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EXCEL SUM Rounding
Make COUNTIFS count duplicate values only onceHow to divide the sum of cells by 7 and then transpose them in ExcelPerform calculations on a cell-by-cell basisAvoiding Long Nested IFs in Excel FunctionReverse Hash with MS ExcelExcel count across multiple criteriaExcel sum if formulain Excel I want trailing 0's on a rounded value that ends up in a text formatted cell, how can I do that?Excel 2016, turning a number into Years and Months automaticallyExcel: How to set up data for Feedback Analysis
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
edited Jan 21 at 19:50
teylyn
17.3k22539
asked Jan 21 at 19:35
AdysAdys
1
add a comment |
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
edited Jan 21 at 19:50
teylyn
17.3k22539
asked Jan 21 at 19:35
AdysAdys
1
add a comment |
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
edited Jan 21 at 19:50
teylyn
17.3k22539
asked Jan 21 at 19:35
AdysAdys
1
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
microsoft-excel worksheet-function microsoft-excel-2010
edited Jan 21 at 19:50
teylyn
17.3k22539
asked Jan 21 at 19:35
AdysAdys
1
edited Jan 21 at 19:50
teylyn
17.3k22539
asked Jan 21 at 19:35
AdysAdys
1
edited Jan 21 at 19:50
teylyn
17.3k22539
edited Jan 21 at 19:50
teylyn
17.3k22539
edited Jan 21 at 19:50
teylyn
17.3k22539
17.3k22539
asked Jan 21 at 19:35
AdysAdys
1
asked Jan 21 at 19:35
AdysAdys
1
asked Jan 21 at 19:35
AdysAdys
1
1
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
answered 6 mins ago
wilsonwilson
3,68811536
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
add a comment |
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
add a comment |
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
17.3k22539
add a comment |
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736, is treated as 0.082644628099174 in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
777213
add a comment |
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
answered 6 mins ago
wilsonwilson
3,68811536
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
answered 6 mins ago
wilsonwilson
3,68811536
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
answered 6 mins ago
wilsonwilson
3,68811536
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999 is rounded to 1.00000000000000, i.e. 1.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001 (15th decimal place), the result will still be 1.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
answered 6 mins ago
wilsonwilson
3,68811536
answered 6 mins ago
wilsonwilson
3,68811536
answered 6 mins ago
wilsonwilson
3,68811536
answered 6 mins ago
wilsonwilson
3,68811536
3,68811536
add a comment |
add a comment |
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