Extract date from file name Announcing the arrival of Valued Associate #679: Cesar Manara ...

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Extract date from file name



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Windows command-line: create a file with the current date in its nameExtract substring using bashHow to save echo result into a variable?How to extract the filename without the extension from a full path?How to make a bash script that names files with today's datebash extract first number from filenameRemove version information from maven generated war fileHow to change date format in file name using bash/linux?Extract contents from log file for the last 5 minutesLatest file name saving it a variable





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I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?



File Name: GHDC_src_04142019_05_09_32.data.gz


looking the result of that date



04142019 as var=2019-04-14









share|improve this question







New contributor




Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.



























    0















    I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?



    File Name: GHDC_src_04142019_05_09_32.data.gz


    looking the result of that date



    04142019 as var=2019-04-14









    share|improve this question







    New contributor




    Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0








      I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?



      File Name: GHDC_src_04142019_05_09_32.data.gz


      looking the result of that date



      04142019 as var=2019-04-14









      share|improve this question







      New contributor




      Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?



      File Name: GHDC_src_04142019_05_09_32.data.gz


      looking the result of that date



      04142019 as var=2019-04-14






      bash shell






      share|improve this question







      New contributor




      Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 10 hours ago









      Seshi KumarSeshi Kumar

      1




      1




      New contributor




      Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















          1 Answer
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          1














          Since you can "go by position," try:



          $ name=GHDC_src_04142019_05_09_32.data.gz
          $ echo "${name:13:4}-${name:9:2}-${name:11:2}"
          2019-04-14


          Or, to save in a variable:



          name=GHDC_src_04142019_05_09_32.data.gz
          var="${name:13:4}-${name:9:2}-${name:11:2}"


          Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.



          The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.






          share|improve this answer


























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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            Since you can "go by position," try:



            $ name=GHDC_src_04142019_05_09_32.data.gz
            $ echo "${name:13:4}-${name:9:2}-${name:11:2}"
            2019-04-14


            Or, to save in a variable:



            name=GHDC_src_04142019_05_09_32.data.gz
            var="${name:13:4}-${name:9:2}-${name:11:2}"


            Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.



            The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.






            share|improve this answer






























              1














              Since you can "go by position," try:



              $ name=GHDC_src_04142019_05_09_32.data.gz
              $ echo "${name:13:4}-${name:9:2}-${name:11:2}"
              2019-04-14


              Or, to save in a variable:



              name=GHDC_src_04142019_05_09_32.data.gz
              var="${name:13:4}-${name:9:2}-${name:11:2}"


              Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.



              The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.






              share|improve this answer




























                1












                1








                1







                Since you can "go by position," try:



                $ name=GHDC_src_04142019_05_09_32.data.gz
                $ echo "${name:13:4}-${name:9:2}-${name:11:2}"
                2019-04-14


                Or, to save in a variable:



                name=GHDC_src_04142019_05_09_32.data.gz
                var="${name:13:4}-${name:9:2}-${name:11:2}"


                Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.



                The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.






                share|improve this answer















                Since you can "go by position," try:



                $ name=GHDC_src_04142019_05_09_32.data.gz
                $ echo "${name:13:4}-${name:9:2}-${name:11:2}"
                2019-04-14


                Or, to save in a variable:



                name=GHDC_src_04142019_05_09_32.data.gz
                var="${name:13:4}-${name:9:2}-${name:11:2}"


                Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.



                The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 10 hours ago

























                answered 10 hours ago









                John1024John1024

                12.9k43433




                12.9k43433






















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