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I'm trying to create a magic square
How to Determine a Magic Constant in a Magic Square?Magic Matrices?Magic Square Mixups [Challenge]The magic square with a holeComplete the magic square!Unsolved Mysteries: Magic Square of SquaresNo ordinary magic squareMagic-preserving Permutations on a 4x4 Magic SquareCreate a 3x3 Magic Square that uses integers from -10 to -2This four-by-four Magic Square uses all the integers from -7 to 8. Complete the square. More Magic Squares!
$begingroup$
I'm having trouble trying to make a $3times3$ magic square with magic number $12$ and I can't figure it out.
Can you please help me?
mathematics magic-square
New contributor
$endgroup$
add a comment |
$begingroup$
I'm having trouble trying to make a $3times3$ magic square with magic number $12$ and I can't figure it out.
Can you please help me?
mathematics magic-square
New contributor
$endgroup$
1
$begingroup$
While this isn't the most exciting question, I think it's legitimate, and I personally don't see the need for downvotes.
$endgroup$
– Brandon_J
10 hours ago
add a comment |
$begingroup$
I'm having trouble trying to make a $3times3$ magic square with magic number $12$ and I can't figure it out.
Can you please help me?
mathematics magic-square
New contributor
$endgroup$
I'm having trouble trying to make a $3times3$ magic square with magic number $12$ and I can't figure it out.
Can you please help me?
mathematics magic-square
mathematics magic-square
New contributor
New contributor
edited 14 hours ago
JonMark Perry
19.8k64094
19.8k64094
New contributor
asked 15 hours ago
LucyLucy
391
391
New contributor
New contributor
1
$begingroup$
While this isn't the most exciting question, I think it's legitimate, and I personally don't see the need for downvotes.
$endgroup$
– Brandon_J
10 hours ago
add a comment |
1
$begingroup$
While this isn't the most exciting question, I think it's legitimate, and I personally don't see the need for downvotes.
$endgroup$
– Brandon_J
10 hours ago
1
1
$begingroup$
While this isn't the most exciting question, I think it's legitimate, and I personally don't see the need for downvotes.
$endgroup$
– Brandon_J
10 hours ago
$begingroup$
While this isn't the most exciting question, I think it's legitimate, and I personally don't see the need for downvotes.
$endgroup$
– Brandon_J
10 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You need to:
Subtract $1$ from every entry of a magic square with magic number $15$:
8 1 6 --> 7 0 5
3 5 7 --> 2 4 6
4 9 2 --> 3 8 1
$endgroup$
add a comment |
$begingroup$
Alternatively to @JonMarkPerry 's answer, if you don't want to use zero in your answer and you do want to use decimals,
all you need to do is come up with some 9-number sequence whose average is 4. Enter the sequence, in order, into the bottom cell, the top right cell, the left cell, the top left cell, the middle cell, the bottom right cell, the right cell, the bottom left cell, and the top cell. This process will work for any nine-number sequence; the magic number will be three times the number in the middle of the square. In my magic square, the sequence is 2, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6.
3.5| 6 |2.5
---|---|---
3 | 4 | 5
---|---|---
5.5| 2 |4.5
There you go! Enjoy!
$endgroup$
add a comment |
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2 Answers
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oldest
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2 Answers
2
active
oldest
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active
oldest
votes
$begingroup$
You need to:
Subtract $1$ from every entry of a magic square with magic number $15$:
8 1 6 --> 7 0 5
3 5 7 --> 2 4 6
4 9 2 --> 3 8 1
$endgroup$
add a comment |
$begingroup$
You need to:
Subtract $1$ from every entry of a magic square with magic number $15$:
8 1 6 --> 7 0 5
3 5 7 --> 2 4 6
4 9 2 --> 3 8 1
$endgroup$
add a comment |
$begingroup$
You need to:
Subtract $1$ from every entry of a magic square with magic number $15$:
8 1 6 --> 7 0 5
3 5 7 --> 2 4 6
4 9 2 --> 3 8 1
$endgroup$
You need to:
Subtract $1$ from every entry of a magic square with magic number $15$:
8 1 6 --> 7 0 5
3 5 7 --> 2 4 6
4 9 2 --> 3 8 1
edited 15 hours ago
answered 15 hours ago
JonMark PerryJonMark Perry
19.8k64094
19.8k64094
add a comment |
add a comment |
$begingroup$
Alternatively to @JonMarkPerry 's answer, if you don't want to use zero in your answer and you do want to use decimals,
all you need to do is come up with some 9-number sequence whose average is 4. Enter the sequence, in order, into the bottom cell, the top right cell, the left cell, the top left cell, the middle cell, the bottom right cell, the right cell, the bottom left cell, and the top cell. This process will work for any nine-number sequence; the magic number will be three times the number in the middle of the square. In my magic square, the sequence is 2, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6.
3.5| 6 |2.5
---|---|---
3 | 4 | 5
---|---|---
5.5| 2 |4.5
There you go! Enjoy!
$endgroup$
add a comment |
$begingroup$
Alternatively to @JonMarkPerry 's answer, if you don't want to use zero in your answer and you do want to use decimals,
all you need to do is come up with some 9-number sequence whose average is 4. Enter the sequence, in order, into the bottom cell, the top right cell, the left cell, the top left cell, the middle cell, the bottom right cell, the right cell, the bottom left cell, and the top cell. This process will work for any nine-number sequence; the magic number will be three times the number in the middle of the square. In my magic square, the sequence is 2, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6.
3.5| 6 |2.5
---|---|---
3 | 4 | 5
---|---|---
5.5| 2 |4.5
There you go! Enjoy!
$endgroup$
add a comment |
$begingroup$
Alternatively to @JonMarkPerry 's answer, if you don't want to use zero in your answer and you do want to use decimals,
all you need to do is come up with some 9-number sequence whose average is 4. Enter the sequence, in order, into the bottom cell, the top right cell, the left cell, the top left cell, the middle cell, the bottom right cell, the right cell, the bottom left cell, and the top cell. This process will work for any nine-number sequence; the magic number will be three times the number in the middle of the square. In my magic square, the sequence is 2, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6.
3.5| 6 |2.5
---|---|---
3 | 4 | 5
---|---|---
5.5| 2 |4.5
There you go! Enjoy!
$endgroup$
Alternatively to @JonMarkPerry 's answer, if you don't want to use zero in your answer and you do want to use decimals,
all you need to do is come up with some 9-number sequence whose average is 4. Enter the sequence, in order, into the bottom cell, the top right cell, the left cell, the top left cell, the middle cell, the bottom right cell, the right cell, the bottom left cell, and the top cell. This process will work for any nine-number sequence; the magic number will be three times the number in the middle of the square. In my magic square, the sequence is 2, 2.5, 3, 3.5, 4, 4.5, 5, 5.5, 6.
3.5| 6 |2.5
---|---|---
3 | 4 | 5
---|---|---
5.5| 2 |4.5
There you go! Enjoy!
answered 10 hours ago
Brandon_JBrandon_J
2,126231
2,126231
add a comment |
add a comment |
Lucy is a new contributor. Be nice, and check out our Code of Conduct.
Lucy is a new contributor. Be nice, and check out our Code of Conduct.
Lucy is a new contributor. Be nice, and check out our Code of Conduct.
Lucy is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
While this isn't the most exciting question, I think it's legitimate, and I personally don't see the need for downvotes.
$endgroup$
– Brandon_J
10 hours ago