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How to count words in a line

Bash script doesn't TEE output to subdirectoryHow to name a file in the deepest level of a directory treeCount result in a find/exec statementHow to grep the logs for a list of patterns and make a report out of it?Bash scripting to scan files for words and create reportgrep with count of individual patternscount country code in a file and save a file command or bash scripthow to split a comma separated line in bashBrowse directory and extract word from folder nameAwk: Count occurrences of a string in one column, between a range of lines starting 2 lines below pattern 1 and ending with a condition

3

I have a text file called "shoplist.txt" which one have:

drinks water cola fanta

fruit banana orange

And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?

My actually code is:

fileLine=`cat file.txt`

#Here I get each line saving it to fileLine

for line in $fileLine; do

 echo

((aux++))

done

But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)

How can I get the first line and then count the words on that line?

bash shell-script

share|improve this question

edited 13 hours ago

Rui F Ribeiro

41k1479137

asked 13 hours ago

Multi17Multi17

182

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  wc would do the necessary job in a loop.
  
  – Puspharaj Selvaraj
  2 hours ago
  

  
  
  
  

add a comment | 

3

I have a text file called "shoplist.txt" which one have:

drinks water cola fanta

fruit banana orange

And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?

My actually code is:

fileLine=`cat file.txt`

#Here I get each line saving it to fileLine

for line in $fileLine; do

 echo

((aux++))

done

But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)

How can I get the first line and then count the words on that line?

bash shell-script

share|improve this question

edited 13 hours ago

Rui F Ribeiro

41k1479137

asked 13 hours ago

Multi17Multi17

182

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  wc would do the necessary job in a loop.
  
  – Puspharaj Selvaraj
  2 hours ago
  

  
  
  
  

add a comment | 

I have a text file called "shoplist.txt" which one have:

drinks water cola fanta

fruit banana orange

And I want to get how many items per line I have. I'm able to extract drinks and fruit with function "cut" but how can I count how many words I have in each line?

My actually code is:

fileLine=`cat file.txt`

#Here I get each line saving it to fileLine

for line in $fileLine; do

 echo

((aux++))

done

But this code dosen't work because it save to %fileLine each work (drinks, then water,then cola,...)

How can I get the first line and then count the words on that line?

bash shell-script

share|improve this question

edited 13 hours ago

Rui F Ribeiro

41k1479137

asked 13 hours ago

Multi17Multi17

182

drinks water cola fanta

fruit banana orange

fileLine=`cat file.txt`

#Here I get each line saving it to fileLine

for line in $fileLine; do

 echo

((aux++))

done

share|improve this question

edited 13 hours ago

Rui F Ribeiro

41k1479137

asked 13 hours ago

Multi17Multi17

182

share|improve this question

edited 13 hours ago

Rui F Ribeiro

41k1479137

asked 13 hours ago

Multi17Multi17

182

edited 13 hours ago

Rui F Ribeiro

41k1479137

edited 13 hours ago

Rui F Ribeiro

41k1479137

asked 13 hours ago

Multi17Multi17

182

asked 13 hours ago

Multi17Multi17

182

2 Answers
2

active

oldest

votes

13

If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).

Use

awk '{ print NF, $0 }' inputfile

With your sample input, this will print

4 drinks water cola fanta

3 fruit banana orange

share|improve this answer

edited 9 hours ago

Kusalananda

133k17254417

answered 13 hours ago

BodoBodo

1,993314

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.
  
  – Isaac
  3 hours ago
  

  
  
  
  

add a comment | 

2

In Bash and wc:

IFS=$'n'

while read line; do

    wc -w <<< "$line"

done < file.txt

wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.

share|improve this answer

edited 9 hours ago

answered 11 hours ago

sborskysborsky

789511

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Stobor thanks, fixed.
  
  – sborsky
  9 hours ago
  

  
  
  
  

add a comment | 

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13

If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).

Use

awk '{ print NF, $0 }' inputfile

With your sample input, this will print

4 drinks water cola fanta

3 fruit banana orange

share|improve this answer

edited 9 hours ago

Kusalananda

133k17254417

answered 13 hours ago

BodoBodo

1,993314

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.
  
  – Isaac
  3 hours ago
  

  
  
  
  

add a comment | 

13

If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).

Use

awk '{ print NF, $0 }' inputfile

With your sample input, this will print

4 drinks water cola fanta

3 fruit banana orange

share|improve this answer

edited 9 hours ago

Kusalananda

133k17254417

answered 13 hours ago

BodoBodo

1,993314

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The more cryptic awk '$0=NF" "$0' inputfile is a shorter solution.
  
  – Isaac
  3 hours ago
  

  
  
  
  

add a comment | 

If you can use awk, NF is the number of fields in the current line (by default, a field is a word delimited by any amount of whitespace).

Use

awk '{ print NF, $0 }' inputfile

With your sample input, this will print

4 drinks water cola fanta

3 fruit banana orange

share|improve this answer

edited 9 hours ago

Kusalananda

133k17254417

answered 13 hours ago

BodoBodo

1,993314

awk '{ print NF, $0 }' inputfile

4 drinks water cola fanta

3 fruit banana orange

share|improve this answer

edited 9 hours ago

Kusalananda

133k17254417

answered 13 hours ago

BodoBodo

1,993314

edited 9 hours ago

Kusalananda

133k17254417

edited 9 hours ago

Kusalananda

133k17254417

answered 13 hours ago

BodoBodo

1,993314

answered 13 hours ago

BodoBodo

1,993314

2

In Bash and wc:

IFS=$'n'

while read line; do

    wc -w <<< "$line"

done < file.txt

wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.

share|improve this answer

edited 9 hours ago

answered 11 hours ago

sborskysborsky

789511

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Stobor thanks, fixed.
  
  – sborsky
  9 hours ago
  

  
  
  
  

add a comment | 

2

In Bash and wc:

IFS=$'n'

while read line; do

    wc -w <<< "$line"

done < file.txt

wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.

share|improve this answer

edited 9 hours ago

answered 11 hours ago

sborskysborsky

789511

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  @Stobor thanks, fixed.
  
  – sborsky
  9 hours ago
  

  
  
  
  

add a comment | 

In Bash and wc:

IFS=$'n'

while read line; do

    wc -w <<< "$line"

done < file.txt

wc counts lines, words, bytes in files. With a shell loop you can make it count words in a line.

share|improve this answer

edited 9 hours ago

answered 11 hours ago

sborskysborsky

789511

IFS=$'n'

while read line; do

    wc -w <<< "$line"

done < file.txt

share|improve this answer

edited 9 hours ago

answered 11 hours ago

sborskysborsky

789511

answered 11 hours ago

sborskysborsky

789511

answered 11 hours ago

sborskysborsky

789511