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What is the difference between rolling more dice versus fewer dice?
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$begingroup$
Let's say there are two attacks: one rolls a 10d10 and the other rolls a 5d20. Assuming the modifier was the same, which rolls would have better chances of rolling average, and which would have better chances of rolling the minimum or maximum?
To specify I am aware that more dice would have a higher avg and min roll but both of those would be by a slim margin and I'm not sure how those would affect your "odds" of hitting each number.
dice statistics
$endgroup$
|
show 2 more comments
$begingroup$
Let's say there are two attacks: one rolls a 10d10 and the other rolls a 5d20. Assuming the modifier was the same, which rolls would have better chances of rolling average, and which would have better chances of rolling the minimum or maximum?
To specify I am aware that more dice would have a higher avg and min roll but both of those would be by a slim margin and I'm not sure how those would affect your "odds" of hitting each number.
dice statistics
$endgroup$
$begingroup$
As it stands, I do not understand this question. Ability checks (if that's what you mean) do not use such rolls, and....well, I don't know at all what you are talking about when you talk about the modifier being the same and having better odds of hitting (abilities aren't used to hit anything). Are you actually talking about D&D?
$endgroup$
– PJRZ
3 hours ago
4
$begingroup$
I think this belongs on Math.SE as a probability question (it has nothing to do with RPGs and is generic enough to be purely a probability question without a specific mechanic involved.)
$endgroup$
– NautArch
3 hours ago
$begingroup$
@PJRZ by ability I meant a magic spell technique or some other form of attack. fixed it.
$endgroup$
– Mage in the Barrel
3 hours ago
$begingroup$
@NautArch And they can do a much better job than we can. I've seent it!
$endgroup$
– Premier Bromanov
2 hours ago
2
$begingroup$
@NautArch I've seen mods move posts to Math. SE, so it might just require moderator attention. That is, you can flag it
$endgroup$
– Premier Bromanov
2 hours ago
|
show 2 more comments
$begingroup$
Let's say there are two attacks: one rolls a 10d10 and the other rolls a 5d20. Assuming the modifier was the same, which rolls would have better chances of rolling average, and which would have better chances of rolling the minimum or maximum?
To specify I am aware that more dice would have a higher avg and min roll but both of those would be by a slim margin and I'm not sure how those would affect your "odds" of hitting each number.
dice statistics
$endgroup$
Let's say there are two attacks: one rolls a 10d10 and the other rolls a 5d20. Assuming the modifier was the same, which rolls would have better chances of rolling average, and which would have better chances of rolling the minimum or maximum?
To specify I am aware that more dice would have a higher avg and min roll but both of those would be by a slim margin and I'm not sure how those would affect your "odds" of hitting each number.
dice statistics
dice statistics
edited 2 hours ago
Tuorg
1,6551719
1,6551719
asked 3 hours ago
Mage in the BarrelMage in the Barrel
1056
1056
$begingroup$
As it stands, I do not understand this question. Ability checks (if that's what you mean) do not use such rolls, and....well, I don't know at all what you are talking about when you talk about the modifier being the same and having better odds of hitting (abilities aren't used to hit anything). Are you actually talking about D&D?
$endgroup$
– PJRZ
3 hours ago
4
$begingroup$
I think this belongs on Math.SE as a probability question (it has nothing to do with RPGs and is generic enough to be purely a probability question without a specific mechanic involved.)
$endgroup$
– NautArch
3 hours ago
$begingroup$
@PJRZ by ability I meant a magic spell technique or some other form of attack. fixed it.
$endgroup$
– Mage in the Barrel
3 hours ago
$begingroup$
@NautArch And they can do a much better job than we can. I've seent it!
$endgroup$
– Premier Bromanov
2 hours ago
2
$begingroup$
@NautArch I've seen mods move posts to Math. SE, so it might just require moderator attention. That is, you can flag it
$endgroup$
– Premier Bromanov
2 hours ago
|
show 2 more comments
$begingroup$
As it stands, I do not understand this question. Ability checks (if that's what you mean) do not use such rolls, and....well, I don't know at all what you are talking about when you talk about the modifier being the same and having better odds of hitting (abilities aren't used to hit anything). Are you actually talking about D&D?
$endgroup$
– PJRZ
3 hours ago
4
$begingroup$
I think this belongs on Math.SE as a probability question (it has nothing to do with RPGs and is generic enough to be purely a probability question without a specific mechanic involved.)
$endgroup$
– NautArch
3 hours ago
$begingroup$
@PJRZ by ability I meant a magic spell technique or some other form of attack. fixed it.
$endgroup$
– Mage in the Barrel
3 hours ago
$begingroup$
@NautArch And they can do a much better job than we can. I've seent it!
$endgroup$
– Premier Bromanov
2 hours ago
2
$begingroup$
@NautArch I've seen mods move posts to Math. SE, so it might just require moderator attention. That is, you can flag it
$endgroup$
– Premier Bromanov
2 hours ago
$begingroup$
As it stands, I do not understand this question. Ability checks (if that's what you mean) do not use such rolls, and....well, I don't know at all what you are talking about when you talk about the modifier being the same and having better odds of hitting (abilities aren't used to hit anything). Are you actually talking about D&D?
$endgroup$
– PJRZ
3 hours ago
$begingroup$
As it stands, I do not understand this question. Ability checks (if that's what you mean) do not use such rolls, and....well, I don't know at all what you are talking about when you talk about the modifier being the same and having better odds of hitting (abilities aren't used to hit anything). Are you actually talking about D&D?
$endgroup$
– PJRZ
3 hours ago
4
4
$begingroup$
I think this belongs on Math.SE as a probability question (it has nothing to do with RPGs and is generic enough to be purely a probability question without a specific mechanic involved.)
$endgroup$
– NautArch
3 hours ago
$begingroup$
I think this belongs on Math.SE as a probability question (it has nothing to do with RPGs and is generic enough to be purely a probability question without a specific mechanic involved.)
$endgroup$
– NautArch
3 hours ago
$begingroup$
@PJRZ by ability I meant a magic spell technique or some other form of attack. fixed it.
$endgroup$
– Mage in the Barrel
3 hours ago
$begingroup$
@PJRZ by ability I meant a magic spell technique or some other form of attack. fixed it.
$endgroup$
– Mage in the Barrel
3 hours ago
$begingroup$
@NautArch And they can do a much better job than we can. I've seent it!
$endgroup$
– Premier Bromanov
2 hours ago
$begingroup$
@NautArch And they can do a much better job than we can. I've seent it!
$endgroup$
– Premier Bromanov
2 hours ago
2
2
$begingroup$
@NautArch I've seen mods move posts to Math. SE, so it might just require moderator attention. That is, you can flag it
$endgroup$
– Premier Bromanov
2 hours ago
$begingroup$
@NautArch I've seen mods move posts to Math. SE, so it might just require moderator attention. That is, you can flag it
$endgroup$
– Premier Bromanov
2 hours ago
|
show 2 more comments
2 Answers
2
active
oldest
votes
$begingroup$
More dice lead to more average results
There are a number of dice calculators around the internet to illustrate the probabilities of whatever combinations you'd like to see, but a general statement is that rolling a combination of dice and summing them for a result will increase the probability of average results and reduce the probability of extreme results as compared with rolling fewer dice.
For a simple example consider 2d4-1 and 1d7 (this is for you @SevenSidedDie) both produce a number between 1 and 7. Your chance of a 1 with the 7-sider is 1 in 7 or about 14%. Your chance with the 2d4 is 1 in 16 (6.25%), because there are 16 different results possible, but only one of them is the 2 ones which give you a 1. On the other hand there are 3 ways to get 3: 1 & 3, 2 & 2, and 3 & 1, so 3 chances in 16 (18.75%), but still only 1 in 7 with the 7-sider.
$endgroup$
add a comment |
$begingroup$
From what I can gather what you're asking, you want to know the probabilistic difference between rolling 10d10 and 5d20. You've rightly pointed out that each roll has the same maximum and that each has a better chance at rolling their given averages. They obviously have different minimums (10 vs 5), and so you want to know precisely how different the rolls are.
Using AnyDice.com we can calculate the probability very simply with the commands output 10d10 and output 5d20. And really that's all there is to it. The black line below represents 10d10, and the yellow line represents 5d20.

Generally speaking, when you have a greater number of smaller dice, your rolls are less "swingy". Meaning, there are better odds at rolling the "average". But, you have worse odds at rolling higher numbers.
Put another way: Look at this graph, it represents the odds that you will roll at least a given number. You can see in general it's better to roll 10d10 because you have greater odds at hitting a certain number until about 60, then 5d20 gives you better odds at hitting those values, but only slightly.

So with 5d20, you have higher odds at hitting a greater range of values, meaning that if you roll 5d20 often, you'll see more "swingy" results. But with 10d10, the odds are more stacked in the middle, meaning it should feel like you're hitting the "average" or the "middle" results more often.
But let's simplify. Lets look at output 2d10 vs output 1d20. Same idea as 10d10 vs 5d20. Here we can see that each value of 1d20 has an equal chance to be rolled. But with 2d10, the odds change because there are a greater number of rolls that represent the middle values (11). there's 10-1, 9-2, 8-3, 7-4, 6-5, 5-6, 4-7, 3-8, 2-9, and 1-10 representing 11. 10% of all the combinations are 11. But for higher values (20), there is only 10-10 representing that, which is only 1% of all possibilities.

Similarly, if you wanted to compare 1d100 to 5d20 and 10d10, you would see a flat probability: a 1% chance for each value between 1 and 100.

$endgroup$
add a comment |
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2 Answers
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2 Answers
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$begingroup$
More dice lead to more average results
There are a number of dice calculators around the internet to illustrate the probabilities of whatever combinations you'd like to see, but a general statement is that rolling a combination of dice and summing them for a result will increase the probability of average results and reduce the probability of extreme results as compared with rolling fewer dice.
For a simple example consider 2d4-1 and 1d7 (this is for you @SevenSidedDie) both produce a number between 1 and 7. Your chance of a 1 with the 7-sider is 1 in 7 or about 14%. Your chance with the 2d4 is 1 in 16 (6.25%), because there are 16 different results possible, but only one of them is the 2 ones which give you a 1. On the other hand there are 3 ways to get 3: 1 & 3, 2 & 2, and 3 & 1, so 3 chances in 16 (18.75%), but still only 1 in 7 with the 7-sider.
$endgroup$
add a comment |
$begingroup$
More dice lead to more average results
There are a number of dice calculators around the internet to illustrate the probabilities of whatever combinations you'd like to see, but a general statement is that rolling a combination of dice and summing them for a result will increase the probability of average results and reduce the probability of extreme results as compared with rolling fewer dice.
For a simple example consider 2d4-1 and 1d7 (this is for you @SevenSidedDie) both produce a number between 1 and 7. Your chance of a 1 with the 7-sider is 1 in 7 or about 14%. Your chance with the 2d4 is 1 in 16 (6.25%), because there are 16 different results possible, but only one of them is the 2 ones which give you a 1. On the other hand there are 3 ways to get 3: 1 & 3, 2 & 2, and 3 & 1, so 3 chances in 16 (18.75%), but still only 1 in 7 with the 7-sider.
$endgroup$
add a comment |
$begingroup$
More dice lead to more average results
There are a number of dice calculators around the internet to illustrate the probabilities of whatever combinations you'd like to see, but a general statement is that rolling a combination of dice and summing them for a result will increase the probability of average results and reduce the probability of extreme results as compared with rolling fewer dice.
For a simple example consider 2d4-1 and 1d7 (this is for you @SevenSidedDie) both produce a number between 1 and 7. Your chance of a 1 with the 7-sider is 1 in 7 or about 14%. Your chance with the 2d4 is 1 in 16 (6.25%), because there are 16 different results possible, but only one of them is the 2 ones which give you a 1. On the other hand there are 3 ways to get 3: 1 & 3, 2 & 2, and 3 & 1, so 3 chances in 16 (18.75%), but still only 1 in 7 with the 7-sider.
$endgroup$
More dice lead to more average results
There are a number of dice calculators around the internet to illustrate the probabilities of whatever combinations you'd like to see, but a general statement is that rolling a combination of dice and summing them for a result will increase the probability of average results and reduce the probability of extreme results as compared with rolling fewer dice.
For a simple example consider 2d4-1 and 1d7 (this is for you @SevenSidedDie) both produce a number between 1 and 7. Your chance of a 1 with the 7-sider is 1 in 7 or about 14%. Your chance with the 2d4 is 1 in 16 (6.25%), because there are 16 different results possible, but only one of them is the 2 ones which give you a 1. On the other hand there are 3 ways to get 3: 1 & 3, 2 & 2, and 3 & 1, so 3 chances in 16 (18.75%), but still only 1 in 7 with the 7-sider.
edited 2 hours ago
answered 3 hours ago
TuorgTuorg
1,6551719
1,6551719
add a comment |
add a comment |
$begingroup$
From what I can gather what you're asking, you want to know the probabilistic difference between rolling 10d10 and 5d20. You've rightly pointed out that each roll has the same maximum and that each has a better chance at rolling their given averages. They obviously have different minimums (10 vs 5), and so you want to know precisely how different the rolls are.
Using AnyDice.com we can calculate the probability very simply with the commands output 10d10 and output 5d20. And really that's all there is to it. The black line below represents 10d10, and the yellow line represents 5d20.

Generally speaking, when you have a greater number of smaller dice, your rolls are less "swingy". Meaning, there are better odds at rolling the "average". But, you have worse odds at rolling higher numbers.
Put another way: Look at this graph, it represents the odds that you will roll at least a given number. You can see in general it's better to roll 10d10 because you have greater odds at hitting a certain number until about 60, then 5d20 gives you better odds at hitting those values, but only slightly.

So with 5d20, you have higher odds at hitting a greater range of values, meaning that if you roll 5d20 often, you'll see more "swingy" results. But with 10d10, the odds are more stacked in the middle, meaning it should feel like you're hitting the "average" or the "middle" results more often.
But let's simplify. Lets look at output 2d10 vs output 1d20. Same idea as 10d10 vs 5d20. Here we can see that each value of 1d20 has an equal chance to be rolled. But with 2d10, the odds change because there are a greater number of rolls that represent the middle values (11). there's 10-1, 9-2, 8-3, 7-4, 6-5, 5-6, 4-7, 3-8, 2-9, and 1-10 representing 11. 10% of all the combinations are 11. But for higher values (20), there is only 10-10 representing that, which is only 1% of all possibilities.

Similarly, if you wanted to compare 1d100 to 5d20 and 10d10, you would see a flat probability: a 1% chance for each value between 1 and 100.

$endgroup$
add a comment |
$begingroup$
From what I can gather what you're asking, you want to know the probabilistic difference between rolling 10d10 and 5d20. You've rightly pointed out that each roll has the same maximum and that each has a better chance at rolling their given averages. They obviously have different minimums (10 vs 5), and so you want to know precisely how different the rolls are.
Using AnyDice.com we can calculate the probability very simply with the commands output 10d10 and output 5d20. And really that's all there is to it. The black line below represents 10d10, and the yellow line represents 5d20.

Generally speaking, when you have a greater number of smaller dice, your rolls are less "swingy". Meaning, there are better odds at rolling the "average". But, you have worse odds at rolling higher numbers.
Put another way: Look at this graph, it represents the odds that you will roll at least a given number. You can see in general it's better to roll 10d10 because you have greater odds at hitting a certain number until about 60, then 5d20 gives you better odds at hitting those values, but only slightly.

So with 5d20, you have higher odds at hitting a greater range of values, meaning that if you roll 5d20 often, you'll see more "swingy" results. But with 10d10, the odds are more stacked in the middle, meaning it should feel like you're hitting the "average" or the "middle" results more often.
But let's simplify. Lets look at output 2d10 vs output 1d20. Same idea as 10d10 vs 5d20. Here we can see that each value of 1d20 has an equal chance to be rolled. But with 2d10, the odds change because there are a greater number of rolls that represent the middle values (11). there's 10-1, 9-2, 8-3, 7-4, 6-5, 5-6, 4-7, 3-8, 2-9, and 1-10 representing 11. 10% of all the combinations are 11. But for higher values (20), there is only 10-10 representing that, which is only 1% of all possibilities.

Similarly, if you wanted to compare 1d100 to 5d20 and 10d10, you would see a flat probability: a 1% chance for each value between 1 and 100.

$endgroup$
add a comment |
$begingroup$
From what I can gather what you're asking, you want to know the probabilistic difference between rolling 10d10 and 5d20. You've rightly pointed out that each roll has the same maximum and that each has a better chance at rolling their given averages. They obviously have different minimums (10 vs 5), and so you want to know precisely how different the rolls are.
Using AnyDice.com we can calculate the probability very simply with the commands output 10d10 and output 5d20. And really that's all there is to it. The black line below represents 10d10, and the yellow line represents 5d20.

Generally speaking, when you have a greater number of smaller dice, your rolls are less "swingy". Meaning, there are better odds at rolling the "average". But, you have worse odds at rolling higher numbers.
Put another way: Look at this graph, it represents the odds that you will roll at least a given number. You can see in general it's better to roll 10d10 because you have greater odds at hitting a certain number until about 60, then 5d20 gives you better odds at hitting those values, but only slightly.

So with 5d20, you have higher odds at hitting a greater range of values, meaning that if you roll 5d20 often, you'll see more "swingy" results. But with 10d10, the odds are more stacked in the middle, meaning it should feel like you're hitting the "average" or the "middle" results more often.
But let's simplify. Lets look at output 2d10 vs output 1d20. Same idea as 10d10 vs 5d20. Here we can see that each value of 1d20 has an equal chance to be rolled. But with 2d10, the odds change because there are a greater number of rolls that represent the middle values (11). there's 10-1, 9-2, 8-3, 7-4, 6-5, 5-6, 4-7, 3-8, 2-9, and 1-10 representing 11. 10% of all the combinations are 11. But for higher values (20), there is only 10-10 representing that, which is only 1% of all possibilities.

Similarly, if you wanted to compare 1d100 to 5d20 and 10d10, you would see a flat probability: a 1% chance for each value between 1 and 100.

$endgroup$
From what I can gather what you're asking, you want to know the probabilistic difference between rolling 10d10 and 5d20. You've rightly pointed out that each roll has the same maximum and that each has a better chance at rolling their given averages. They obviously have different minimums (10 vs 5), and so you want to know precisely how different the rolls are.
Using AnyDice.com we can calculate the probability very simply with the commands output 10d10 and output 5d20. And really that's all there is to it. The black line below represents 10d10, and the yellow line represents 5d20.

Generally speaking, when you have a greater number of smaller dice, your rolls are less "swingy". Meaning, there are better odds at rolling the "average". But, you have worse odds at rolling higher numbers.
Put another way: Look at this graph, it represents the odds that you will roll at least a given number. You can see in general it's better to roll 10d10 because you have greater odds at hitting a certain number until about 60, then 5d20 gives you better odds at hitting those values, but only slightly.

So with 5d20, you have higher odds at hitting a greater range of values, meaning that if you roll 5d20 often, you'll see more "swingy" results. But with 10d10, the odds are more stacked in the middle, meaning it should feel like you're hitting the "average" or the "middle" results more often.
But let's simplify. Lets look at output 2d10 vs output 1d20. Same idea as 10d10 vs 5d20. Here we can see that each value of 1d20 has an equal chance to be rolled. But with 2d10, the odds change because there are a greater number of rolls that represent the middle values (11). there's 10-1, 9-2, 8-3, 7-4, 6-5, 5-6, 4-7, 3-8, 2-9, and 1-10 representing 11. 10% of all the combinations are 11. But for higher values (20), there is only 10-10 representing that, which is only 1% of all possibilities.

Similarly, if you wanted to compare 1d100 to 5d20 and 10d10, you would see a flat probability: a 1% chance for each value between 1 and 100.

edited 2 hours ago
answered 3 hours ago
Premier BromanovPremier Bromanov
12.1k644110
12.1k644110
add a comment |
add a comment |
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$begingroup$
As it stands, I do not understand this question. Ability checks (if that's what you mean) do not use such rolls, and....well, I don't know at all what you are talking about when you talk about the modifier being the same and having better odds of hitting (abilities aren't used to hit anything). Are you actually talking about D&D?
$endgroup$
– PJRZ
3 hours ago
4
$begingroup$
I think this belongs on Math.SE as a probability question (it has nothing to do with RPGs and is generic enough to be purely a probability question without a specific mechanic involved.)
$endgroup$
– NautArch
3 hours ago
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@PJRZ by ability I meant a magic spell technique or some other form of attack. fixed it.
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– Mage in the Barrel
3 hours ago
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@NautArch And they can do a much better job than we can. I've seent it!
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– Premier Bromanov
2 hours ago
2
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@NautArch I've seen mods move posts to Math. SE, so it might just require moderator attention. That is, you can flag it
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– Premier Bromanov
2 hours ago