Count number of li element and addclass2019 Community Moderator ElectionValidate decimal numbers in...
What problems would a superhuman have whose skin is constantly hot?
What will happen if my luggage gets delayed?
Giving a career talk in my old university, how prominently should I tell students my salary?
In the late 1940’s to early 1950’s what technology was available that could melt a LOT of ice?
What ability score modifier does a javelin's damage use?
Are small insurances worth it?
Is it possible to avoid unpacking when merging Association?
Rationale to prefer local variables over instance variables?
How can I get players to focus on the story aspect of D&D?
How do we create new idioms and use them in a novel?
Windows Server Datacenter Edition - Unlimited Virtual Machines
How does Ehrenfest's theorem apply to the quantum harmonic oscillator?
Are all players supposed to be able to see each others' character sheets?
What is better: yes / no radio, or simple checkbox?
When a wind turbine does not produce enough electricity how does the power company compensate for the loss?
Is it a Cyclops number? "Nobody" knows!
Why does liquid water form when we exhale on a mirror?
What do you call someone who likes to pick fights?
Why does cron require MTA for logging?
Can I negotiate a patent idea for a raise, under French law?
I reported the illegal activity of my boss to his boss. My boss found out. Now I am being punished. What should I do?
Can I use a violin G string for D?
How to draw dashed arc of a circle behind pyramid?
Outlet with 3 sets of wires
Count number of li element and addclass
2019 Community Moderator ElectionValidate decimal numbers in JavaScript - IsNumeric()How to efficiently count the number of keys/properties of an object in JavaScript?How do I detect a click outside an element?How do I check if an element is hidden in jQuery?Retrieve the position (X,Y) of an HTML elementCreating a div element in jQueryHow to move an element into another element?Click through div to underlying elementsHow do I remove a particular element from an array in JavaScript?jQuery scroll to element
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
add a comment |
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
1
Your$(this)
is not pointing to.box2
as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2
, hence not working as expected as there is no.box1
after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.
– Andy Hoffman
43 mins ago
It would be great to add$(document).ready(function(){
, around your JQuery operations,
– harish sharma
10 mins ago
add a comment |
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
javascript html css
I am trying to count LI elements, and addclass to another div.
For example,
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
This should be like this
<div class="box2 list3">text</div>
But I don't know why when I check on the DOM code,
<div class="box2 list0">text</div>
I get this result.
What do I need to fix the code?
Please help.
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $(this).find('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
javascript html css
javascript html css
asked 1 hour ago
kk kkkk kk
926
926
1
Your$(this)
is not pointing to.box2
as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2
, hence not working as expected as there is no.box1
after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.
– Andy Hoffman
43 mins ago
It would be great to add$(document).ready(function(){
, around your JQuery operations,
– harish sharma
10 mins ago
add a comment |
1
Your$(this)
is not pointing to.box2
as you expect
– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to.box2
, hence not working as expected as there is no.box1
after it.
– LGSon
49 mins ago
@Mr.Alien Aconsole.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.
– Andy Hoffman
43 mins ago
It would be great to add$(document).ready(function(){
, around your JQuery operations,
– harish sharma
10 mins ago
1
1
Your
$(this)
is not pointing to .box2
as you expect– Mr. Alien
1 hour ago
Your
$(this)
is not pointing to .box2
as you expect– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to
.box2
, hence not working as expected as there is no .box1
after it.– LGSon
49 mins ago
@Mr.Alien It is what it actually does, pointing to
.box2
, hence not working as expected as there is no .box1
after it.– LGSon
49 mins ago
@Mr.Alien A
console.log($(this)
shows that $(this)
is pointing to .box2
. If you reverse the HTML structure of box1
and box2
and change the JavaScript
to return 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start of find
.– Andy Hoffman
43 mins ago
@Mr.Alien A
console.log($(this)
shows that $(this)
is pointing to .box2
. If you reverse the HTML structure of box1
and box2
and change the JavaScript
to return 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start of find
.– Andy Hoffman
43 mins ago
It would be great to add
$(document).ready(function(){
, around your JQuery operations,– harish sharma
10 mins ago
It would be great to add
$(document).ready(function(){
, around your JQuery operations,– harish sharma
10 mins ago
add a comment |
5 Answers
5
active
oldest
votes
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55095760%2fcount-number-of-li-element-and-addclass%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
Pretty close. box1
comes before box2
, so your query beginning at box2
, or $(this)
, would return 0 results as find
looks ahead in the DOM
.
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 1 hour ago
answered 1 hour ago
Andy HoffmanAndy Hoffman
8,07631538
8,07631538
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
thank you for your answer :)
– kk kk
1 hour ago
thank you for your answer :)
– kk kk
1 hour ago
thank you for your answer :)
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
Here $(this)
is referring to box2
element.Only $('.box1 li').length
is what you required
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function() {
return 'list_' + $('.box1 li').length;
});
.list_3 {
color: green;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 1 hour ago
answered 1 hour ago
brkbrk
28.4k32143
28.4k32143
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
thank you this works perfectly
– kk kk
1 hour ago
thank you this works perfectly
– kk kk
1 hour ago
thank you this works perfectly
– kk kk
1 hour ago
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
this is not pointing to the element you are thinking, it is referring to DIV element on which the addClass()
is invoked and this element does not have .box1 li
. Thus find()
is failing to refer your intended element.
Simply use:
$('.box1 li').length
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
console.log(this.nodeName); // DIV
return 'list' + $('.box1 li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 54 mins ago
answered 1 hour ago
MamunMamun
29k71831
29k71831
add a comment |
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$(this).find
will find the li
in the div
with box2
class which are not present. Instead check this in the div
with box1
class and find the li
elements
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass(function(){
return 'list' + $('.box1').find('li').length;
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
edited 21 mins ago
answered 1 hour ago
ellipsisellipsis
7,6962929
7,6962929
add a comment |
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
add a comment |
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
You can simply do this by following method
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
$('.box2').addClass('list' + $('.box1 li').length);
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<ul class="box1">
<li>a</li>
<li>b</li>
<li>c</li>
</ul>
<div class="box2">text</div>
answered 1 hour ago
Sarabjit SinghSarabjit Singh
1169
1169
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f55095760%2fcount-number-of-li-element-and-addclass%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
Your
$(this)
is not pointing to.box2
as you expect– Mr. Alien
1 hour ago
@Mr.Alien It is what it actually does, pointing to
.box2
, hence not working as expected as there is no.box1
after it.– LGSon
49 mins ago
@Mr.Alien A
console.log($(this)
shows that$(this)
is pointing to.box2
. If you reverse the HTML structure ofbox1
andbox2
and change theJavaScript
toreturn 'list' + $(this).find('+ .box1 li').length;
, you'll see it's working properly using the adjacent sibling selector added to the start offind
.– Andy Hoffman
43 mins ago
It would be great to add
$(document).ready(function(){
, around your JQuery operations,– harish sharma
10 mins ago