("T1", "X1", "T6", "R5")
c2<-c("R4", "C6", "C7", "X3")
c3<-c("C5", "C2", "X4", "T2")

df<-data.frame(c1, c2, c3)

c1 c2 c3
1 T1 R4 C5
2 X1 C6 C2
3 T6 C7 X4
4 R5 X3 T2

code.vec<-c("T1", "T2", "T3", "T4") #Text patterns of interest
code_regex<-paste(code.vec, collapse="|")

new<-df %>%
unite(all_c, c1:c3, remove=FALSE) %>%
mutate(indicator=if_else(grepl(code_regex, all_c), 1, 0)) %>%
select(-(all_c))

c1 c2 c3 indicator
1 T1 R4 C5 1
2 X1 C6 C2 0
3 T6 C7 X4 0
4 R5 X3 T2 1


Above is an example that produces the desired result, however I feel as if there should be a way of doing this in tidyverse without having to unite the variables. This is something that SAS handles very easily using an ARRAY statement and a DO loop, and I'm hoping R has a good way of handling this.



The real dataframe has many additional variables besides from the "c" fields to search, so a solution that involves searching every column would require subsetting the dataframe to first only contain the variables I want to search, and then joining the data back with the other variables.










share|improve this question
















I have a sequence of variables in a dataframe (over 100) and I would like to create an indicator variable for if particular text patterns are present in any of the variables. Below is an example with three variables. One solution I've found is using tidyr::unite() followed by dplyr::mutate(), but I'm interested in a solution where I do not have to unite the variables.



c1<-c("T1", "X1", "T6", "R5")
c2<-c("R4", "C6", "C7", "X3")
c3<-c("C5", "C2", "X4", "T2")

df<-data.frame(c1, c2, c3)

c1 c2 c3
1 T1 R4 C5
2 X1 C6 C2
3 T6 C7 X4
4 R5 X3 T2

code.vec<-c("T1", "T2", "T3", "T4") #Text patterns of interest
code_regex<-paste(code.vec, collapse="|")

new<-df %>%
unite(all_c, c1:c3, remove=FALSE) %>%
mutate(indicator=if_else(grepl(code_regex, all_c), 1, 0)) %>%
select(-(all_c))

c1 c2 c3 indicator
1 T1 R4 C5 1
2 X1 C6 C2 0
3 T6 C7 X4 0
4 R5 X3 T2 1


Above is an example that produces the desired result, however I feel as if there should be a way of doing this in tidyverse without having to unite the variables. This is something that SAS handles very easily using an ARRAY statement and a DO loop, and I'm hoping R has a good way of handling this.



The real dataframe has many additional variables besides from the "c" fields to search, so a solution that involves searching every column would require subsetting the dataframe to first only contain the variables I want to search, and then joining the data back with the other variables.







r dplyr tidyverse mutate






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 11 hours ago







patward5656

















asked 11 hours ago









patward5656patward5656

425




425













  • You said you don't want to use unite, but it's worth noting that passing the argument remove = FALSE has unite create a column of the united variables leaving the others intact. Might be convenient in this case.

    – camille
    11 hours ago











  • Yes, it is convenient. And it does work. I just feel like there may be a simpler approach I'm missing that doesn't need to create a united variable.

    – patward5656
    11 hours ago



















  • You said you don't want to use unite, but it's worth noting that passing the argument remove = FALSE has unite create a column of the united variables leaving the others intact. Might be convenient in this case.

    – camille
    11 hours ago











  • Yes, it is convenient. And it does work. I just feel like there may be a simpler approach I'm missing that doesn't need to create a united variable.

    – patward5656
    11 hours ago

















You said you don't want to use unite, but it's worth noting that passing the argument remove = FALSE has unite create a column of the united variables leaving the others intact. Might be convenient in this case.

– camille
11 hours ago





You said you don't want to use unite, but it's worth noting that passing the argument remove = FALSE has unite create a column of the united variables leaving the others intact. Might be convenient in this case.

– camille
11 hours ago













Yes, it is convenient. And it does work. I just feel like there may be a simpler approach I'm missing that doesn't need to create a united variable.

– patward5656
11 hours ago





Yes, it is convenient. And it does work. I just feel like there may be a simpler approach I'm missing that doesn't need to create a united variable.

– patward5656
11 hours ago












3 Answers
3






active

oldest

votes


















3














We can use tidyverse



library(tidyverse)
df %>%
mutate_all(str_detect, pattern = code_regex) %>%
reduce(`+`) %>%
mutate(df, indicator = .)
# c1 c2 c3 indicator
#1 T1 R4 C5 1
#2 X1 C6 C2 0
#3 T6 C7 X4 0
#4 R5 X3 T2 1




Or using base R



Reduce(`+`, lapply(df, grepl, pattern = code_regex))
#[1] 1 0 0 1





share|improve this answer
























  • This tidyverse solution seems to only work in the scenario where all of the columns are being searched. I have other variables in my real dataset, and when using it for that the output is all NA. Does this have something to do with the reduce function?

    – patward5656
    10 hours ago











  • @patward5656 That is an easy fix. df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce("+") %>% mutate(df, indicator = .)

    – akrun
    10 hours ago













  • c1<-c("T1", "X1", "T6", "R5") c2<-c("R4", "C6", "C7", "X3") c3<-c("C5", "C2", "X4", "T2") z1<-c("C5", "C2", "X4", "T2") df<-data.frame(c1, c2, c3, z1) df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+) %>% mutate(df, indicator = .) c1 c2 c3 z1 indicator 1 T1 R4 C5 C5 NA 2 X1 C6 C2 C2 NA 3 T6 C7 X4 X4 NA 4 R5 X3 T2 T2 NA Warning message: In Ops.factor(.x, .y) : ‘+’ not meaningful for factors This produced NAs, it seems.

    – patward5656
    10 hours ago








  • 1





    @patward5656 I would use transmute_at instead of mutate_at df %>% transmute_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+)

    – akrun
    10 hours ago








  • 1





    Thanks. I believe transmute_at() solves it perfectly.

    – patward5656
    10 hours ago





















6














Using base R, we can use sapply and use grepl to find pattern in every column and assign 1 to rows where there is more than 0 matches.



df$indicator <- as.integer(rowSums(sapply(df, grepl, pattern = code_regex)) > 0)

df
# c1 c2 c3 indicator
#1 T1 R4 C5 1
#2 X1 C6 C2 0
#3 T6 C7 X4 0
#4 R5 X3 T2 1


If there are few other columns and we are interested to apply it only for columns which start with "c" we can use grep to filter them.



cols <- grep("^c", names(df))
as.integer(rowSums(sapply(df[cols], grepl, pattern = code_regex)) > 0)




Using dplyr we can do



library(dplyr)

df$indicator <- as.integer(df %>%
mutate_at(vars(c1:c3), ~grepl(code_regex, .)) %>%
rowSums() > 0)





share|improve this answer


























  • This is a good solution, but in the real data there are additional variables that I do not want to pattern search, so this would require me to index the dataframe to include only the columns I want to search first. Will edit my original post to include this information.

    – patward5656
    11 hours ago











  • The purr solution looks like what I was looking for--one line of code that doesn't involve uniting the variables.

    – patward5656
    11 hours ago











  • @patward5656 I think the purrr solution would not give you the expected output. I changed it to use mutate_at which should work on range of columns. Moreover, you can use column numbers directly in cols for sapply ., say columns 3:5 or 1:3 to find pattern in those column.

    – Ronak Shah
    11 hours ago





















1














Base R with apply



apply(df[cols], 1, function(x) sum(grepl(code_regex, x)))
# [1] 1 0 0 1





share|improve this answer
























    Your Answer






    StackExchange.ifUsing("editor", function () {
    StackExchange.using("externalEditor", function () {
    StackExchange.using("snippets", function () {
    StackExchange.snippets.init();
    });
    });
    }, "code-snippets");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "1"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55795925%2fcreating-one-variable-from-a-list-of-variables-in-r%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3














    We can use tidyverse



    library(tidyverse)
    df %>%
    mutate_all(str_detect, pattern = code_regex) %>%
    reduce(`+`) %>%
    mutate(df, indicator = .)
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1




    Or using base R



    Reduce(`+`, lapply(df, grepl, pattern = code_regex))
    #[1] 1 0 0 1





    share|improve this answer
























    • This tidyverse solution seems to only work in the scenario where all of the columns are being searched. I have other variables in my real dataset, and when using it for that the output is all NA. Does this have something to do with the reduce function?

      – patward5656
      10 hours ago











    • @patward5656 That is an easy fix. df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce("+") %>% mutate(df, indicator = .)

      – akrun
      10 hours ago













    • c1<-c("T1", "X1", "T6", "R5") c2<-c("R4", "C6", "C7", "X3") c3<-c("C5", "C2", "X4", "T2") z1<-c("C5", "C2", "X4", "T2") df<-data.frame(c1, c2, c3, z1) df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+) %>% mutate(df, indicator = .) c1 c2 c3 z1 indicator 1 T1 R4 C5 C5 NA 2 X1 C6 C2 C2 NA 3 T6 C7 X4 X4 NA 4 R5 X3 T2 T2 NA Warning message: In Ops.factor(.x, .y) : ‘+’ not meaningful for factors This produced NAs, it seems.

      – patward5656
      10 hours ago








    • 1





      @patward5656 I would use transmute_at instead of mutate_at df %>% transmute_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+)

      – akrun
      10 hours ago








    • 1





      Thanks. I believe transmute_at() solves it perfectly.

      – patward5656
      10 hours ago


















    3














    We can use tidyverse



    library(tidyverse)
    df %>%
    mutate_all(str_detect, pattern = code_regex) %>%
    reduce(`+`) %>%
    mutate(df, indicator = .)
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1




    Or using base R



    Reduce(`+`, lapply(df, grepl, pattern = code_regex))
    #[1] 1 0 0 1





    share|improve this answer
























    • This tidyverse solution seems to only work in the scenario where all of the columns are being searched. I have other variables in my real dataset, and when using it for that the output is all NA. Does this have something to do with the reduce function?

      – patward5656
      10 hours ago











    • @patward5656 That is an easy fix. df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce("+") %>% mutate(df, indicator = .)

      – akrun
      10 hours ago













    • c1<-c("T1", "X1", "T6", "R5") c2<-c("R4", "C6", "C7", "X3") c3<-c("C5", "C2", "X4", "T2") z1<-c("C5", "C2", "X4", "T2") df<-data.frame(c1, c2, c3, z1) df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+) %>% mutate(df, indicator = .) c1 c2 c3 z1 indicator 1 T1 R4 C5 C5 NA 2 X1 C6 C2 C2 NA 3 T6 C7 X4 X4 NA 4 R5 X3 T2 T2 NA Warning message: In Ops.factor(.x, .y) : ‘+’ not meaningful for factors This produced NAs, it seems.

      – patward5656
      10 hours ago








    • 1





      @patward5656 I would use transmute_at instead of mutate_at df %>% transmute_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+)

      – akrun
      10 hours ago








    • 1





      Thanks. I believe transmute_at() solves it perfectly.

      – patward5656
      10 hours ago
















    3












    3








    3







    We can use tidyverse



    library(tidyverse)
    df %>%
    mutate_all(str_detect, pattern = code_regex) %>%
    reduce(`+`) %>%
    mutate(df, indicator = .)
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1




    Or using base R



    Reduce(`+`, lapply(df, grepl, pattern = code_regex))
    #[1] 1 0 0 1





    share|improve this answer













    We can use tidyverse



    library(tidyverse)
    df %>%
    mutate_all(str_detect, pattern = code_regex) %>%
    reduce(`+`) %>%
    mutate(df, indicator = .)
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1




    Or using base R



    Reduce(`+`, lapply(df, grepl, pattern = code_regex))
    #[1] 1 0 0 1






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered 11 hours ago









    akrunakrun

    424k13209287




    424k13209287













    • This tidyverse solution seems to only work in the scenario where all of the columns are being searched. I have other variables in my real dataset, and when using it for that the output is all NA. Does this have something to do with the reduce function?

      – patward5656
      10 hours ago











    • @patward5656 That is an easy fix. df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce("+") %>% mutate(df, indicator = .)

      – akrun
      10 hours ago













    • c1<-c("T1", "X1", "T6", "R5") c2<-c("R4", "C6", "C7", "X3") c3<-c("C5", "C2", "X4", "T2") z1<-c("C5", "C2", "X4", "T2") df<-data.frame(c1, c2, c3, z1) df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+) %>% mutate(df, indicator = .) c1 c2 c3 z1 indicator 1 T1 R4 C5 C5 NA 2 X1 C6 C2 C2 NA 3 T6 C7 X4 X4 NA 4 R5 X3 T2 T2 NA Warning message: In Ops.factor(.x, .y) : ‘+’ not meaningful for factors This produced NAs, it seems.

      – patward5656
      10 hours ago








    • 1





      @patward5656 I would use transmute_at instead of mutate_at df %>% transmute_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+)

      – akrun
      10 hours ago








    • 1





      Thanks. I believe transmute_at() solves it perfectly.

      – patward5656
      10 hours ago





















    • This tidyverse solution seems to only work in the scenario where all of the columns are being searched. I have other variables in my real dataset, and when using it for that the output is all NA. Does this have something to do with the reduce function?

      – patward5656
      10 hours ago











    • @patward5656 That is an easy fix. df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce("+") %>% mutate(df, indicator = .)

      – akrun
      10 hours ago













    • c1<-c("T1", "X1", "T6", "R5") c2<-c("R4", "C6", "C7", "X3") c3<-c("C5", "C2", "X4", "T2") z1<-c("C5", "C2", "X4", "T2") df<-data.frame(c1, c2, c3, z1) df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+) %>% mutate(df, indicator = .) c1 c2 c3 z1 indicator 1 T1 R4 C5 C5 NA 2 X1 C6 C2 C2 NA 3 T6 C7 X4 X4 NA 4 R5 X3 T2 T2 NA Warning message: In Ops.factor(.x, .y) : ‘+’ not meaningful for factors This produced NAs, it seems.

      – patward5656
      10 hours ago








    • 1





      @patward5656 I would use transmute_at instead of mutate_at df %>% transmute_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+)

      – akrun
      10 hours ago








    • 1





      Thanks. I believe transmute_at() solves it perfectly.

      – patward5656
      10 hours ago



















    This tidyverse solution seems to only work in the scenario where all of the columns are being searched. I have other variables in my real dataset, and when using it for that the output is all NA. Does this have something to do with the reduce function?

    – patward5656
    10 hours ago





    This tidyverse solution seems to only work in the scenario where all of the columns are being searched. I have other variables in my real dataset, and when using it for that the output is all NA. Does this have something to do with the reduce function?

    – patward5656
    10 hours ago













    @patward5656 That is an easy fix. df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce("+") %>% mutate(df, indicator = .)

    – akrun
    10 hours ago







    @patward5656 That is an easy fix. df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce("+") %>% mutate(df, indicator = .)

    – akrun
    10 hours ago















    c1<-c("T1", "X1", "T6", "R5") c2<-c("R4", "C6", "C7", "X3") c3<-c("C5", "C2", "X4", "T2") z1<-c("C5", "C2", "X4", "T2") df<-data.frame(c1, c2, c3, z1) df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+) %>% mutate(df, indicator = .) c1 c2 c3 z1 indicator 1 T1 R4 C5 C5 NA 2 X1 C6 C2 C2 NA 3 T6 C7 X4 X4 NA 4 R5 X3 T2 T2 NA Warning message: In Ops.factor(.x, .y) : ‘+’ not meaningful for factors This produced NAs, it seems.

    – patward5656
    10 hours ago







    c1<-c("T1", "X1", "T6", "R5") c2<-c("R4", "C6", "C7", "X3") c3<-c("C5", "C2", "X4", "T2") z1<-c("C5", "C2", "X4", "T2") df<-data.frame(c1, c2, c3, z1) df %>% mutate_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+) %>% mutate(df, indicator = .) c1 c2 c3 z1 indicator 1 T1 R4 C5 C5 NA 2 X1 C6 C2 C2 NA 3 T6 C7 X4 X4 NA 4 R5 X3 T2 T2 NA Warning message: In Ops.factor(.x, .y) : ‘+’ not meaningful for factors This produced NAs, it seems.

    – patward5656
    10 hours ago






    1




    1





    @patward5656 I would use transmute_at instead of mutate_at df %>% transmute_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+)

    – akrun
    10 hours ago







    @patward5656 I would use transmute_at instead of mutate_at df %>% transmute_at(vars(starts_with("c")), str_detect, pattern = code_regex) %>% reduce(+)

    – akrun
    10 hours ago






    1




    1





    Thanks. I believe transmute_at() solves it perfectly.

    – patward5656
    10 hours ago







    Thanks. I believe transmute_at() solves it perfectly.

    – patward5656
    10 hours ago















    6














    Using base R, we can use sapply and use grepl to find pattern in every column and assign 1 to rows where there is more than 0 matches.



    df$indicator <- as.integer(rowSums(sapply(df, grepl, pattern = code_regex)) > 0)

    df
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1


    If there are few other columns and we are interested to apply it only for columns which start with "c" we can use grep to filter them.



    cols <- grep("^c", names(df))
    as.integer(rowSums(sapply(df[cols], grepl, pattern = code_regex)) > 0)




    Using dplyr we can do



    library(dplyr)

    df$indicator <- as.integer(df %>%
    mutate_at(vars(c1:c3), ~grepl(code_regex, .)) %>%
    rowSums() > 0)





    share|improve this answer


























    • This is a good solution, but in the real data there are additional variables that I do not want to pattern search, so this would require me to index the dataframe to include only the columns I want to search first. Will edit my original post to include this information.

      – patward5656
      11 hours ago











    • The purr solution looks like what I was looking for--one line of code that doesn't involve uniting the variables.

      – patward5656
      11 hours ago











    • @patward5656 I think the purrr solution would not give you the expected output. I changed it to use mutate_at which should work on range of columns. Moreover, you can use column numbers directly in cols for sapply ., say columns 3:5 or 1:3 to find pattern in those column.

      – Ronak Shah
      11 hours ago


















    6














    Using base R, we can use sapply and use grepl to find pattern in every column and assign 1 to rows where there is more than 0 matches.



    df$indicator <- as.integer(rowSums(sapply(df, grepl, pattern = code_regex)) > 0)

    df
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1


    If there are few other columns and we are interested to apply it only for columns which start with "c" we can use grep to filter them.



    cols <- grep("^c", names(df))
    as.integer(rowSums(sapply(df[cols], grepl, pattern = code_regex)) > 0)




    Using dplyr we can do



    library(dplyr)

    df$indicator <- as.integer(df %>%
    mutate_at(vars(c1:c3), ~grepl(code_regex, .)) %>%
    rowSums() > 0)





    share|improve this answer


























    • This is a good solution, but in the real data there are additional variables that I do not want to pattern search, so this would require me to index the dataframe to include only the columns I want to search first. Will edit my original post to include this information.

      – patward5656
      11 hours ago











    • The purr solution looks like what I was looking for--one line of code that doesn't involve uniting the variables.

      – patward5656
      11 hours ago











    • @patward5656 I think the purrr solution would not give you the expected output. I changed it to use mutate_at which should work on range of columns. Moreover, you can use column numbers directly in cols for sapply ., say columns 3:5 or 1:3 to find pattern in those column.

      – Ronak Shah
      11 hours ago
















    6












    6








    6







    Using base R, we can use sapply and use grepl to find pattern in every column and assign 1 to rows where there is more than 0 matches.



    df$indicator <- as.integer(rowSums(sapply(df, grepl, pattern = code_regex)) > 0)

    df
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1


    If there are few other columns and we are interested to apply it only for columns which start with "c" we can use grep to filter them.



    cols <- grep("^c", names(df))
    as.integer(rowSums(sapply(df[cols], grepl, pattern = code_regex)) > 0)




    Using dplyr we can do



    library(dplyr)

    df$indicator <- as.integer(df %>%
    mutate_at(vars(c1:c3), ~grepl(code_regex, .)) %>%
    rowSums() > 0)





    share|improve this answer















    Using base R, we can use sapply and use grepl to find pattern in every column and assign 1 to rows where there is more than 0 matches.



    df$indicator <- as.integer(rowSums(sapply(df, grepl, pattern = code_regex)) > 0)

    df
    # c1 c2 c3 indicator
    #1 T1 R4 C5 1
    #2 X1 C6 C2 0
    #3 T6 C7 X4 0
    #4 R5 X3 T2 1


    If there are few other columns and we are interested to apply it only for columns which start with "c" we can use grep to filter them.



    cols <- grep("^c", names(df))
    as.integer(rowSums(sapply(df[cols], grepl, pattern = code_regex)) > 0)




    Using dplyr we can do



    library(dplyr)

    df$indicator <- as.integer(df %>%
    mutate_at(vars(c1:c3), ~grepl(code_regex, .)) %>%
    rowSums() > 0)






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited 11 hours ago

























    answered 11 hours ago









    Ronak ShahRonak Shah

    49k104370




    49k104370













    • This is a good solution, but in the real data there are additional variables that I do not want to pattern search, so this would require me to index the dataframe to include only the columns I want to search first. Will edit my original post to include this information.

      – patward5656
      11 hours ago











    • The purr solution looks like what I was looking for--one line of code that doesn't involve uniting the variables.

      – patward5656
      11 hours ago











    • @patward5656 I think the purrr solution would not give you the expected output. I changed it to use mutate_at which should work on range of columns. Moreover, you can use column numbers directly in cols for sapply ., say columns 3:5 or 1:3 to find pattern in those column.

      – Ronak Shah
      11 hours ago





















    • This is a good solution, but in the real data there are additional variables that I do not want to pattern search, so this would require me to index the dataframe to include only the columns I want to search first. Will edit my original post to include this information.

      – patward5656
      11 hours ago











    • The purr solution looks like what I was looking for--one line of code that doesn't involve uniting the variables.

      – patward5656
      11 hours ago











    • @patward5656 I think the purrr solution would not give you the expected output. I changed it to use mutate_at which should work on range of columns. Moreover, you can use column numbers directly in cols for sapply ., say columns 3:5 or 1:3 to find pattern in those column.

      – Ronak Shah
      11 hours ago



















    This is a good solution, but in the real data there are additional variables that I do not want to pattern search, so this would require me to index the dataframe to include only the columns I want to search first. Will edit my original post to include this information.

    – patward5656
    11 hours ago





    This is a good solution, but in the real data there are additional variables that I do not want to pattern search, so this would require me to index the dataframe to include only the columns I want to search first. Will edit my original post to include this information.

    – patward5656
    11 hours ago













    The purr solution looks like what I was looking for--one line of code that doesn't involve uniting the variables.

    – patward5656
    11 hours ago





    The purr solution looks like what I was looking for--one line of code that doesn't involve uniting the variables.

    – patward5656
    11 hours ago













    @patward5656 I think the purrr solution would not give you the expected output. I changed it to use mutate_at which should work on range of columns. Moreover, you can use column numbers directly in cols for sapply ., say columns 3:5 or 1:3 to find pattern in those column.

    – Ronak Shah
    11 hours ago







    @patward5656 I think the purrr solution would not give you the expected output. I changed it to use mutate_at which should work on range of columns. Moreover, you can use column numbers directly in cols for sapply ., say columns 3:5 or 1:3 to find pattern in those column.

    – Ronak Shah
    11 hours ago













    1














    Base R with apply



    apply(df[cols], 1, function(x) sum(grepl(code_regex, x)))
    # [1] 1 0 0 1





    share|improve this answer




























      1














      Base R with apply



      apply(df[cols], 1, function(x) sum(grepl(code_regex, x)))
      # [1] 1 0 0 1





      share|improve this answer


























        1












        1








        1







        Base R with apply



        apply(df[cols], 1, function(x) sum(grepl(code_regex, x)))
        # [1] 1 0 0 1





        share|improve this answer













        Base R with apply



        apply(df[cols], 1, function(x) sum(grepl(code_regex, x)))
        # [1] 1 0 0 1






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 10 hours ago









        nsinghsnsinghs

        1,262621




        1,262621






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55795925%2fcreating-one-variable-from-a-list-of-variables-in-r%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            Popular posts from this blog

            Couldn't open a raw socket. Error: Permission denied (13) (nmap)Is it possible to run networking commands...

            VNC viewer RFB protocol error: bad desktop size 0x0I Cannot Type the Key 'd' (lowercase) in VNC Viewer...

            Why not use the yoke to control yaw, as well as pitch and roll? Announcing the arrival of...