Partitioning values in a sequenceOrdering the elements in a list and separate them into sublists for...

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Partitioning values in a sequence


Ordering the elements in a list and separate them into sublists for plottingFinding all partitions of a setPartitioning an image based on featuresPartition list into a given number of sub-listsPartitioning List Into Sublists of Length 2 With The Pairing Being RandomCluster numbers into n partitions so that each partitions sum is closest to total/nEfficient lazy weak compositionsTiming and memory use is critical:fast partitioning of binary sparse arrayVariable iterator in Do Loop (splitting a list)Non-Constant Partitioning of a List with Order AnalysisTotally orderless partition













3












$begingroup$


I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?



Here is the start of the sequence:



list = {2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197};


Thanks.



cheers,
Jamie










share|improve this question











$endgroup$












  • $begingroup$
    Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
    $endgroup$
    – MelaGo
    yesterday
















3












$begingroup$


I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?



Here is the start of the sequence:



list = {2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197};


Thanks.



cheers,
Jamie










share|improve this question











$endgroup$












  • $begingroup$
    Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
    $endgroup$
    – MelaGo
    yesterday














3












3








3





$begingroup$


I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?



Here is the start of the sequence:



list = {2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197};


Thanks.



cheers,
Jamie










share|improve this question











$endgroup$




I have a sequence that forms visible lines when plotted as a graph, what would be a good way to automatically partition the sequence to create a list of sequences, one for each line that is visible when the sequence is plotted?



Here is the start of the sequence:



list = {2,3,5,11,7,23,13,29,41,17,53,37,83,43,89,19,113,131,67,47,73,31,79,173,179,61,191,97,233,239,251,127,139,281,71,293,101,103,107,163,59,359,193,199,137,419,431,443,151,491,509,181,109,277,593,149,307,641,653,659,683,719,241,743,373,761,257,157,263,809,271,409,283,433,911,311,313,953,487,331,499,1013,1019,1031,347,1049,211,269,367,1103,577,167,397,1223,1229,619,1289,223,673,229,461,467,1409,709,1439,1451,727,739,1481,1499,503,1511,1559,1583,1601,401,557,337,853,1733,349,883,197};


Thanks.



cheers,
Jamie







partitions






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday









user64494

3,65311122




3,65311122










asked yesterday









Jamie MJamie M

525




525












  • $begingroup$
    Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
    $endgroup$
    – MelaGo
    yesterday


















  • $begingroup$
    Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
    $endgroup$
    – MelaGo
    yesterday
















$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
yesterday




$begingroup$
Possible duplicate of ordering-the-elements-in-a-list-and-separate-them-into-sublists-for-plotting
$endgroup$
– MelaGo
yesterday










2 Answers
2






active

oldest

votes


















3












$begingroup$

You could for instance fit a mean polynomial function through the data:



fun = NonlinearModelFit[list, a x^2 + b x + c , {a, b, c}, x] //Normal



-48.3941 + 6.86017 x + 0.0161064 x^2




This will separarate the upper line from the lower line that you can see in the plot:



Show[
ListLinePlot[list, PlotRange -> All],
Plot[fun, {x, 0, 125}, PlotRange -> All, PlotStyle -> Red],
PlotRange -> All]


enter image description here



Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:



upperLine = {};
lowerLine = {};
shift=1;
Do[
If[list[[x]] > fun+shift,
AppendTo[upperLine, {x, list[[x]]}],
AppendTo[lowerLine, {x, list[[x]]}]];
, {x, 1, Length[list]}]


The upperLine and lowerLine data sets then look like:



{ListLinePlot[upperLine], ListLinePlot[lowerLine]}


enter image description here



Repeat the process on the lowerLine data to separate the sequences further. For instance for the next line:



newlist = lowerLine;
fun = NonlinearModelFit[newlist, a x^2 + b x + c, {a, b, c}, x] // Normal;
upperLine2 = {};
lowerLine = {};
shift = 10;
Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
AppendTo[upperLine2, newlist[[i]]],
AppendTo[lowerLine, newlist[[i]]]];
, {i, 1, Length[newlist]}]


And the next line:



newlist = lowerLine;
fun = NonlinearModelFit[ newlist[[FindPeaks[newlist[[;; , 2]]][[;; , 1]]]], a x^2 + b x + c, {a, b, c}, x] // Normal;
upperLine3 = {};
lowerLine = {};
shift = -8;
Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
AppendTo[upperLine3, newlist[[i]]],
AppendTo[lowerLine, newlist[[i]]]];
, {i, 1, Length[newlist]}]


So far this looks like:



Show[ListPlot[upperLine, PlotStyle -> Red], 
ListPlot[upperLine2, PlotStyle -> Green],
ListPlot[upperLine3, PlotStyle -> Black],
ListPlot[lowerLine, PlotStyle -> Blue]]


enter image description here



You'll have to play with the shift parameter a bit for optimal results. Just execute the fit first and plot it against newlist, adjust shift and proceed.



PS:



If you have a mathematical model for a function that describes these curves, you could use it with intermediate parameter values instead of the polynomial fit to separate the points much better.






share|improve this answer











$endgroup$













  • $begingroup$
    How could I have the polynomial adjusted upwards, ie offset a certain distance from the max value? the max value will always be in the uppermost line being partitioned out.
    $endgroup$
    – Jamie M
    yesterday










  • $begingroup$
    @JamieM After making the fit, try plotting fun+c instead of fun, where you put a real number for the shift c. This will shift the curve up and down allowing you to separate points a bit more precisely. Is that what you had in mind?
    $endgroup$
    – Kagaratsch
    yesterday



















6












$begingroup$

list = {2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19, 
113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
1733, 349, 883, 197};

upper = FindPeaks[list];

lower = {1, -1} # & /@ FindPeaks[-list];

ListLinePlot[{list, lower, upper},
PlotStyle -> {LightGray, Blue, Red}]


enter image description here






share|improve this answer









$endgroup$














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    2 Answers
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    active

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3












    $begingroup$

    You could for instance fit a mean polynomial function through the data:



    fun = NonlinearModelFit[list, a x^2 + b x + c , {a, b, c}, x] //Normal



    -48.3941 + 6.86017 x + 0.0161064 x^2




    This will separarate the upper line from the lower line that you can see in the plot:



    Show[
    ListLinePlot[list, PlotRange -> All],
    Plot[fun, {x, 0, 125}, PlotRange -> All, PlotStyle -> Red],
    PlotRange -> All]


    enter image description here



    Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:



    upperLine = {};
    lowerLine = {};
    shift=1;
    Do[
    If[list[[x]] > fun+shift,
    AppendTo[upperLine, {x, list[[x]]}],
    AppendTo[lowerLine, {x, list[[x]]}]];
    , {x, 1, Length[list]}]


    The upperLine and lowerLine data sets then look like:



    {ListLinePlot[upperLine], ListLinePlot[lowerLine]}


    enter image description here



    Repeat the process on the lowerLine data to separate the sequences further. For instance for the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[newlist, a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine2 = {};
    lowerLine = {};
    shift = 10;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine2, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    And the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[ newlist[[FindPeaks[newlist[[;; , 2]]][[;; , 1]]]], a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine3 = {};
    lowerLine = {};
    shift = -8;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine3, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    So far this looks like:



    Show[ListPlot[upperLine, PlotStyle -> Red], 
    ListPlot[upperLine2, PlotStyle -> Green],
    ListPlot[upperLine3, PlotStyle -> Black],
    ListPlot[lowerLine, PlotStyle -> Blue]]


    enter image description here



    You'll have to play with the shift parameter a bit for optimal results. Just execute the fit first and plot it against newlist, adjust shift and proceed.



    PS:



    If you have a mathematical model for a function that describes these curves, you could use it with intermediate parameter values instead of the polynomial fit to separate the points much better.






    share|improve this answer











    $endgroup$













    • $begingroup$
      How could I have the polynomial adjusted upwards, ie offset a certain distance from the max value? the max value will always be in the uppermost line being partitioned out.
      $endgroup$
      – Jamie M
      yesterday










    • $begingroup$
      @JamieM After making the fit, try plotting fun+c instead of fun, where you put a real number for the shift c. This will shift the curve up and down allowing you to separate points a bit more precisely. Is that what you had in mind?
      $endgroup$
      – Kagaratsch
      yesterday
















    3












    $begingroup$

    You could for instance fit a mean polynomial function through the data:



    fun = NonlinearModelFit[list, a x^2 + b x + c , {a, b, c}, x] //Normal



    -48.3941 + 6.86017 x + 0.0161064 x^2




    This will separarate the upper line from the lower line that you can see in the plot:



    Show[
    ListLinePlot[list, PlotRange -> All],
    Plot[fun, {x, 0, 125}, PlotRange -> All, PlotStyle -> Red],
    PlotRange -> All]


    enter image description here



    Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:



    upperLine = {};
    lowerLine = {};
    shift=1;
    Do[
    If[list[[x]] > fun+shift,
    AppendTo[upperLine, {x, list[[x]]}],
    AppendTo[lowerLine, {x, list[[x]]}]];
    , {x, 1, Length[list]}]


    The upperLine and lowerLine data sets then look like:



    {ListLinePlot[upperLine], ListLinePlot[lowerLine]}


    enter image description here



    Repeat the process on the lowerLine data to separate the sequences further. For instance for the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[newlist, a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine2 = {};
    lowerLine = {};
    shift = 10;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine2, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    And the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[ newlist[[FindPeaks[newlist[[;; , 2]]][[;; , 1]]]], a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine3 = {};
    lowerLine = {};
    shift = -8;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine3, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    So far this looks like:



    Show[ListPlot[upperLine, PlotStyle -> Red], 
    ListPlot[upperLine2, PlotStyle -> Green],
    ListPlot[upperLine3, PlotStyle -> Black],
    ListPlot[lowerLine, PlotStyle -> Blue]]


    enter image description here



    You'll have to play with the shift parameter a bit for optimal results. Just execute the fit first and plot it against newlist, adjust shift and proceed.



    PS:



    If you have a mathematical model for a function that describes these curves, you could use it with intermediate parameter values instead of the polynomial fit to separate the points much better.






    share|improve this answer











    $endgroup$













    • $begingroup$
      How could I have the polynomial adjusted upwards, ie offset a certain distance from the max value? the max value will always be in the uppermost line being partitioned out.
      $endgroup$
      – Jamie M
      yesterday










    • $begingroup$
      @JamieM After making the fit, try plotting fun+c instead of fun, where you put a real number for the shift c. This will shift the curve up and down allowing you to separate points a bit more precisely. Is that what you had in mind?
      $endgroup$
      – Kagaratsch
      yesterday














    3












    3








    3





    $begingroup$

    You could for instance fit a mean polynomial function through the data:



    fun = NonlinearModelFit[list, a x^2 + b x + c , {a, b, c}, x] //Normal



    -48.3941 + 6.86017 x + 0.0161064 x^2




    This will separarate the upper line from the lower line that you can see in the plot:



    Show[
    ListLinePlot[list, PlotRange -> All],
    Plot[fun, {x, 0, 125}, PlotRange -> All, PlotStyle -> Red],
    PlotRange -> All]


    enter image description here



    Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:



    upperLine = {};
    lowerLine = {};
    shift=1;
    Do[
    If[list[[x]] > fun+shift,
    AppendTo[upperLine, {x, list[[x]]}],
    AppendTo[lowerLine, {x, list[[x]]}]];
    , {x, 1, Length[list]}]


    The upperLine and lowerLine data sets then look like:



    {ListLinePlot[upperLine], ListLinePlot[lowerLine]}


    enter image description here



    Repeat the process on the lowerLine data to separate the sequences further. For instance for the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[newlist, a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine2 = {};
    lowerLine = {};
    shift = 10;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine2, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    And the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[ newlist[[FindPeaks[newlist[[;; , 2]]][[;; , 1]]]], a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine3 = {};
    lowerLine = {};
    shift = -8;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine3, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    So far this looks like:



    Show[ListPlot[upperLine, PlotStyle -> Red], 
    ListPlot[upperLine2, PlotStyle -> Green],
    ListPlot[upperLine3, PlotStyle -> Black],
    ListPlot[lowerLine, PlotStyle -> Blue]]


    enter image description here



    You'll have to play with the shift parameter a bit for optimal results. Just execute the fit first and plot it against newlist, adjust shift and proceed.



    PS:



    If you have a mathematical model for a function that describes these curves, you could use it with intermediate parameter values instead of the polynomial fit to separate the points much better.






    share|improve this answer











    $endgroup$



    You could for instance fit a mean polynomial function through the data:



    fun = NonlinearModelFit[list, a x^2 + b x + c , {a, b, c}, x] //Normal



    -48.3941 + 6.86017 x + 0.0161064 x^2




    This will separarate the upper line from the lower line that you can see in the plot:



    Show[
    ListLinePlot[list, PlotRange -> All],
    Plot[fun, {x, 0, 125}, PlotRange -> All, PlotStyle -> Red],
    PlotRange -> All]


    enter image description here



    Then you can simply run through the list and separate it into two lists based on whether the value is above or below the mean fit:



    upperLine = {};
    lowerLine = {};
    shift=1;
    Do[
    If[list[[x]] > fun+shift,
    AppendTo[upperLine, {x, list[[x]]}],
    AppendTo[lowerLine, {x, list[[x]]}]];
    , {x, 1, Length[list]}]


    The upperLine and lowerLine data sets then look like:



    {ListLinePlot[upperLine], ListLinePlot[lowerLine]}


    enter image description here



    Repeat the process on the lowerLine data to separate the sequences further. For instance for the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[newlist, a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine2 = {};
    lowerLine = {};
    shift = 10;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine2, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    And the next line:



    newlist = lowerLine;
    fun = NonlinearModelFit[ newlist[[FindPeaks[newlist[[;; , 2]]][[;; , 1]]]], a x^2 + b x + c, {a, b, c}, x] // Normal;
    upperLine3 = {};
    lowerLine = {};
    shift = -8;
    Do[If[newlist[[i, 2]] > (fun + shift /. x -> newlist[[i, 1]]),
    AppendTo[upperLine3, newlist[[i]]],
    AppendTo[lowerLine, newlist[[i]]]];
    , {i, 1, Length[newlist]}]


    So far this looks like:



    Show[ListPlot[upperLine, PlotStyle -> Red], 
    ListPlot[upperLine2, PlotStyle -> Green],
    ListPlot[upperLine3, PlotStyle -> Black],
    ListPlot[lowerLine, PlotStyle -> Blue]]


    enter image description here



    You'll have to play with the shift parameter a bit for optimal results. Just execute the fit first and plot it against newlist, adjust shift and proceed.



    PS:



    If you have a mathematical model for a function that describes these curves, you could use it with intermediate parameter values instead of the polynomial fit to separate the points much better.







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited yesterday

























    answered yesterday









    KagaratschKagaratsch

    4,92231350




    4,92231350












    • $begingroup$
      How could I have the polynomial adjusted upwards, ie offset a certain distance from the max value? the max value will always be in the uppermost line being partitioned out.
      $endgroup$
      – Jamie M
      yesterday










    • $begingroup$
      @JamieM After making the fit, try plotting fun+c instead of fun, where you put a real number for the shift c. This will shift the curve up and down allowing you to separate points a bit more precisely. Is that what you had in mind?
      $endgroup$
      – Kagaratsch
      yesterday


















    • $begingroup$
      How could I have the polynomial adjusted upwards, ie offset a certain distance from the max value? the max value will always be in the uppermost line being partitioned out.
      $endgroup$
      – Jamie M
      yesterday










    • $begingroup$
      @JamieM After making the fit, try plotting fun+c instead of fun, where you put a real number for the shift c. This will shift the curve up and down allowing you to separate points a bit more precisely. Is that what you had in mind?
      $endgroup$
      – Kagaratsch
      yesterday
















    $begingroup$
    How could I have the polynomial adjusted upwards, ie offset a certain distance from the max value? the max value will always be in the uppermost line being partitioned out.
    $endgroup$
    – Jamie M
    yesterday




    $begingroup$
    How could I have the polynomial adjusted upwards, ie offset a certain distance from the max value? the max value will always be in the uppermost line being partitioned out.
    $endgroup$
    – Jamie M
    yesterday












    $begingroup$
    @JamieM After making the fit, try plotting fun+c instead of fun, where you put a real number for the shift c. This will shift the curve up and down allowing you to separate points a bit more precisely. Is that what you had in mind?
    $endgroup$
    – Kagaratsch
    yesterday




    $begingroup$
    @JamieM After making the fit, try plotting fun+c instead of fun, where you put a real number for the shift c. This will shift the curve up and down allowing you to separate points a bit more precisely. Is that what you had in mind?
    $endgroup$
    – Kagaratsch
    yesterday











    6












    $begingroup$

    list = {2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19, 
    113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
    127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
    137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
    641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
    271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
    1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
    619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
    739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
    1733, 349, 883, 197};

    upper = FindPeaks[list];

    lower = {1, -1} # & /@ FindPeaks[-list];

    ListLinePlot[{list, lower, upper},
    PlotStyle -> {LightGray, Blue, Red}]


    enter image description here






    share|improve this answer









    $endgroup$


















      6












      $begingroup$

      list = {2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19, 
      113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
      127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
      137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
      641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
      271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
      1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
      619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
      739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
      1733, 349, 883, 197};

      upper = FindPeaks[list];

      lower = {1, -1} # & /@ FindPeaks[-list];

      ListLinePlot[{list, lower, upper},
      PlotStyle -> {LightGray, Blue, Red}]


      enter image description here






      share|improve this answer









      $endgroup$
















        6












        6








        6





        $begingroup$

        list = {2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19, 
        113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
        127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
        137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
        641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
        271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
        1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
        619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
        739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
        1733, 349, 883, 197};

        upper = FindPeaks[list];

        lower = {1, -1} # & /@ FindPeaks[-list];

        ListLinePlot[{list, lower, upper},
        PlotStyle -> {LightGray, Blue, Red}]


        enter image description here






        share|improve this answer









        $endgroup$



        list = {2, 3, 5, 11, 7, 23, 13, 29, 41, 17, 53, 37, 83, 43, 89, 19, 
        113, 131, 67, 47, 73, 31, 79, 173, 179, 61, 191, 97, 233, 239, 251,
        127, 139, 281, 71, 293, 101, 103, 107, 163, 59, 359, 193, 199,
        137, 419, 431, 443, 151, 491, 509, 181, 109, 277, 593, 149, 307,
        641, 653, 659, 683, 719, 241, 743, 373, 761, 257, 157, 263, 809,
        271, 409, 283, 433, 911, 311, 313, 953, 487, 331, 499, 1013, 1019,
        1031, 347, 1049, 211, 269, 367, 1103, 577, 167, 397, 1223, 1229,
        619, 1289, 223, 673, 229, 461, 467, 1409, 709, 1439, 1451, 727,
        739, 1481, 1499, 503, 1511, 1559, 1583, 1601, 401, 557, 337, 853,
        1733, 349, 883, 197};

        upper = FindPeaks[list];

        lower = {1, -1} # & /@ FindPeaks[-list];

        ListLinePlot[{list, lower, upper},
        PlotStyle -> {LightGray, Blue, Red}]


        enter image description here







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered yesterday









        Bob HanlonBob Hanlon

        62k33598




        62k33598






























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