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Supply current of negative rail
The 2019 Stack Overflow Developer Survey Results Are InOpAmps - Single Supply or Dual?Tripping Power supply but no short circuitHow to Mount Power Supply to PCBDesign for a balanced (positive and negative) HV DC regulatorOp Amp Power Supply ConsiderationDesigning a linear regulated dual-rail power supplyHow to create a negative voltage supply?What is the most painless way to get a high current negative voltage power supply from a positive?Are there any single supply OP amps with negative supply voltage?Supply current for dual supply
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$begingroup$
I'm using an LTC1983ES6-5 to provide a negative rail for both a MAX4311 and a MAX4395. LTC1983 provides up to 100 mA, but I cannot find in the other datasheets how much current is required for the negative supply rail of the components.
What parameter(s) I should look to?
power-supply datasheet dual negative-voltage
asked yesterday
MarkMark
24419
$endgroup$
add a comment |
$begingroup$
I'm using an LTC1983ES6-5 to provide a negative rail for both a MAX4311 and a MAX4395. LTC1983 provides up to 100 mA, but I cannot find in the other datasheets how much current is required for the negative supply rail of the components.
What parameter(s) I should look to?
power-supply datasheet dual negative-voltage
asked yesterday
MarkMark
24419
$endgroup$
add a comment |
$begingroup$
I'm using an LTC1983ES6-5 to provide a negative rail for both a MAX4311 and a MAX4395. LTC1983 provides up to 100 mA, but I cannot find in the other datasheets how much current is required for the negative supply rail of the components.
What parameter(s) I should look to?
power-supply datasheet dual negative-voltage
asked yesterday
MarkMark
24419
$endgroup$
I'm using an LTC1983ES6-5 to provide a negative rail for both a MAX4311 and a MAX4395. LTC1983 provides up to 100 mA, but I cannot find in the other datasheets how much current is required for the negative supply rail of the components.
What parameter(s) I should look to?
power-supply datasheet dual negative-voltage
power-supply datasheet dual negative-voltage
asked yesterday
MarkMark
24419
asked yesterday
MarkMark
24419
asked yesterday
MarkMark
24419
asked yesterday
MarkMark
24419
asked yesterday
MarkMark
24419
24419
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
The datasheets for both ICs have a section called "output current." Both datasheets give the conditions for that output current:
MAX4311:
That's 95mA into a 30ohm load when operated at 5V, with 2.5 V output.
MAX4395:
Again, 95mA. But, into a 75ohm load operated on +- 5V.
You have to add in the quiescent current, of course. Also given in the datasheets.
It looks to me like your LTC1983 is a little on the weak side (100mA opposed to the 200mA both amps can draw,) at least if you are driving anywhere near the rated loads - and I expect you are, since both ICs are intended to drive video signals into typical video cable impedances.
You know your circuit better than we do. If you are driving lower loads, you might get away with just one LTC1983. If you are driving typical video signals, you'd do better with two LTC1983 (or a single converter that can supply more current.)
answered yesterday
JREJRE
23.4k54178
$endgroup$
$begingroup$
Yes, I'm driving standard 75-ohm video signals. About MAX4311 because there's no indication about dual-supply, am I wrong to assume (just as rule-of-thumb) a negative current slightly less than the half of the total (95 mA) ?
$endgroup$
– Mark
yesterday
1
$begingroup$
That assumption is incorrect. It will draw that current from both supplies.
$endgroup$
– JRE
yesterday
add a comment |
$begingroup$
The datasheet does tell how much the chips itself use. It's the quiescent current section. But what answer you really want depends on how much current is used by the loads connected to these chips. Only you can answer this.
answered yesterday
JustmeJustme
2,2031413
$endgroup$
add a comment |
$begingroup$
You can start by assuming the supply current for these ICs flows from the positive to the negative supply. Thus all positive supply current must be sunk by the negative supply.
This assumption is not correct if the ICs a sinking or sourcing current on other pins. Current from other pins is generally directed to either the positive or negative supply. Sometimes current is directed from one pin to another (non-supply) pin.
I haven't looked at the data sheets but you should be able to find the supply currents in there.
answered yesterday
jherboldjherbold
33815
$endgroup$
$begingroup$
This assumption is not correct if the ICs a sinking or sourcing current on other pins and I haven't looked at the data sheets don't make this answer helpful I think.
$endgroup$
– Huisman
yesterday
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The datasheets for both ICs have a section called "output current." Both datasheets give the conditions for that output current:
MAX4311:
That's 95mA into a 30ohm load when operated at 5V, with 2.5 V output.
MAX4395:
Again, 95mA. But, into a 75ohm load operated on +- 5V.
You have to add in the quiescent current, of course. Also given in the datasheets.
It looks to me like your LTC1983 is a little on the weak side (100mA opposed to the 200mA both amps can draw,) at least if you are driving anywhere near the rated loads - and I expect you are, since both ICs are intended to drive video signals into typical video cable impedances.
You know your circuit better than we do. If you are driving lower loads, you might get away with just one LTC1983. If you are driving typical video signals, you'd do better with two LTC1983 (or a single converter that can supply more current.)
answered yesterday
JREJRE
23.4k54178
$endgroup$
$begingroup$
Yes, I'm driving standard 75-ohm video signals. About MAX4311 because there's no indication about dual-supply, am I wrong to assume (just as rule-of-thumb) a negative current slightly less than the half of the total (95 mA) ?
$endgroup$
– Mark
yesterday
1
$begingroup$
That assumption is incorrect. It will draw that current from both supplies.
$endgroup$
– JRE
yesterday
add a comment |
$begingroup$
The datasheets for both ICs have a section called "output current." Both datasheets give the conditions for that output current:
MAX4311:
That's 95mA into a 30ohm load when operated at 5V, with 2.5 V output.
MAX4395:
Again, 95mA. But, into a 75ohm load operated on +- 5V.
You have to add in the quiescent current, of course. Also given in the datasheets.
It looks to me like your LTC1983 is a little on the weak side (100mA opposed to the 200mA both amps can draw,) at least if you are driving anywhere near the rated loads - and I expect you are, since both ICs are intended to drive video signals into typical video cable impedances.
You know your circuit better than we do. If you are driving lower loads, you might get away with just one LTC1983. If you are driving typical video signals, you'd do better with two LTC1983 (or a single converter that can supply more current.)
answered yesterday
JREJRE
23.4k54178
$endgroup$
$begingroup$
Yes, I'm driving standard 75-ohm video signals. About MAX4311 because there's no indication about dual-supply, am I wrong to assume (just as rule-of-thumb) a negative current slightly less than the half of the total (95 mA) ?
$endgroup$
– Mark
yesterday
1
$begingroup$
That assumption is incorrect. It will draw that current from both supplies.
$endgroup$
– JRE
yesterday
add a comment |
$begingroup$
The datasheets for both ICs have a section called "output current." Both datasheets give the conditions for that output current:
MAX4311:
That's 95mA into a 30ohm load when operated at 5V, with 2.5 V output.
MAX4395:
Again, 95mA. But, into a 75ohm load operated on +- 5V.
You have to add in the quiescent current, of course. Also given in the datasheets.
It looks to me like your LTC1983 is a little on the weak side (100mA opposed to the 200mA both amps can draw,) at least if you are driving anywhere near the rated loads - and I expect you are, since both ICs are intended to drive video signals into typical video cable impedances.
You know your circuit better than we do. If you are driving lower loads, you might get away with just one LTC1983. If you are driving typical video signals, you'd do better with two LTC1983 (or a single converter that can supply more current.)
answered yesterday
JREJRE
23.4k54178
$endgroup$
The datasheets for both ICs have a section called "output current." Both datasheets give the conditions for that output current:
MAX4311:
That's 95mA into a 30ohm load when operated at 5V, with 2.5 V output.
MAX4395:
Again, 95mA. But, into a 75ohm load operated on +- 5V.
You have to add in the quiescent current, of course. Also given in the datasheets.
It looks to me like your LTC1983 is a little on the weak side (100mA opposed to the 200mA both amps can draw,) at least if you are driving anywhere near the rated loads - and I expect you are, since both ICs are intended to drive video signals into typical video cable impedances.
You know your circuit better than we do. If you are driving lower loads, you might get away with just one LTC1983. If you are driving typical video signals, you'd do better with two LTC1983 (or a single converter that can supply more current.)
answered yesterday
JREJRE
23.4k54178
edited yesterday
answered yesterday
JREJRE
23.4k54178
answered yesterday
JREJRE
23.4k54178
answered yesterday
JREJRE
23.4k54178
23.4k54178
$begingroup$
Yes, I'm driving standard 75-ohm video signals. About MAX4311 because there's no indication about dual-supply, am I wrong to assume (just as rule-of-thumb) a negative current slightly less than the half of the total (95 mA) ?
$endgroup$
– Mark
yesterday
1
$begingroup$
That assumption is incorrect. It will draw that current from both supplies.
$endgroup$
– JRE
yesterday
add a comment |
$begingroup$
Yes, I'm driving standard 75-ohm video signals. About MAX4311 because there's no indication about dual-supply, am I wrong to assume (just as rule-of-thumb) a negative current slightly less than the half of the total (95 mA) ?
$endgroup$
– Mark
yesterday
1
$begingroup$
That assumption is incorrect. It will draw that current from both supplies.
$endgroup$
– JRE
yesterday
$begingroup$
Yes, I'm driving standard 75-ohm video signals. About MAX4311 because there's no indication about dual-supply, am I wrong to assume (just as rule-of-thumb) a negative current slightly less than the half of the total (95 mA) ?
$endgroup$
– Mark
yesterday
$begingroup$
Yes, I'm driving standard 75-ohm video signals. About MAX4311 because there's no indication about dual-supply, am I wrong to assume (just as rule-of-thumb) a negative current slightly less than the half of the total (95 mA) ?
$endgroup$
– Mark
yesterday
1
1
$begingroup$
That assumption is incorrect. It will draw that current from both supplies.
$endgroup$
– JRE
yesterday
$begingroup$
That assumption is incorrect. It will draw that current from both supplies.
$endgroup$
– JRE
yesterday
add a comment |
$begingroup$
The datasheet does tell how much the chips itself use. It's the quiescent current section. But what answer you really want depends on how much current is used by the loads connected to these chips. Only you can answer this.
answered yesterday
JustmeJustme
2,2031413
$endgroup$
add a comment |
$begingroup$
The datasheet does tell how much the chips itself use. It's the quiescent current section. But what answer you really want depends on how much current is used by the loads connected to these chips. Only you can answer this.
answered yesterday
JustmeJustme
2,2031413
$endgroup$
add a comment |
$begingroup$
The datasheet does tell how much the chips itself use. It's the quiescent current section. But what answer you really want depends on how much current is used by the loads connected to these chips. Only you can answer this.
answered yesterday
JustmeJustme
2,2031413
$endgroup$
The datasheet does tell how much the chips itself use. It's the quiescent current section. But what answer you really want depends on how much current is used by the loads connected to these chips. Only you can answer this.
answered yesterday
JustmeJustme
2,2031413
answered yesterday
JustmeJustme
2,2031413
answered yesterday
JustmeJustme
2,2031413
answered yesterday
JustmeJustme
2,2031413
2,2031413
add a comment |
add a comment |
$begingroup$
You can start by assuming the supply current for these ICs flows from the positive to the negative supply. Thus all positive supply current must be sunk by the negative supply.
This assumption is not correct if the ICs a sinking or sourcing current on other pins. Current from other pins is generally directed to either the positive or negative supply. Sometimes current is directed from one pin to another (non-supply) pin.
I haven't looked at the data sheets but you should be able to find the supply currents in there.
answered yesterday
jherboldjherbold
33815
$endgroup$
$begingroup$
This assumption is not correct if the ICs a sinking or sourcing current on other pins and I haven't looked at the data sheets don't make this answer helpful I think.
$endgroup$
– Huisman
yesterday
add a comment |
$begingroup$
You can start by assuming the supply current for these ICs flows from the positive to the negative supply. Thus all positive supply current must be sunk by the negative supply.
This assumption is not correct if the ICs a sinking or sourcing current on other pins. Current from other pins is generally directed to either the positive or negative supply. Sometimes current is directed from one pin to another (non-supply) pin.
I haven't looked at the data sheets but you should be able to find the supply currents in there.
answered yesterday
jherboldjherbold
33815
$endgroup$
$begingroup$
This assumption is not correct if the ICs a sinking or sourcing current on other pins and I haven't looked at the data sheets don't make this answer helpful I think.
$endgroup$
– Huisman
yesterday
add a comment |
$begingroup$
You can start by assuming the supply current for these ICs flows from the positive to the negative supply. Thus all positive supply current must be sunk by the negative supply.
This assumption is not correct if the ICs a sinking or sourcing current on other pins. Current from other pins is generally directed to either the positive or negative supply. Sometimes current is directed from one pin to another (non-supply) pin.
I haven't looked at the data sheets but you should be able to find the supply currents in there.
answered yesterday
jherboldjherbold
33815
$endgroup$
You can start by assuming the supply current for these ICs flows from the positive to the negative supply. Thus all positive supply current must be sunk by the negative supply.
This assumption is not correct if the ICs a sinking or sourcing current on other pins. Current from other pins is generally directed to either the positive or negative supply. Sometimes current is directed from one pin to another (non-supply) pin.
I haven't looked at the data sheets but you should be able to find the supply currents in there.
answered yesterday
jherboldjherbold
33815
answered yesterday
jherboldjherbold
33815
answered yesterday
jherboldjherbold
33815
answered yesterday
jherboldjherbold
33815
33815
$begingroup$
This assumption is not correct if the ICs a sinking or sourcing current on other pins and I haven't looked at the data sheets don't make this answer helpful I think.
$endgroup$
– Huisman
yesterday
add a comment |
$begingroup$
This assumption is not correct if the ICs a sinking or sourcing current on other pins and I haven't looked at the data sheets don't make this answer helpful I think.
$endgroup$
– Huisman
yesterday
$begingroup$
This assumption is not correct if the ICs a sinking or sourcing current on other pins and I haven't looked at the data sheets don't make this answer helpful I think.
$endgroup$
– Huisman
yesterday
$begingroup$
This assumption is not correct if the ICs a sinking or sourcing current on other pins and I haven't looked at the data sheets don't make this answer helpful I think.
$endgroup$
– Huisman
yesterday
add a comment |
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