Extract date from file name Announcing the arrival of Valued Associate #679: Cesar Manara ...
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Extract date from file name
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Windows command-line: create a file with the current date in its nameExtract substring using bashHow to save echo result into a variable?How to extract the filename without the extension from a full path?How to make a bash script that names files with today's datebash extract first number from filenameRemove version information from maven generated war fileHow to change date format in file name using bash/linux?Extract contents from log file for the last 5 minutesLatest file name saving it a variable
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ height:90px;width:728px;box-sizing:border-box;
}
I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?
File Name: GHDC_src_04142019_05_09_32.data.gz
looking the result of that date
04142019 as var=2019-04-14
bash shell
asked 10 hours ago
Seshi KumarSeshi Kumar
1
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?
File Name: GHDC_src_04142019_05_09_32.data.gz
looking the result of that date
04142019 as var=2019-04-14
bash shell
asked 10 hours ago
Seshi KumarSeshi Kumar
1
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?
File Name: GHDC_src_04142019_05_09_32.data.gz
looking the result of that date
04142019 as var=2019-04-14
bash shell
asked 10 hours ago
Seshi KumarSeshi Kumar
1
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm trying to extract the date from a filename and storing it to a variable and also needs to change the date format . If I have the name of the file consistent, can I go by position and extract the date?
File Name: GHDC_src_04142019_05_09_32.data.gz
looking the result of that date
04142019 as var=2019-04-14
bash shell
bash shell
asked 10 hours ago
Seshi KumarSeshi Kumar
1
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 hours ago
Seshi KumarSeshi Kumar
1
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 hours ago
Seshi KumarSeshi Kumar
1
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 10 hours ago
Seshi KumarSeshi Kumar
1
asked 10 hours ago
Seshi KumarSeshi Kumar
1
1
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Seshi Kumar is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
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votes
Since you can "go by position," try:
$ name=GHDC_src_04142019_05_09_32.data.gz
$ echo "${name:13:4}-${name:9:2}-${name:11:2}"
2019-04-14
Or, to save in a variable:
name=GHDC_src_04142019_05_09_32.data.gz
var="${name:13:4}-${name:9:2}-${name:11:2}"
Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.
The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.
answered 10 hours ago
John1024John1024
12.9k43433
add a comment |
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1 Answer
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1 Answer
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active
oldest
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Since you can "go by position," try:
$ name=GHDC_src_04142019_05_09_32.data.gz
$ echo "${name:13:4}-${name:9:2}-${name:11:2}"
2019-04-14
Or, to save in a variable:
name=GHDC_src_04142019_05_09_32.data.gz
var="${name:13:4}-${name:9:2}-${name:11:2}"
Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.
The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.
answered 10 hours ago
John1024John1024
12.9k43433
add a comment |
Since you can "go by position," try:
$ name=GHDC_src_04142019_05_09_32.data.gz
$ echo "${name:13:4}-${name:9:2}-${name:11:2}"
2019-04-14
Or, to save in a variable:
name=GHDC_src_04142019_05_09_32.data.gz
var="${name:13:4}-${name:9:2}-${name:11:2}"
Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.
The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.
answered 10 hours ago
John1024John1024
12.9k43433
add a comment |
Since you can "go by position," try:
$ name=GHDC_src_04142019_05_09_32.data.gz
$ echo "${name:13:4}-${name:9:2}-${name:11:2}"
2019-04-14
Or, to save in a variable:
name=GHDC_src_04142019_05_09_32.data.gz
var="${name:13:4}-${name:9:2}-${name:11:2}"
Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.
The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.
answered 10 hours ago
John1024John1024
12.9k43433
Since you can "go by position," try:
$ name=GHDC_src_04142019_05_09_32.data.gz
$ echo "${name:13:4}-${name:9:2}-${name:11:2}"
2019-04-14
Or, to save in a variable:
name=GHDC_src_04142019_05_09_32.data.gz
var="${name:13:4}-${name:9:2}-${name:11:2}"
Since this uses pure bash, no subprocess needs to be started and no external command needs to be launched. This makes this approach efficient.
The form ${name:offset:length} is called substring expansion. It selects characters from $name starting at offset and continuing for length. In our case, ${name:13:4} captures the year, ${name:9:2} the month, and ${name:11:2} the day.
answered 10 hours ago
John1024John1024
12.9k43433
edited 10 hours ago
answered 10 hours ago
John1024John1024
12.9k43433
answered 10 hours ago
John1024John1024
12.9k43433
answered 10 hours ago
John1024John1024
12.9k43433
12.9k43433
add a comment |
add a comment |
Seshi Kumar is a new contributor. Be nice, and check out our Code of Conduct.
Seshi Kumar is a new contributor. Be nice, and check out our Code of Conduct.
Seshi Kumar is a new contributor. Be nice, and check out our Code of Conduct.
Seshi Kumar is a new contributor. Be nice, and check out our Code of Conduct.
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