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Using command line to bypass “Missing parentheses in call to 'print'”
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I have a foo.py Python file containing print "bar" code.
When I want to python foo.py my code, here is the error : SyntaxError: Missing parentheses in call to 'print'. Do you know how to avoid this error without adding '(' and ')' to my print function ?
Thanks !
command-line python printing python3
add a comment |
I have a foo.py Python file containing print "bar" code.
When I want to python foo.py my code, here is the error : SyntaxError: Missing parentheses in call to 'print'. Do you know how to avoid this error without adding '(' and ')' to my print function ?
Thanks !
command-line python printing python3
1
For python 3 print is a function and must have ()
– Mark
Jan 25 at 16:37
add a comment |
I have a foo.py Python file containing print "bar" code.
When I want to python foo.py my code, here is the error : SyntaxError: Missing parentheses in call to 'print'. Do you know how to avoid this error without adding '(' and ')' to my print function ?
Thanks !
command-line python printing python3
I have a foo.py Python file containing print "bar" code.
When I want to python foo.py my code, here is the error : SyntaxError: Missing parentheses in call to 'print'. Do you know how to avoid this error without adding '(' and ')' to my print function ?
Thanks !
command-line python printing python3
command-line python printing python3
edited Jan 24 at 16:09
isherwood
514515
514515
asked Jan 24 at 16:08
Kevin VALERIOKevin VALERIO
62
62
1
For python 3 print is a function and must have ()
– Mark
Jan 25 at 16:37
add a comment |
1
For python 3 print is a function and must have ()
– Mark
Jan 25 at 16:37
1
1
For python 3 print is a function and must have ()
– Mark
Jan 25 at 16:37
For python 3 print is a function and must have ()
– Mark
Jan 25 at 16:37
add a comment |
1 Answer
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If your script is compatible then you can force use of Python2 by running it something like
python2 foo.py
or
python2.7 foo.py
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If your script is compatible then you can force use of Python2 by running it something like
python2 foo.py
or
python2.7 foo.py
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
If your script is compatible then you can force use of Python2 by running it something like
python2 foo.py
or
python2.7 foo.py
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
If your script is compatible then you can force use of Python2 by running it something like
python2 foo.py
or
python2.7 foo.py
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
If your script is compatible then you can force use of Python2 by running it something like
python2 foo.py
or
python2.7 foo.py
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 1 hour ago
MarakaiMarakai
1011
1011
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Marakai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
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1
For python 3 print is a function and must have ()
– Mark
Jan 25 at 16:37