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What expression will give age in years in QGIS?



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I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?










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    1















    I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?










    share|improve this question









    New contributor




    TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      1












      1








      1








      I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?










      share|improve this question









      New contributor




      TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?







      qgis-plugins






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      TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this question









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      edited 7 hours ago









      Vince

      14.8k32849




      14.8k32849






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      asked 8 hours ago









      TraineeGISTraineeGIS

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          2 Answers
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          4














          Or use the age function



          year(age(now() ,"yourdatefield"))





          share|improve this answer
























          • Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P

            – Gabriel C.
            7 hours ago



















          2














          From the field calculator, this expression could do the trick:



          year(now()) - year('the laying date')



          Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.






          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4














            Or use the age function



            year(age(now() ,"yourdatefield"))





            share|improve this answer
























            • Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P

              – Gabriel C.
              7 hours ago
















            4














            Or use the age function



            year(age(now() ,"yourdatefield"))





            share|improve this answer
























            • Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P

              – Gabriel C.
              7 hours ago














            4












            4








            4







            Or use the age function



            year(age(now() ,"yourdatefield"))





            share|improve this answer













            Or use the age function



            year(age(now() ,"yourdatefield"))






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 7 hours ago









            cskcsk

            9,4701035




            9,4701035













            • Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P

              – Gabriel C.
              7 hours ago



















            • Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P

              – Gabriel C.
              7 hours ago

















            Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P

            – Gabriel C.
            7 hours ago





            Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P

            – Gabriel C.
            7 hours ago













            2














            From the field calculator, this expression could do the trick:



            year(now()) - year('the laying date')



            Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.






            share|improve this answer




























              2














              From the field calculator, this expression could do the trick:



              year(now()) - year('the laying date')



              Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.






              share|improve this answer


























                2












                2








                2







                From the field calculator, this expression could do the trick:



                year(now()) - year('the laying date')



                Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.






                share|improve this answer













                From the field calculator, this expression could do the trick:



                year(now()) - year('the laying date')



                Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 7 hours ago









                Gabriel C.Gabriel C.

                1,342320




                1,342320






















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