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EXCEL SUM Rounding
Make COUNTIFS count duplicate values only onceHow to divide the sum of cells by 7 and then transpose them in ExcelPerform calculations on a cell-by-cell basisAvoiding Long Nested IFs in Excel FunctionReverse Hash with MS ExcelExcel count across multiple criteriaExcel sum if formulain Excel I want trailing 0's on a rounded value that ends up in a text formatted cell, how can I do that?Excel 2016, turning a number into Years and Months automaticallyExcel: How to set up data for Feedback Analysis
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
add a comment |
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
add a comment |
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
Hello to all Super Users!
I would like to ask about one interesting thing I found today related to sum function within rounding in excel. I have the following set of numbers (they are rounded to full decimal places - no other decimal numbers following in each of the numbers):
0.140495867768595,
0.173553719008264,
0.206611570247934,
0.076741440377804,
0.0826446280991736,
0.118063754427391,
0.063754427390791,
0.0814639905548997,
0.0566706021251476,
When I perform a simple sum function in excel result is equal to 1.0000000000000000 but when I put these numbers into calculator result is equal to 0.9999999999999999 (which is correct) -> my question, therefore, is there any way how to set the behavior of Excel to calculate this correctly and why is it calculating it wrong? Thank you all in advance for your suggestions!
microsoft-excel worksheet-function microsoft-excel-2010
microsoft-excel worksheet-function microsoft-excel-2010
edited Jan 21 at 19:50
teylyn
17.3k22539
17.3k22539
asked Jan 21 at 19:35
AdysAdys
1
1
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736
, is treated as 0.082644628099174
in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999
is rounded to 1.00000000000000
, i.e. 1
.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001
(15th decimal place), the result will still be 1
.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
add a comment |
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
add a comment |
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
Excel number values have 15 digits of precision. Everything after the 15th digit will displayed as a 0.
Microsoft support article
Workaround: If you want to show more than 16 significant digits, you need to enter the value as text, i.e. start with a single quote, then enter the value.
answered Jan 21 at 19:50
teylynteylyn
17.3k22539
17.3k22539
add a comment |
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736
, is treated as 0.082644628099174
in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736
, is treated as 0.082644628099174
in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
add a comment |
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736
, is treated as 0.082644628099174
in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
Excel stores 15 significant digits of precision. So that fifth value in your list -- 0.0826446280991736
, is treated as 0.082644628099174
in the sum. Similarly for the eighth and ninth values in your list.
See https://www.microsoft.com/en-us/microsoft-365/blog/2008/04/10/understanding-floating-point-precision-aka-why-does-excel-give-me-seemingly-wrong-answers/ for more information about how Excel stores numbers.
answered Jan 21 at 19:51
Doug DedenDoug Deden
777213
777213
add a comment |
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999
is rounded to 1.00000000000000
, i.e. 1
.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001
(15th decimal place), the result will still be 1
.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999
is rounded to 1.00000000000000
, i.e. 1
.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001
(15th decimal place), the result will still be 1
.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
add a comment |
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999
is rounded to 1.00000000000000
, i.e. 1
.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001
(15th decimal place), the result will still be 1
.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
Excel only stores 15 significant digits of precision. Anything over 15 significant digits will be rounded.
Therefore, the result 0.9999999999999999
is rounded to 1.00000000000000
, i.e. 1
.
Input Sum (by Excel) Sum (Actual)
------------------- ------------------- -------------------
0.140495867768595 0.140495867768595 0.140495867768595
0.173553719008264 0.314049586776859 0.314049586776859
0.206611570247934 0.520661157024793 0.520661157024793
0.076741440377804 0.597402597402597 0.597402597402597
0.0826446280991736 0.680047225501771 0.6800472255017706
0.118063754427391 0.798110979929162 0.7981109799291616
0.063754427390791 0.861865407319953 0.8618654073199526
0.0814639905548997 0.943329397874852 0.9433293978748523
0.0566706021251476 1.00000000000000 0.9999999999999999
0.000000000000001 1.00000000000000 1.0000000000000009 <-- Bonus information
Bonus: Even if you add another 0.000000000000001
(15th decimal place), the result will still be 1
.
Reference: https://en.wikipedia.org/wiki/Numeric_precision_in_Microsoft_Excel
answered 6 mins ago
wilsonwilson
3,68811536
3,68811536
add a comment |
add a comment |
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