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I am running some php scripts from cli. I use xampp installation for php with path var /c/xampp/php. I tend to swap versions around by renaming installed xampp folders when I want to switch between php5 and 7 etc..

Recently deleted my php5.6 and had to reinstall it. Now for some reason I can run any funciton without passing in the required params and I only get a warning instead of an exception halting executuin.

eg.

    <?php

function someFunction($required_param){

    if (!isset($required_param)) die('WTF! Param was not passed in yet im allowed to execute!');

}

someFunction();

//results with

$ php test/test.php

PHP Warning:  Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2



Warning: Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2

WTF! Param was not passed in!

This is really strange behaviour. I have never seen php allow a function to be called without the required params.

Any ideas how this could happen?

PS-also note that it outputs the error twice even if I disable log errors or display errors to only get a single error output. (the above example is without setting any error handling at run time just what you see is run)

windows command-line php xampp

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asked 9 mins ago

Bradley HayesBradley Hayes

1

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Bradley Hayes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment | 

0

I am running some php scripts from cli. I use xampp installation for php with path var /c/xampp/php. I tend to swap versions around by renaming installed xampp folders when I want to switch between php5 and 7 etc..

Recently deleted my php5.6 and had to reinstall it. Now for some reason I can run any funciton without passing in the required params and I only get a warning instead of an exception halting executuin.

eg.

    <?php

function someFunction($required_param){

    if (!isset($required_param)) die('WTF! Param was not passed in yet im allowed to execute!');

}

someFunction();

//results with

$ php test/test.php

PHP Warning:  Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2



Warning: Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2

WTF! Param was not passed in!

This is really strange behaviour. I have never seen php allow a function to be called without the required params.

Any ideas how this could happen?

PS-also note that it outputs the error twice even if I disable log errors or display errors to only get a single error output. (the above example is without setting any error handling at run time just what you see is run)

windows command-line php xampp

share

asked 9 mins ago

Bradley HayesBradley Hayes

1

New contributor

Bradley Hayes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

I am running some php scripts from cli. I use xampp installation for php with path var /c/xampp/php. I tend to swap versions around by renaming installed xampp folders when I want to switch between php5 and 7 etc..

Recently deleted my php5.6 and had to reinstall it. Now for some reason I can run any funciton without passing in the required params and I only get a warning instead of an exception halting executuin.

eg.

    <?php

function someFunction($required_param){

    if (!isset($required_param)) die('WTF! Param was not passed in yet im allowed to execute!');

}

someFunction();

//results with

$ php test/test.php

PHP Warning:  Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2



Warning: Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2

WTF! Param was not passed in!

This is really strange behaviour. I have never seen php allow a function to be called without the required params.

Any ideas how this could happen?

PS-also note that it outputs the error twice even if I disable log errors or display errors to only get a single error output. (the above example is without setting any error handling at run time just what you see is run)

windows command-line php xampp

share

asked 9 mins ago

Bradley HayesBradley Hayes

1

New contributor

Bradley Hayes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

    <?php

function someFunction($required_param){

    if (!isset($required_param)) die('WTF! Param was not passed in yet im allowed to execute!');

}

someFunction();

$ php test/test.php

PHP Warning:  Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2



Warning: Missing argument 1 for someFunction(), called in C:repophp5ormtesttest.php on line 5 and defined in C:repophp5ormtesttest.php on line 2

WTF! Param was not passed in!

share

asked 9 mins ago

Bradley HayesBradley Hayes

1

New contributor

Bradley Hayes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share

asked 9 mins ago

Bradley HayesBradley Hayes

1

New contributor

Bradley Hayes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 9 mins ago

Bradley HayesBradley Hayes

1

New contributor

Bradley Hayes is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 9 mins ago

Bradley HayesBradley Hayes

1