How will Occam's Razor principle work in Machine learningHow exactly does a validation data-set work work in...

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How will Occam's Razor principle work in Machine learning


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6












$begingroup$


The following question displayed in the image was asked during one of the exams recently. I am not sure if I have correctly understood the Occam's Razor principle or not. According to the distributions and decision boundaries given in the question and following the Occam's Razor the decision boundary B in both the cases should be the answer. Because as per Occam's Razor, choose the simpler classifier which does a decent job rather than the complex one.



Can someone please testify if my understanding is correct and the answer chosen is appropriate or not?
Please help as I am just a beginner in machine learning



the question










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  • 1




    $begingroup$
    3.328 "If a sign is not necessary then it is meaningless. That is the meaning of Occam's Razor." From the Tractatus Logico-Philosophicus by Wittgenstein
    $endgroup$
    – Jorge Barrios
    18 hours ago
















6












$begingroup$


The following question displayed in the image was asked during one of the exams recently. I am not sure if I have correctly understood the Occam's Razor principle or not. According to the distributions and decision boundaries given in the question and following the Occam's Razor the decision boundary B in both the cases should be the answer. Because as per Occam's Razor, choose the simpler classifier which does a decent job rather than the complex one.



Can someone please testify if my understanding is correct and the answer chosen is appropriate or not?
Please help as I am just a beginner in machine learning



the question










share|improve this question







New contributor




user1479198 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$








  • 1




    $begingroup$
    3.328 "If a sign is not necessary then it is meaningless. That is the meaning of Occam's Razor." From the Tractatus Logico-Philosophicus by Wittgenstein
    $endgroup$
    – Jorge Barrios
    18 hours ago














6












6








6


2



$begingroup$


The following question displayed in the image was asked during one of the exams recently. I am not sure if I have correctly understood the Occam's Razor principle or not. According to the distributions and decision boundaries given in the question and following the Occam's Razor the decision boundary B in both the cases should be the answer. Because as per Occam's Razor, choose the simpler classifier which does a decent job rather than the complex one.



Can someone please testify if my understanding is correct and the answer chosen is appropriate or not?
Please help as I am just a beginner in machine learning



the question










share|improve this question







New contributor




user1479198 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




The following question displayed in the image was asked during one of the exams recently. I am not sure if I have correctly understood the Occam's Razor principle or not. According to the distributions and decision boundaries given in the question and following the Occam's Razor the decision boundary B in both the cases should be the answer. Because as per Occam's Razor, choose the simpler classifier which does a decent job rather than the complex one.



Can someone please testify if my understanding is correct and the answer chosen is appropriate or not?
Please help as I am just a beginner in machine learning



the question







machine-learning classification






share|improve this question







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asked yesterday









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  • 1




    $begingroup$
    3.328 "If a sign is not necessary then it is meaningless. That is the meaning of Occam's Razor." From the Tractatus Logico-Philosophicus by Wittgenstein
    $endgroup$
    – Jorge Barrios
    18 hours ago














  • 1




    $begingroup$
    3.328 "If a sign is not necessary then it is meaningless. That is the meaning of Occam's Razor." From the Tractatus Logico-Philosophicus by Wittgenstein
    $endgroup$
    – Jorge Barrios
    18 hours ago








1




1




$begingroup$
3.328 "If a sign is not necessary then it is meaningless. That is the meaning of Occam's Razor." From the Tractatus Logico-Philosophicus by Wittgenstein
$endgroup$
– Jorge Barrios
18 hours ago




$begingroup$
3.328 "If a sign is not necessary then it is meaningless. That is the meaning of Occam's Razor." From the Tractatus Logico-Philosophicus by Wittgenstein
$endgroup$
– Jorge Barrios
18 hours ago










3 Answers
3






active

oldest

votes


















6












$begingroup$

Occam’s razor principle:




Having two hypotheses (here, decision boundaries) that has the same empirical risk (here, training error), a short explanation (here, a boundary with fewer parameters) tends to be more valid than a long explanation.




In your example, both A and B have zero training error, thus B (shorter explanation) is preferred.



What if training error is not the same?



If boundary A had a smaller training error than B, selecting becomes tricky. We need to quantify "explanation size" the same as "empirical risk" and combine the two in one scoring function, then proceed to compare A and B. An example would be Akaike Information Criterion (AIC) that combines empirical risk (measured with negative log-likelihood) and explanation size (measured with the number of parameters) in one score.



As a side note, AIC cannot be used for all models, there are many alternatives to AIC too.



Relation to cross-validation



In many practical cases, when model progresses toward more complexity (larger explanation) to reach lower training error, AIC and the like can be replaced with a validation set (a set on which the model is not trained). We stop the progress when validation error (error of model on validation set) starts to increase. This way, we strike a balance between low training error and short explanation.






share|improve this answer











$endgroup$





















    3












    $begingroup$

    Occam Razor is just a synonym to Parsimony principal. (KISS, Keep it simple and stupid.)
    Most algos work in this principal.



    In above question one has to think in designing the simple separable boundaries,



    like in first picture D1 answer is B.
    As it define the best line separating 2 samples, as a is polynomial and may end up in over-fitting. (if I would have used SVM that line would have come)



    similarly in figure 2 D2 answer is B.






    share|improve this answer








    New contributor




    Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.






    $endgroup$





















      2












      $begingroup$

      Occam’s razor in data-fitting tasks :




      1. First try linear equation

      2. If (1) don't helps much - choose a non-linear one with less terms and/or smaller degrees of variables.


      D2



      B clearly wins, because it's linear boundary which nicely separates data. (What is "nicely" I can't currently define. You have to develop this feeling with experience). A boundary is highly non-linear which seems like a jittered sine wave.



      D1



      However I am not sure about this one. A boundary is like a circle and B is strictly linear. IMHO, for me - boundary line is neither circle segment nor a line segment,- it's parabola-like curve :



      enter image description here



      So I opt for a C :-)






      share|improve this answer








      New contributor




      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      $endgroup$













      • $begingroup$
        I'm still unsure of why you want an in-between line for D1. Occam's Razor says to use the simple solution that works. Absent more data, B is a perfectly valid division that fits the data. If we received more data that suggests more of a curve to B's data set then I could see your argument, but requesting C goes against your point (1), since it's a linear boundary that works.
        $endgroup$
        – Delioth
        9 hours ago











      Your Answer





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      3 Answers
      3






      active

      oldest

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      3 Answers
      3






      active

      oldest

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      active

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      active

      oldest

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      6












      $begingroup$

      Occam’s razor principle:




      Having two hypotheses (here, decision boundaries) that has the same empirical risk (here, training error), a short explanation (here, a boundary with fewer parameters) tends to be more valid than a long explanation.




      In your example, both A and B have zero training error, thus B (shorter explanation) is preferred.



      What if training error is not the same?



      If boundary A had a smaller training error than B, selecting becomes tricky. We need to quantify "explanation size" the same as "empirical risk" and combine the two in one scoring function, then proceed to compare A and B. An example would be Akaike Information Criterion (AIC) that combines empirical risk (measured with negative log-likelihood) and explanation size (measured with the number of parameters) in one score.



      As a side note, AIC cannot be used for all models, there are many alternatives to AIC too.



      Relation to cross-validation



      In many practical cases, when model progresses toward more complexity (larger explanation) to reach lower training error, AIC and the like can be replaced with a validation set (a set on which the model is not trained). We stop the progress when validation error (error of model on validation set) starts to increase. This way, we strike a balance between low training error and short explanation.






      share|improve this answer











      $endgroup$


















        6












        $begingroup$

        Occam’s razor principle:




        Having two hypotheses (here, decision boundaries) that has the same empirical risk (here, training error), a short explanation (here, a boundary with fewer parameters) tends to be more valid than a long explanation.




        In your example, both A and B have zero training error, thus B (shorter explanation) is preferred.



        What if training error is not the same?



        If boundary A had a smaller training error than B, selecting becomes tricky. We need to quantify "explanation size" the same as "empirical risk" and combine the two in one scoring function, then proceed to compare A and B. An example would be Akaike Information Criterion (AIC) that combines empirical risk (measured with negative log-likelihood) and explanation size (measured with the number of parameters) in one score.



        As a side note, AIC cannot be used for all models, there are many alternatives to AIC too.



        Relation to cross-validation



        In many practical cases, when model progresses toward more complexity (larger explanation) to reach lower training error, AIC and the like can be replaced with a validation set (a set on which the model is not trained). We stop the progress when validation error (error of model on validation set) starts to increase. This way, we strike a balance between low training error and short explanation.






        share|improve this answer











        $endgroup$
















          6












          6








          6





          $begingroup$

          Occam’s razor principle:




          Having two hypotheses (here, decision boundaries) that has the same empirical risk (here, training error), a short explanation (here, a boundary with fewer parameters) tends to be more valid than a long explanation.




          In your example, both A and B have zero training error, thus B (shorter explanation) is preferred.



          What if training error is not the same?



          If boundary A had a smaller training error than B, selecting becomes tricky. We need to quantify "explanation size" the same as "empirical risk" and combine the two in one scoring function, then proceed to compare A and B. An example would be Akaike Information Criterion (AIC) that combines empirical risk (measured with negative log-likelihood) and explanation size (measured with the number of parameters) in one score.



          As a side note, AIC cannot be used for all models, there are many alternatives to AIC too.



          Relation to cross-validation



          In many practical cases, when model progresses toward more complexity (larger explanation) to reach lower training error, AIC and the like can be replaced with a validation set (a set on which the model is not trained). We stop the progress when validation error (error of model on validation set) starts to increase. This way, we strike a balance between low training error and short explanation.






          share|improve this answer











          $endgroup$



          Occam’s razor principle:




          Having two hypotheses (here, decision boundaries) that has the same empirical risk (here, training error), a short explanation (here, a boundary with fewer parameters) tends to be more valid than a long explanation.




          In your example, both A and B have zero training error, thus B (shorter explanation) is preferred.



          What if training error is not the same?



          If boundary A had a smaller training error than B, selecting becomes tricky. We need to quantify "explanation size" the same as "empirical risk" and combine the two in one scoring function, then proceed to compare A and B. An example would be Akaike Information Criterion (AIC) that combines empirical risk (measured with negative log-likelihood) and explanation size (measured with the number of parameters) in one score.



          As a side note, AIC cannot be used for all models, there are many alternatives to AIC too.



          Relation to cross-validation



          In many practical cases, when model progresses toward more complexity (larger explanation) to reach lower training error, AIC and the like can be replaced with a validation set (a set on which the model is not trained). We stop the progress when validation error (error of model on validation set) starts to increase. This way, we strike a balance between low training error and short explanation.







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited 20 hours ago

























          answered 21 hours ago









          EsmailianEsmailian

          3865




          3865























              3












              $begingroup$

              Occam Razor is just a synonym to Parsimony principal. (KISS, Keep it simple and stupid.)
              Most algos work in this principal.



              In above question one has to think in designing the simple separable boundaries,



              like in first picture D1 answer is B.
              As it define the best line separating 2 samples, as a is polynomial and may end up in over-fitting. (if I would have used SVM that line would have come)



              similarly in figure 2 D2 answer is B.






              share|improve this answer








              New contributor




              Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.






              $endgroup$


















                3












                $begingroup$

                Occam Razor is just a synonym to Parsimony principal. (KISS, Keep it simple and stupid.)
                Most algos work in this principal.



                In above question one has to think in designing the simple separable boundaries,



                like in first picture D1 answer is B.
                As it define the best line separating 2 samples, as a is polynomial and may end up in over-fitting. (if I would have used SVM that line would have come)



                similarly in figure 2 D2 answer is B.






                share|improve this answer








                New contributor




                Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.






                $endgroup$
















                  3












                  3








                  3





                  $begingroup$

                  Occam Razor is just a synonym to Parsimony principal. (KISS, Keep it simple and stupid.)
                  Most algos work in this principal.



                  In above question one has to think in designing the simple separable boundaries,



                  like in first picture D1 answer is B.
                  As it define the best line separating 2 samples, as a is polynomial and may end up in over-fitting. (if I would have used SVM that line would have come)



                  similarly in figure 2 D2 answer is B.






                  share|improve this answer








                  New contributor




                  Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  $endgroup$



                  Occam Razor is just a synonym to Parsimony principal. (KISS, Keep it simple and stupid.)
                  Most algos work in this principal.



                  In above question one has to think in designing the simple separable boundaries,



                  like in first picture D1 answer is B.
                  As it define the best line separating 2 samples, as a is polynomial and may end up in over-fitting. (if I would have used SVM that line would have come)



                  similarly in figure 2 D2 answer is B.







                  share|improve this answer








                  New contributor




                  Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  share|improve this answer



                  share|improve this answer






                  New contributor




                  Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered 21 hours ago









                  Gaurav DograGaurav Dogra

                  312




                  312




                  New contributor




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                  New contributor





                  Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                  Gaurav Dogra is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.























                      2












                      $begingroup$

                      Occam’s razor in data-fitting tasks :




                      1. First try linear equation

                      2. If (1) don't helps much - choose a non-linear one with less terms and/or smaller degrees of variables.


                      D2



                      B clearly wins, because it's linear boundary which nicely separates data. (What is "nicely" I can't currently define. You have to develop this feeling with experience). A boundary is highly non-linear which seems like a jittered sine wave.



                      D1



                      However I am not sure about this one. A boundary is like a circle and B is strictly linear. IMHO, for me - boundary line is neither circle segment nor a line segment,- it's parabola-like curve :



                      enter image description here



                      So I opt for a C :-)






                      share|improve this answer








                      New contributor




                      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$













                      • $begingroup$
                        I'm still unsure of why you want an in-between line for D1. Occam's Razor says to use the simple solution that works. Absent more data, B is a perfectly valid division that fits the data. If we received more data that suggests more of a curve to B's data set then I could see your argument, but requesting C goes against your point (1), since it's a linear boundary that works.
                        $endgroup$
                        – Delioth
                        9 hours ago
















                      2












                      $begingroup$

                      Occam’s razor in data-fitting tasks :




                      1. First try linear equation

                      2. If (1) don't helps much - choose a non-linear one with less terms and/or smaller degrees of variables.


                      D2



                      B clearly wins, because it's linear boundary which nicely separates data. (What is "nicely" I can't currently define. You have to develop this feeling with experience). A boundary is highly non-linear which seems like a jittered sine wave.



                      D1



                      However I am not sure about this one. A boundary is like a circle and B is strictly linear. IMHO, for me - boundary line is neither circle segment nor a line segment,- it's parabola-like curve :



                      enter image description here



                      So I opt for a C :-)






                      share|improve this answer








                      New contributor




                      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$













                      • $begingroup$
                        I'm still unsure of why you want an in-between line for D1. Occam's Razor says to use the simple solution that works. Absent more data, B is a perfectly valid division that fits the data. If we received more data that suggests more of a curve to B's data set then I could see your argument, but requesting C goes against your point (1), since it's a linear boundary that works.
                        $endgroup$
                        – Delioth
                        9 hours ago














                      2












                      2








                      2





                      $begingroup$

                      Occam’s razor in data-fitting tasks :




                      1. First try linear equation

                      2. If (1) don't helps much - choose a non-linear one with less terms and/or smaller degrees of variables.


                      D2



                      B clearly wins, because it's linear boundary which nicely separates data. (What is "nicely" I can't currently define. You have to develop this feeling with experience). A boundary is highly non-linear which seems like a jittered sine wave.



                      D1



                      However I am not sure about this one. A boundary is like a circle and B is strictly linear. IMHO, for me - boundary line is neither circle segment nor a line segment,- it's parabola-like curve :



                      enter image description here



                      So I opt for a C :-)






                      share|improve this answer








                      New contributor




                      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.






                      $endgroup$



                      Occam’s razor in data-fitting tasks :




                      1. First try linear equation

                      2. If (1) don't helps much - choose a non-linear one with less terms and/or smaller degrees of variables.


                      D2



                      B clearly wins, because it's linear boundary which nicely separates data. (What is "nicely" I can't currently define. You have to develop this feeling with experience). A boundary is highly non-linear which seems like a jittered sine wave.



                      D1



                      However I am not sure about this one. A boundary is like a circle and B is strictly linear. IMHO, for me - boundary line is neither circle segment nor a line segment,- it's parabola-like curve :



                      enter image description here



                      So I opt for a C :-)







                      share|improve this answer








                      New contributor




                      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.









                      share|improve this answer



                      share|improve this answer






                      New contributor




                      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                      answered 15 hours ago









                      Agnius VasiliauskasAgnius Vasiliauskas

                      1213




                      1213




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                      New contributor





                      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                      Agnius Vasiliauskas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                      Check out our Code of Conduct.












                      • $begingroup$
                        I'm still unsure of why you want an in-between line for D1. Occam's Razor says to use the simple solution that works. Absent more data, B is a perfectly valid division that fits the data. If we received more data that suggests more of a curve to B's data set then I could see your argument, but requesting C goes against your point (1), since it's a linear boundary that works.
                        $endgroup$
                        – Delioth
                        9 hours ago


















                      • $begingroup$
                        I'm still unsure of why you want an in-between line for D1. Occam's Razor says to use the simple solution that works. Absent more data, B is a perfectly valid division that fits the data. If we received more data that suggests more of a curve to B's data set then I could see your argument, but requesting C goes against your point (1), since it's a linear boundary that works.
                        $endgroup$
                        – Delioth
                        9 hours ago
















                      $begingroup$
                      I'm still unsure of why you want an in-between line for D1. Occam's Razor says to use the simple solution that works. Absent more data, B is a perfectly valid division that fits the data. If we received more data that suggests more of a curve to B's data set then I could see your argument, but requesting C goes against your point (1), since it's a linear boundary that works.
                      $endgroup$
                      – Delioth
                      9 hours ago




                      $begingroup$
                      I'm still unsure of why you want an in-between line for D1. Occam's Razor says to use the simple solution that works. Absent more data, B is a perfectly valid division that fits the data. If we received more data that suggests more of a curve to B's data set then I could see your argument, but requesting C goes against your point (1), since it's a linear boundary that works.
                      $endgroup$
                      – Delioth
                      9 hours ago










                      user1479198 is a new contributor. Be nice, and check out our Code of Conduct.










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