Compilation of a 2d array and a 1d array The Next CEO of Stack OverflowWhat is the most...

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Compilation of a 2d array and a 1d array

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Compilation of a 2d array and a 1d array



The Next CEO of Stack OverflowWhat is the most efficient way to add rows and columns to a matrix?Minor question about optimally increasing last item of a listGetting directly a packed array of repeated packed arraysHow to join and 'multiply' two lists?Finding distance through pair of pointsEfficiently create an array of values of a function2D array summation operationsHow to add zeros before and after each element in a list?Select an element from each matrix row/column specified by a vectorBasis enumeration of large lists












2












$begingroup$


With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}






list-manipulation







share|improve this question











$endgroup$

















    2












    $begingroup$


    With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}






    list-manipulation







    share|improve this question











    $endgroup$















      2












      2








      2





      $begingroup$


      With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}






      list-manipulation







      share|improve this question











      $endgroup$




      With a list say {{x1,y1},{x2,y2}…} and a list {z1}, what is the best way to create a list {{x1,y1,z1},{x2,y2,z1},{x3,y3,z1}…}






      list-manipulation




      list-manipulation






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 2 hours ago









      J. M. is slightly pensive♦

      98.9k10311467




      98.9k10311467










      asked 8 hours ago









      tombom21tombom21

      133




      133






















          2 Answers
          2






          active

          oldest

          votes


















          4












          $begingroup$

          You can use PadRight:



          PadRight[
          
    {{x1, y1}, {x2, y2}},
          
    {Automatic, 3},
          
    z1
          
]



          {{x1, y1, z1}, {x2, y2, z1}}




          Or ArrayPad:



          ArrayPad[
          
    {{x1, y1}, {x2, y2}, {x3, y3}},
          
    {{0,0},{0,1}},
          
    z1
          
]



          {{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}







          share|improve this answer









          $endgroup$





















            1












            $begingroup$

            n = 1000000;
            
a = RandomReal[{-1, 1}, {n, 2}];
            
b = ConstantArray[0., 1];
            
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



            0.016







            share|improve this answer









            $endgroup$














              Your Answer





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              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              4












              $begingroup$

              You can use PadRight:



              PadRight[
              
    {{x1, y1}, {x2, y2}},
              
    {Automatic, 3},
              
    z1
              
]



              {{x1, y1, z1}, {x2, y2, z1}}




              Or ArrayPad:



              ArrayPad[
              
    {{x1, y1}, {x2, y2}, {x3, y3}},
              
    {{0,0},{0,1}},
              
    z1
              
]



              {{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}







              share|improve this answer









              $endgroup$


















                4












                $begingroup$

                You can use PadRight:



                PadRight[
                
    {{x1, y1}, {x2, y2}},
                
    {Automatic, 3},
                
    z1
                
]



                {{x1, y1, z1}, {x2, y2, z1}}




                Or ArrayPad:



                ArrayPad[
                
    {{x1, y1}, {x2, y2}, {x3, y3}},
                
    {{0,0},{0,1}},
                
    z1
                
]



                {{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}







                share|improve this answer









                $endgroup$
















                  4












                  4








                  4





                  $begingroup$

                  You can use PadRight:



                  PadRight[
                  
    {{x1, y1}, {x2, y2}},
                  
    {Automatic, 3},
                  
    z1
                  
]



                  {{x1, y1, z1}, {x2, y2, z1}}




                  Or ArrayPad:



                  ArrayPad[
                  
    {{x1, y1}, {x2, y2}, {x3, y3}},
                  
    {{0,0},{0,1}},
                  
    z1
                  
]



                  {{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}







                  share|improve this answer









                  $endgroup$



                  You can use PadRight:



                  PadRight[
                  
    {{x1, y1}, {x2, y2}},
                  
    {Automatic, 3},
                  
    z1
                  
]



                  {{x1, y1, z1}, {x2, y2, z1}}




                  Or ArrayPad:



                  ArrayPad[
                  
    {{x1, y1}, {x2, y2}, {x3, y3}},
                  
    {{0,0},{0,1}},
                  
    z1
                  
]



                  {{x1, y1, z1}, {x2, y2, z1}, {x3, y3, z1}}








                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 7 hours ago









                  Carl WollCarl Woll

                  72.2k395186




                  72.2k395186























                      1












                      $begingroup$

                      n = 1000000;
                      
a = RandomReal[{-1, 1}, {n, 2}];
                      
b = ConstantArray[0., 1];
                      
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                      0.016







                      share|improve this answer









                      $endgroup$


















                        1












                        $begingroup$

                        n = 1000000;
                        
a = RandomReal[{-1, 1}, {n, 2}];
                        
b = ConstantArray[0., 1];
                        
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                        0.016







                        share|improve this answer









                        $endgroup$
















                          1












                          1








                          1





                          $begingroup$

                          n = 1000000;
                          
a = RandomReal[{-1, 1}, {n, 2}];
                          
b = ConstantArray[0., 1];
                          
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                          0.016







                          share|improve this answer









                          $endgroup$



                          n = 1000000;
                          
a = RandomReal[{-1, 1}, {n, 2}];
                          
b = ConstantArray[0., 1];
                          
c = Join[a, ConstantArray[b, Length[a]], 2]; // RepeatedTiming // First



                          0.016








                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered 8 hours ago









                          Henrik SchumacherHenrik Schumacher

                          58.7k581162




                          58.7k581162






























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