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How to format long polynomial?
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I have a long polynomial:
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
$ f(z)=frac{1}{382112640}(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
end{document}
Question. How to format such long polynomial correctly?
math-mode
add a comment |
I have a long polynomial:
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
$ f(z)=frac{1}{382112640}(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
end{document}
Question. How to format such long polynomial correctly?
math-mode
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_{i,j}$ and then adding a table to show the values.
– Mefitico
17 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
17 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
17 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
17 hours ago
add a comment |
I have a long polynomial:
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
$ f(z)=frac{1}{382112640}(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
end{document}
Question. How to format such long polynomial correctly?
math-mode
I have a long polynomial:
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
$ f(z)=frac{1}{382112640}(-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028\
079eta^3+347370177721463765064153eta)/((417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001))$
end{document}
Question. How to format such long polynomial correctly?
math-mode
math-mode
edited 22 hours ago
Bernard
175k777207
175k777207
asked 22 hours ago
NickNick
1915
1915
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_{i,j}$ and then adding a table to show the values.
– Mefitico
17 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
17 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
17 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
17 hours ago
add a comment |
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_{i,j}$ and then adding a table to show the values.
– Mefitico
17 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
17 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
17 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
17 hours ago
3
3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_{i,j}$ and then adding a table to show the values.
– Mefitico
17 hours ago
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_{i,j}$ and then adding a table to show the values.
– Mefitico
17 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
17 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
17 hours ago
1
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
17 hours ago
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
17 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
17 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
17 hours ago
add a comment |
7 Answers
7
active
oldest
votes
I suggest something line the following, so the wide terms are reduced.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
begin{gather*}
begin{align*}
g(eta,z)&=
parbox[t]{0.85displaywidth}{raggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
}
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
end{align*}
\[2ex]
f(z)=frac{1}{382112640}frac{g(eta,z)}{h(z)}
end{gather*}
end{document}
your answer is OK, but some terms are out of pages margins.
– Nick
21 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
21 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
21 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
21 hours ago
add a comment |
I would use something like this
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
begin{align*}
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
end{align*}
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
end{document}
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
14 hours ago
add a comment |
or
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools, nccmath}
begin{document}
begin{multline*}medmath
f(z)=frac{1}{382112640}
frac{left[
begin{multlined}
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
end{multlined}right]}
{(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)}
end{multline*}
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac{1}{382112640} frac{g(eta, z)}{u(z) , v(z) , w(z) } $$
where
$$
begin{array}{ll}
g(eta, z) = begin{bmatrix}
begin{array}{r @{hspace{0em}} l}
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
end{array}
end{bmatrix}^T
begin{bmatrix}
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
end{bmatrix} &
begin{array}{l}
u(z) = left ( begin{bmatrix} 417420 \ -4169121 \ -15571312 end{bmatrix}^T begin{bmatrix} z^2 \ z \ 1 end{bmatrix} right ) \[3em]
v(z) = left ( begin{bmatrix} 1546 \ 3537 end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
w(z) = left ( begin{bmatrix} 3092 \ 17001end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
end{array}
end{array}
$$
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
[
arraycolsep=0.5pt
begin{array}{rrllrll}
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
end{array}
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
end{document}
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{2}
& f(z) && = frac{1}{382112640} times left( vphantom{frac{1}{382112640}} -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantom{frac{1}{382112640}} right) times frac{417420z^2-4169121z-15571312}{(1546z+3537)(3092z+17001)}
end{alignat*}
Do you think this fits the page margin?
– JouleV
20 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
20 hours ago
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begin{dmath*}
f(z)=frac{1}{382112640}times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^{-1}
end{dmath*}
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
add a comment |
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I suggest something line the following, so the wide terms are reduced.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
begin{gather*}
begin{align*}
g(eta,z)&=
parbox[t]{0.85displaywidth}{raggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
}
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
end{align*}
\[2ex]
f(z)=frac{1}{382112640}frac{g(eta,z)}{h(z)}
end{gather*}
end{document}
your answer is OK, but some terms are out of pages margins.
– Nick
21 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
21 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
21 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
21 hours ago
add a comment |
I suggest something line the following, so the wide terms are reduced.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
begin{gather*}
begin{align*}
g(eta,z)&=
parbox[t]{0.85displaywidth}{raggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
}
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
end{align*}
\[2ex]
f(z)=frac{1}{382112640}frac{g(eta,z)}{h(z)}
end{gather*}
end{document}
your answer is OK, but some terms are out of pages margins.
– Nick
21 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
21 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
21 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
21 hours ago
add a comment |
I suggest something line the following, so the wide terms are reduced.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
begin{gather*}
begin{align*}
g(eta,z)&=
parbox[t]{0.85displaywidth}{raggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
}
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
end{align*}
\[2ex]
f(z)=frac{1}{382112640}frac{g(eta,z)}{h(z)}
end{gather*}
end{document}
I suggest something line the following, so the wide terms are reduced.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
begin{gather*}
begin{align*}
g(eta,z)&=
parbox[t]{0.85displaywidth}{raggedright
$-306772802511648469920eta^4z^4+
762453974480763801600eta^5z^4-
1678626210368271790080eta^5z^3-
28510918043555533736160eta^4z^3+
11443138641451067779872eta^3z^3-
52164076923190540413504eta^2z^2-
78145258181161076156160eta^5z^2-
211306163712129371808450eta^4z^2+
228927087397104405937944eta^3z^2+
999881065017543109136462eta^3z-
317254092617698017425280eta^5z-
443761561344388063474665eta^4z+
82327155732241730770824eta z-
514623285385260545505123eta^2z-
1010535343560043404912120eta^2-
357788302700438191196160eta^5-
43808044579418934376632-
214023244873618345872240eta^4+
11818373349781028079eta^3+
347370177721463765064153eta$
}
\[2ex]
h(z)&=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)
end{align*}
\[2ex]
f(z)=frac{1}{382112640}frac{g(eta,z)}{h(z)}
end{gather*}
end{document}
answered 22 hours ago
egregegreg
732k8919303253
732k8919303253
your answer is OK, but some terms are out of pages margins.
– Nick
21 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
21 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
21 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
21 hours ago
add a comment |
your answer is OK, but some terms are out of pages margins.
– Nick
21 hours ago
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
21 hours ago
@Nick egreg's answer uses default margin ofarticle
, which is already really big. But it doesn't fit your margin?
– JouleV
21 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
21 hours ago
your answer is OK, but some terms are out of pages margins.
– Nick
21 hours ago
your answer is OK, but some terms are out of pages margins.
– Nick
21 hours ago
5
5
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
21 hours ago
@Nick Without knowing the line width you're using it's difficult to say more.
– egreg
21 hours ago
@Nick egreg's answer uses default margin of
article
, which is already really big. But it doesn't fit your margin?– JouleV
21 hours ago
@Nick egreg's answer uses default margin of
article
, which is already really big. But it doesn't fit your margin?– JouleV
21 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
21 hours ago
I have moved the signs "-, +" from lines end and put them under sign "=".
– Nick
21 hours ago
add a comment |
I would use something like this
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
begin{align*}
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
end{align*}
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
end{document}
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
14 hours ago
add a comment |
I would use something like this
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
begin{align*}
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
end{align*}
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
end{document}
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
14 hours ago
add a comment |
I would use something like this
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
begin{align*}
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
end{align*}
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
end{document}
I would use something like this
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
begin{align*}
A=&,-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4\
&,-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3\
&,+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2\
&,-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2\
&,+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z\
&,-317254092617698017425280eta^5z-443761561344388063474665eta^4z\
&,+82327155732241730770824eta z-514623285385260545505123eta^2z\
&,-1010535343560043404912120eta^2-357788302700438191196160eta^5\
&,-43808044579418934376632-214023244873618345872240eta^4\
&,+11818373349781028079eta^3+347370177721463765064153eta
end{align*}
and
[B=(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)]
end{document}
answered 22 hours ago
JouleVJouleV
10.9k22560
10.9k22560
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
14 hours ago
add a comment |
you could format this even more compactly by using matrix multiplication to expressA
– Tasos Papastylianou
14 hours ago
you could format this even more compactly by using matrix multiplication to express
A
– Tasos Papastylianou
14 hours ago
you could format this even more compactly by using matrix multiplication to express
A
– Tasos Papastylianou
14 hours ago
add a comment |
or
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools, nccmath}
begin{document}
begin{multline*}medmath
f(z)=frac{1}{382112640}
frac{left[
begin{multlined}
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
end{multlined}right]}
{(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)}
end{multline*}
add a comment |
or
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools, nccmath}
begin{document}
begin{multline*}medmath
f(z)=frac{1}{382112640}
frac{left[
begin{multlined}
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
end{multlined}right]}
{(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)}
end{multline*}
add a comment |
or
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools, nccmath}
begin{document}
begin{multline*}medmath
f(z)=frac{1}{382112640}
frac{left[
begin{multlined}
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
end{multlined}right]}
{(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)}
end{multline*}
or
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools, nccmath}
begin{document}
begin{multline*}medmath
f(z)=frac{1}{382112640}
frac{left[
begin{multlined}
-306772802511648469920eta^4z^4+762453974480763801600eta^5z^4-\
1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+\
11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-\
78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+\
228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-\
317254092617698017425280eta^5z-443761561344388063474665eta^4z+\
82327155732241730770824eta z - 514623285385260545505123eta^2z-\
1010535343560043404912120eta^2-357788302700438191196160eta^5-\
43808044579418934376632-214023244873618345872240eta^4+\
11818373349781028079eta^3+347370177721463765064153eta
end{multlined}right]}
{(417420z^2-4169121z-15571312)(1546z+3537)(3092z+17001)}
end{multline*}
answered 22 hours ago
ZarkoZarko
129k868169
129k868169
add a comment |
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac{1}{382112640} frac{g(eta, z)}{u(z) , v(z) , w(z) } $$
where
$$
begin{array}{ll}
g(eta, z) = begin{bmatrix}
begin{array}{r @{hspace{0em}} l}
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
end{array}
end{bmatrix}^T
begin{bmatrix}
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
end{bmatrix} &
begin{array}{l}
u(z) = left ( begin{bmatrix} 417420 \ -4169121 \ -15571312 end{bmatrix}^T begin{bmatrix} z^2 \ z \ 1 end{bmatrix} right ) \[3em]
v(z) = left ( begin{bmatrix} 1546 \ 3537 end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
w(z) = left ( begin{bmatrix} 3092 \ 17001end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
end{array}
end{array}
$$
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac{1}{382112640} frac{g(eta, z)}{u(z) , v(z) , w(z) } $$
where
$$
begin{array}{ll}
g(eta, z) = begin{bmatrix}
begin{array}{r @{hspace{0em}} l}
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
end{array}
end{bmatrix}^T
begin{bmatrix}
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
end{bmatrix} &
begin{array}{l}
u(z) = left ( begin{bmatrix} 417420 \ -4169121 \ -15571312 end{bmatrix}^T begin{bmatrix} z^2 \ z \ 1 end{bmatrix} right ) \[3em]
v(z) = left ( begin{bmatrix} 1546 \ 3537 end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
w(z) = left ( begin{bmatrix} 3092 \ 17001end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
end{array}
end{array}
$$
add a comment |
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac{1}{382112640} frac{g(eta, z)}{u(z) , v(z) , w(z) } $$
where
$$
begin{array}{ll}
g(eta, z) = begin{bmatrix}
begin{array}{r @{hspace{0em}} l}
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
end{array}
end{bmatrix}^T
begin{bmatrix}
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
end{bmatrix} &
begin{array}{l}
u(z) = left ( begin{bmatrix} 417420 \ -4169121 \ -15571312 end{bmatrix}^T begin{bmatrix} z^2 \ z \ 1 end{bmatrix} right ) \[3em]
v(z) = left ( begin{bmatrix} 1546 \ 3537 end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
w(z) = left ( begin{bmatrix} 3092 \ 17001end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
end{array}
end{array}
$$
Given the nature of the operations, you can probably express this in a tidy manner using matrix multiplication notation, eg:
where:
Code:
$$ f(z)=frac{1}{382112640} frac{g(eta, z)}{u(z) , v(z) , w(z) } $$
where
$$
begin{array}{ll}
g(eta, z) = begin{bmatrix}
begin{array}{r @{hspace{0em}} l}
- & 306772802511648469920 \
& 762453974480763801600 \
- & 1678626210368271790080 \
- & 28510918043555533736160 \
& 11443138641451067779872 \
- & 52164076923190540413504 \
- & 78145258181161076156160 \
- & 211306163712129371808450 \
& 228927087397104405937944 \
& 999881065017543109136462 \
- & 317254092617698017425280 \
- & 443761561344388063474665 \
& 82327155732241730770824 \
- & 514623285385260545505123 \
- & 1010535343560043404912120 \
- & 357788302700438191196160 \
- & 43808044579418934376632 \
- & 214023244873618345872240 \
& 11818373349781028079 \
& 347370177721463765064153
end{array}
end{bmatrix}^T
begin{bmatrix}
eta^4z^4 \
eta^5z^4 \
eta^5z^3 \
eta^4z^3 \
eta^3z^3 \
eta^2z^2 \
eta^5z^2 \
eta^4z^2 \
eta^3z^2 \
eta^3z \
eta^5z \
eta^4z \
eta z \
eta^2z \
eta^2 \
eta^5 \
1 \
eta^4 \
eta^3 \
eta
end{bmatrix} &
begin{array}{l}
u(z) = left ( begin{bmatrix} 417420 \ -4169121 \ -15571312 end{bmatrix}^T begin{bmatrix} z^2 \ z \ 1 end{bmatrix} right ) \[3em]
v(z) = left ( begin{bmatrix} 1546 \ 3537 end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
w(z) = left ( begin{bmatrix} 3092 \ 17001end{bmatrix}^T begin{bmatrix} z \ 1 end{bmatrix} right ) \[3em]
end{array}
end{array}
$$
edited 13 hours ago
answered 13 hours ago
Tasos PapastylianouTasos Papastylianou
297211
297211
add a comment |
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
[
arraycolsep=0.5pt
begin{array}{rrllrll}
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
end{array}
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
end{document}
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
[
arraycolsep=0.5pt
begin{array}{rrllrll}
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
end{array}
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
end{document}
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
add a comment |
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
[
arraycolsep=0.5pt
begin{array}{rrllrll}
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
end{array}
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
end{document}
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
I recommend aligning the variables and adding some form of thousand-separators, both will enhance the readability. What I also recommend (but didn't do here) is sorting by the powers of the first and then the second variable. This is a modification of JuleV's answer.
documentclass{article}
%usepackage{amsmath}% Loaded by mathtools
usepackage{mathtools}
begin{document}
Blah blah
[f(z)=frac{1}{382112640}cdotfrac{A}{B}]
where
[
arraycolsep=0.5pt
begin{array}{rrllrll}
A=&, -306,772,802,511,648,469,920 &eta^4 &z^4 & +762,453,974,480,763,801,600 &eta^5 &z^4\
&, -1,678,626,210,368,271,790,080 &eta^5 &z^3 & -2,8510,918,043,555,533,736,160 &eta^4 &z^3\
&, +11,443,138,641,451,067,779,872 &eta^3 &z^3 & -5,2164,076,923,190,540,413,504 &eta^2 &z^2\
&, -78,145,258,181,161,076,156,160 &eta^5 &z^2 & -21,1306,163,712,129,371,808,450 &eta^4 &z^2\
&, +228,927,087,397,104,405,937,944 &eta^3 &z^2 & +99,9881,065,017,543,109,136,462 &eta^3 &z\
&, -317,254,092,617,698,017,425,280 &eta^5 &z & -44,3761,561,344,388,063,474,665 &eta^4 &z\
&, +82,327,155,732,241,730,770,824 &eta &z & -51,4623,285,385,260,545,505,123 &eta^2 &z\
&,-1,010,535,343,560,043,404,912,120 &eta^2 & & -35,7788,302,700,438,191,196,160 &eta^5 &\
&, -43,808,044,579,418,934,376,632 & & & -21,4023,244,873,618,345,872,240 &eta^4 &\
&, +11,818,373,349,781,028,079 &eta^3 & & +34,7370,177,721,463,765,064,153 &eta &
end{array}
]
and
[B=(417,420z^2-4,169,121z-15,571,312)(1,546z+3,537)(3,092z+17,001)]
end{document}
I'm sure there are also some custom packages that can do this for you but this is just using the packages you provided:
answered 19 hours ago
flawrflawr
517413
517413
add a comment |
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{2}
& f(z) && = frac{1}{382112640} times left( vphantom{frac{1}{382112640}} -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantom{frac{1}{382112640}} right) times frac{417420z^2-4169121z-15571312}{(1546z+3537)(3092z+17001)}
end{alignat*}
Do you think this fits the page margin?
– JouleV
20 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
20 hours ago
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{2}
& f(z) && = frac{1}{382112640} times left( vphantom{frac{1}{382112640}} -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantom{frac{1}{382112640}} right) times frac{417420z^2-4169121z-15571312}{(1546z+3537)(3092z+17001)}
end{alignat*}
Do you think this fits the page margin?
– JouleV
20 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
20 hours ago
add a comment |
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{2}
& f(z) && = frac{1}{382112640} times left( vphantom{frac{1}{382112640}} -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantom{frac{1}{382112640}} right) times frac{417420z^2-4169121z-15571312}{(1546z+3537)(3092z+17001)}
end{alignat*}
With the original disposition of the polynomial, but using alignat
, parenthesis, and fractions to emphasize the different terms of the polynomial.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{alignat*}{2}
& f(z) && = frac{1}{382112640} times left( vphantom{frac{1}{382112640}} -306772802511648469920 eta^4 z^4 + 762453974480763801600 eta^5 z^4 right. \[1.5ex]
& && -1678626210368271790080 eta^5 z^3 - 28510918043555533736160 eta^4 z^3 \[1.5ex]
& && +11443138641451067779872 eta^3 z^3 -52164076923190540413504 eta^2 z^2 \[1.5ex]
& && -78145258181161076156160 eta^5 z^2 -211306163712129371808450 eta^4 z^2 \[1.5ex]
& && +228927087397104405937944 eta^3 z^2 +999881065017543109136462 eta^3 z \[1.5ex]
& && -317254092617698017425280 eta^5 z -443761561344388063474665 eta^4 z \[1.5ex]
& && +82327155732241730770824 eta z -514623285385260545505123 eta^2 z \[1.5ex]
& && -1010535343560043404912120 eta^2 -357788302700438191196160 eta^5 \[1.5ex]
& && -43808044579418934376632 - 214023244873618345872240 eta^4 \[1.5ex]
& && +11818373349781028079 eta^3 +347370177721463765064153eta left. vphantom{frac{1}{382112640}} right) times frac{417420z^2-4169121z-15571312}{(1546z+3537)(3092z+17001)}
end{alignat*}
answered 20 hours ago
AndreAndre
1768
1768
Do you think this fits the page margin?
– JouleV
20 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
20 hours ago
add a comment |
Do you think this fits the page margin?
– JouleV
20 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
20 hours ago
Do you think this fits the page margin?
– JouleV
20 hours ago
Do you think this fits the page margin?
– JouleV
20 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
20 hours ago
It fitted for me. An alternative is to add \ to the last line to bring the last multiplication and fraction to an additional line.
– Andre
20 hours ago
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begin{dmath*}
f(z)=frac{1}{382112640}times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^{-1}
end{dmath*}
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begin{dmath*}
f(z)=frac{1}{382112640}times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^{-1}
end{dmath*}
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
add a comment |
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begin{dmath*}
f(z)=frac{1}{382112640}times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^{-1}
end{dmath*}
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
I would usually use the package breqn
. That automatically line-breaks equations, and has a lot of very nice features, but uses low-level having into the maths primitives, which means it tends to make a mess of other packages what do the same thing (for example, you can't use both breqn
and sansmath
in the same document)
begin{dmath*}
f(z)=frac{1}{382112640}times-306772802511648469920eta^4z^4+left(762453974480763801600eta^5z^4-1678626210368271790080eta^5z^3-28510918043555533736160eta^4z^3+11443138641451067779872eta^3z^3-52164076923190540413504eta^2z^2-78145258181161076156160eta^5z^2-211306163712129371808450eta^4z^2+228927087397104405937944eta^3z^2+999881065017543109136462eta^3z-317254092617698017425280eta^5z-443761561344388063474665eta^4z+82327155732241730770824eta z-514623285385260545505123eta^2z-1010535343560043404912120eta^2-357788302700438191196160eta^5-43808044579418934376632-214023244873618345872240eta^4+11818373349781028079eta^3+347370177721463765064153etaright)timesleft(left(417420z^2-4169121z-15571312right)left(1546z+3537right)left(3092z+17001right)right)^{-1}
end{dmath*}
which produces
IMO the right-alignment is ugly but apparently that's the AMS standard - without the brackets it left aligns all those lines like the alginat
version.
answered 16 hours ago
PhilipPhilip
235
235
add a comment |
add a comment |
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3
For anyone reaching this question in the future, I would strongly recommend writing a simple summation formula with coefficients $a_{i,j}$ and then adding a table to show the values.
– Mefitico
17 hours ago
@Mefitico It is a nice option! Why don't you post an answer?
– JouleV
17 hours ago
1
@JouleV: Because it wouldn't answer the question. Ever heard of the patient who went to the doctor and said: "It hurts when I do this", to which the doctor responded: "Then don't do this!"
– Mefitico
17 hours ago
@Mefitico No, it is still an appropriate expression of the equation, in my opinion. You can see that my answer and egreg's answer use indirect expressions, and you are talking about an indirect expression.
– JouleV
17 hours ago