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6

1

I used to have this command to count how many times I have click with a mouse, the command is xev | grep "ButtonPress".

my colleague modify the command so that it return:

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

and so on... Unfortunately he's no longer contactable so I can't reach him anymore.

I recall the involvement of i++ and something like that, how to reproduce the command?

command-line bash scripts dash-shell

share|improve this question

asked 21 hours ago

Jackie NelsonJackie Nelson

334

New contributor

Jackie Nelson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Do you mean xev | grep -c "ButtonPress", showing the number of clicks on exit?
  
  – dessert
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It shows ButtonPress + number everytime I click on white box pop up window, sorry I'm a novice...
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  dessert, your command worked but it only return the number when I exit xev. How to make it return live value ?
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  

add a comment | 

6

1

I used to have this command to count how many times I have click with a mouse, the command is xev | grep "ButtonPress".

my colleague modify the command so that it return:

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

and so on... Unfortunately he's no longer contactable so I can't reach him anymore.

I recall the involvement of i++ and something like that, how to reproduce the command?

command-line bash scripts dash-shell

share|improve this question

asked 21 hours ago

Jackie NelsonJackie Nelson

334

New contributor

Jackie Nelson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Do you mean xev | grep -c "ButtonPress", showing the number of clicks on exit?
  
  – dessert
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It shows ButtonPress + number everytime I click on white box pop up window, sorry I'm a novice...
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  dessert, your command worked but it only return the number when I exit xev. How to make it return live value ?
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  

add a comment | 

I used to have this command to count how many times I have click with a mouse, the command is xev | grep "ButtonPress".

my colleague modify the command so that it return:

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

and so on... Unfortunately he's no longer contactable so I can't reach him anymore.

I recall the involvement of i++ and something like that, how to reproduce the command?

command-line bash scripts dash-shell

share|improve this question

asked 21 hours ago

Jackie NelsonJackie Nelson

334

New contributor

Jackie Nelson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

share|improve this question

asked 21 hours ago

Jackie NelsonJackie Nelson

334

New contributor

Jackie Nelson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 21 hours ago

Jackie NelsonJackie Nelson

334

New contributor

Jackie Nelson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 21 hours ago

Jackie NelsonJackie Nelson

334

New contributor

Jackie Nelson is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 21 hours ago

Jackie NelsonJackie Nelson

334

1 Answer
1

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oldest

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10

The fact that there's i++ suggests there was either bash or ksh shell in use,potentially awk or perl as well. In either case, we can use process substitution <(...) to feed output of xev to counting loop (although simple pipeline xev | while... could work just fine).

text processing tools:

Portably and for fewer key strokes we can use awk :

$ xev | awk '/ButtonPress/{print "ButtonPress",i++}'

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

perl version:

$ xev | perl -ne '/ButtonPress/ && printf("ButtonPress:%dn",++$i)'

ButtonPress:1

ButtonPress:2

ButtonPress:3

Shells:

Here's what works in bash:

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf 'ButtonPress: %dn' "$i";} ;done < <(xev)

ButtonPress: 1

ButtonPress: 2

ButtonPress: 3

In case you don't want spammy output of many lines, we can use printf to send control code to clear previous line and output only the running count (that is you'd only see integer value change on the line):

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf "r%b" "33[2K"; printf 'ButtonPress: %d' "$i";} ;done < <(xev)

Portably in POSIX shell:

$ xev | ( i=0; while IFS= read -r l; do case "$l" in  *ButtonPress*) i=$((i+1)) && printf 'ButtonPress:%dn' "$i";;  esac ;done)

ButtonPress:1

ButtonPress:2

ButtonPress:3

basic utils:

For simple, quick, and dirty way we can hack this via cat -n with line count being printed on the left instead of right:

$ xev | grep --line-buffered 'ButtonPress' | cat -n

     1  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     2  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     3  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

share|improve this answer

edited 21 hours ago

answered 21 hours ago

Sergiy KolodyazhnyySergiy Kolodyazhnyy

73.7k9154322

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried your first command that has awk in it, it works but there's a bit of lag when the output return
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  However, your second and third command works perfectly, thanks a lot Sergiy
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackieNelson A bit of lag might suggest buffering, which may be related to another awk version in use. Recent Ubuntu uses gawk and before 16.04 default was mawk IIRC. Regardless, glad I could help :)
  
  – Sergiy Kolodyazhnyy
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you make so that the number start from one on perl version ? Not zero
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackieNelson Yep, already changed that
  
  – Sergiy Kolodyazhnyy
  21 hours ago
  

  
  
  
  

 | 
show 3 more comments

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10

The fact that there's i++ suggests there was either bash or ksh shell in use,potentially awk or perl as well. In either case, we can use process substitution <(...) to feed output of xev to counting loop (although simple pipeline xev | while... could work just fine).

text processing tools:

Portably and for fewer key strokes we can use awk :

$ xev | awk '/ButtonPress/{print "ButtonPress",i++}'

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

perl version:

$ xev | perl -ne '/ButtonPress/ && printf("ButtonPress:%dn",++$i)'

ButtonPress:1

ButtonPress:2

ButtonPress:3

Shells:

Here's what works in bash:

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf 'ButtonPress: %dn' "$i";} ;done < <(xev)

ButtonPress: 1

ButtonPress: 2

ButtonPress: 3

In case you don't want spammy output of many lines, we can use printf to send control code to clear previous line and output only the running count (that is you'd only see integer value change on the line):

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf "r%b" "33[2K"; printf 'ButtonPress: %d' "$i";} ;done < <(xev)

Portably in POSIX shell:

$ xev | ( i=0; while IFS= read -r l; do case "$l" in  *ButtonPress*) i=$((i+1)) && printf 'ButtonPress:%dn' "$i";;  esac ;done)

ButtonPress:1

ButtonPress:2

ButtonPress:3

basic utils:

For simple, quick, and dirty way we can hack this via cat -n with line count being printed on the left instead of right:

$ xev | grep --line-buffered 'ButtonPress' | cat -n

     1  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     2  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     3  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

share|improve this answer

edited 21 hours ago

answered 21 hours ago

Sergiy KolodyazhnyySergiy Kolodyazhnyy

73.7k9154322

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried your first command that has awk in it, it works but there's a bit of lag when the output return
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  However, your second and third command works perfectly, thanks a lot Sergiy
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackieNelson A bit of lag might suggest buffering, which may be related to another awk version in use. Recent Ubuntu uses gawk and before 16.04 default was mawk IIRC. Regardless, glad I could help :)
  
  – Sergiy Kolodyazhnyy
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you make so that the number start from one on perl version ? Not zero
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackieNelson Yep, already changed that
  
  – Sergiy Kolodyazhnyy
  21 hours ago
  

  
  
  
  

 | 
show 3 more comments

10

The fact that there's i++ suggests there was either bash or ksh shell in use,potentially awk or perl as well. In either case, we can use process substitution <(...) to feed output of xev to counting loop (although simple pipeline xev | while... could work just fine).

text processing tools:

Portably and for fewer key strokes we can use awk :

$ xev | awk '/ButtonPress/{print "ButtonPress",i++}'

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

perl version:

$ xev | perl -ne '/ButtonPress/ && printf("ButtonPress:%dn",++$i)'

ButtonPress:1

ButtonPress:2

ButtonPress:3

Shells:

Here's what works in bash:

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf 'ButtonPress: %dn' "$i";} ;done < <(xev)

ButtonPress: 1

ButtonPress: 2

ButtonPress: 3

In case you don't want spammy output of many lines, we can use printf to send control code to clear previous line and output only the running count (that is you'd only see integer value change on the line):

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf "r%b" "33[2K"; printf 'ButtonPress: %d' "$i";} ;done < <(xev)

Portably in POSIX shell:

$ xev | ( i=0; while IFS= read -r l; do case "$l" in  *ButtonPress*) i=$((i+1)) && printf 'ButtonPress:%dn' "$i";;  esac ;done)

ButtonPress:1

ButtonPress:2

ButtonPress:3

basic utils:

For simple, quick, and dirty way we can hack this via cat -n with line count being printed on the left instead of right:

$ xev | grep --line-buffered 'ButtonPress' | cat -n

     1  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     2  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     3  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

share|improve this answer

edited 21 hours ago

answered 21 hours ago

Sergiy KolodyazhnyySergiy Kolodyazhnyy

73.7k9154322

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I tried your first command that has awk in it, it works but there's a bit of lag when the output return
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  However, your second and third command works perfectly, thanks a lot Sergiy
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackieNelson A bit of lag might suggest buffering, which may be related to another awk version in use. Recent Ubuntu uses gawk and before 16.04 default was mawk IIRC. Regardless, glad I could help :)
  
  – Sergiy Kolodyazhnyy
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can you make so that the number start from one on perl version ? Not zero
  
  – Jackie Nelson
  21 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @JackieNelson Yep, already changed that
  
  – Sergiy Kolodyazhnyy
  21 hours ago
  

  
  
  
  

 | 
show 3 more comments

The fact that there's i++ suggests there was either bash or ksh shell in use,potentially awk or perl as well. In either case, we can use process substitution <(...) to feed output of xev to counting loop (although simple pipeline xev | while... could work just fine).

text processing tools:

Portably and for fewer key strokes we can use awk :

$ xev | awk '/ButtonPress/{print "ButtonPress",i++}'

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

perl version:

$ xev | perl -ne '/ButtonPress/ && printf("ButtonPress:%dn",++$i)'

ButtonPress:1

ButtonPress:2

ButtonPress:3

Shells:

Here's what works in bash:

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf 'ButtonPress: %dn' "$i";} ;done < <(xev)

ButtonPress: 1

ButtonPress: 2

ButtonPress: 3

In case you don't want spammy output of many lines, we can use printf to send control code to clear previous line and output only the running count (that is you'd only see integer value change on the line):

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf "r%b" "33[2K"; printf 'ButtonPress: %d' "$i";} ;done < <(xev)

Portably in POSIX shell:

$ xev | ( i=0; while IFS= read -r l; do case "$l" in  *ButtonPress*) i=$((i+1)) && printf 'ButtonPress:%dn' "$i";;  esac ;done)

ButtonPress:1

ButtonPress:2

ButtonPress:3

basic utils:

For simple, quick, and dirty way we can hack this via cat -n with line count being printed on the left instead of right:

$ xev | grep --line-buffered 'ButtonPress' | cat -n

     1  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     2  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     3  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

share|improve this answer

edited 21 hours ago

answered 21 hours ago

Sergiy KolodyazhnyySergiy Kolodyazhnyy

73.7k9154322

$ xev | awk '/ButtonPress/{print "ButtonPress",i++}'

ButtonPress 0

ButtonPress 1

ButtonPress 2

ButtonPress 3

$ xev | perl -ne '/ButtonPress/ && printf("ButtonPress:%dn",++$i)'

ButtonPress:1

ButtonPress:2

ButtonPress:3

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf 'ButtonPress: %dn' "$i";} ;done < <(xev)

ButtonPress: 1

ButtonPress: 2

ButtonPress: 3

$ i=0; while IFS= read -r line; do [[ $line =~ ButtonPress ]] && { ((i++)); printf "r%b" "33[2K"; printf 'ButtonPress: %d' "$i";} ;done < <(xev)

$ xev | ( i=0; while IFS= read -r l; do case "$l" in  *ButtonPress*) i=$((i+1)) && printf 'ButtonPress:%dn' "$i";;  esac ;done)

ButtonPress:1

ButtonPress:2

ButtonPress:3

$ xev | grep --line-buffered 'ButtonPress' | cat -n

     1  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     2  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

     3  ButtonPress event, serial 34, synthetic NO, window 0x4a00001,

share|improve this answer

edited 21 hours ago

answered 21 hours ago

Sergiy KolodyazhnyySergiy Kolodyazhnyy

73.7k9154322

answered 21 hours ago

Sergiy KolodyazhnyySergiy Kolodyazhnyy

73.7k9154322

answered 21 hours ago

Sergiy KolodyazhnyySergiy Kolodyazhnyy

73.7k9154322