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'Var' does not name a type!



Announcing the arrival of Valued Associate #679: Cesar Manara
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1















I don't have much experience in C++ programming. I'm getting this error



'z' does not name a type!!!



which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!



float x=10; float y=50; float z;
z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}









share|improve this question









New contributor




2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • float z=x*y; will work

    – Juraj
    11 hours ago
















1















I don't have much experience in C++ programming. I'm getting this error



'z' does not name a type!!!



which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!



float x=10; float y=50; float z;
z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}









share|improve this question









New contributor




2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





















  • float z=x*y; will work

    – Juraj
    11 hours ago














1












1








1








I don't have much experience in C++ programming. I'm getting this error



'z' does not name a type!!!



which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!



float x=10; float y=50; float z;
z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}









share|improve this question









New contributor




2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












I don't have much experience in C++ programming. I'm getting this error



'z' does not name a type!!!



which I have't seen in MATLAB or python... What's wrong??? It is so simple!!!



float x=10; float y=50; float z;
z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}






arduino-uno programming c++ error






share|improve this question









New contributor




2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited yesterday









Michel Keijzers

7,13451939




7,13451939






New contributor




2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked yesterday









2012User2012User

154




154




New contributor




2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






2012User is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • float z=x*y; will work

    – Juraj
    11 hours ago



















  • float z=x*y; will work

    – Juraj
    11 hours ago

















float z=x*y; will work

– Juraj
11 hours ago





float z=x*y; will work

– Juraj
11 hours ago










1 Answer
1






active

oldest

votes


















4














You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).



Try the following:



float x=10; float y=50; float z;


void setup() {
// put your setup code here, to run once:
z=x*y;
}

void loop() {
// put your main code here, to run repeatedly:
}


Update



What even is easier and also works (thanks to Ruslan and Juraj):



float x=10; float y=50; float z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}





share|improve this answer


























  • Thank you. pretty much basic thing that I didn't know about C++.

    – 2012User
    yesterday






  • 1





    You can put an expression outside a function (e.g. float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).

    – Ruslan
    23 hours ago













  • @Ruslan Thanks for the clarification; I added the word statement in my answer.

    – Michel Keijzers
    19 hours ago











  • and float z=x*y;

    – Juraj
    11 hours ago











  • @Juraj: Thanks; I added it

    – Michel Keijzers
    9 hours ago












Your Answer






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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).



Try the following:



float x=10; float y=50; float z;


void setup() {
// put your setup code here, to run once:
z=x*y;
}

void loop() {
// put your main code here, to run repeatedly:
}


Update



What even is easier and also works (thanks to Ruslan and Juraj):



float x=10; float y=50; float z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}





share|improve this answer


























  • Thank you. pretty much basic thing that I didn't know about C++.

    – 2012User
    yesterday






  • 1





    You can put an expression outside a function (e.g. float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).

    – Ruslan
    23 hours ago













  • @Ruslan Thanks for the clarification; I added the word statement in my answer.

    – Michel Keijzers
    19 hours ago











  • and float z=x*y;

    – Juraj
    11 hours ago











  • @Juraj: Thanks; I added it

    – Michel Keijzers
    9 hours ago
















4














You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).



Try the following:



float x=10; float y=50; float z;


void setup() {
// put your setup code here, to run once:
z=x*y;
}

void loop() {
// put your main code here, to run repeatedly:
}


Update



What even is easier and also works (thanks to Ruslan and Juraj):



float x=10; float y=50; float z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}





share|improve this answer


























  • Thank you. pretty much basic thing that I didn't know about C++.

    – 2012User
    yesterday






  • 1





    You can put an expression outside a function (e.g. float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).

    – Ruslan
    23 hours ago













  • @Ruslan Thanks for the clarification; I added the word statement in my answer.

    – Michel Keijzers
    19 hours ago











  • and float z=x*y;

    – Juraj
    11 hours ago











  • @Juraj: Thanks; I added it

    – Michel Keijzers
    9 hours ago














4












4








4







You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).



Try the following:



float x=10; float y=50; float z;


void setup() {
// put your setup code here, to run once:
z=x*y;
}

void loop() {
// put your main code here, to run repeatedly:
}


Update



What even is easier and also works (thanks to Ruslan and Juraj):



float x=10; float y=50; float z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}





share|improve this answer















You cannot put an expression statement outside a function. Only the variable declarations can be placed outside functions (and those variables are called globals/global variables).



Try the following:



float x=10; float y=50; float z;


void setup() {
// put your setup code here, to run once:
z=x*y;
}

void loop() {
// put your main code here, to run repeatedly:
}


Update



What even is easier and also works (thanks to Ruslan and Juraj):



float x=10; float y=50; float z=x*y;

void setup() {
// put your setup code here, to run once:
}

void loop() {
// put your main code here, to run repeatedly:
}






share|improve this answer














share|improve this answer



share|improve this answer








edited 9 hours ago

























answered yesterday









Michel KeijzersMichel Keijzers

7,13451939




7,13451939













  • Thank you. pretty much basic thing that I didn't know about C++.

    – 2012User
    yesterday






  • 1





    You can put an expression outside a function (e.g. float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).

    – Ruslan
    23 hours ago













  • @Ruslan Thanks for the clarification; I added the word statement in my answer.

    – Michel Keijzers
    19 hours ago











  • and float z=x*y;

    – Juraj
    11 hours ago











  • @Juraj: Thanks; I added it

    – Michel Keijzers
    9 hours ago



















  • Thank you. pretty much basic thing that I didn't know about C++.

    – 2012User
    yesterday






  • 1





    You can put an expression outside a function (e.g. float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).

    – Ruslan
    23 hours ago













  • @Ruslan Thanks for the clarification; I added the word statement in my answer.

    – Michel Keijzers
    19 hours ago











  • and float z=x*y;

    – Juraj
    11 hours ago











  • @Juraj: Thanks; I added it

    – Michel Keijzers
    9 hours ago

















Thank you. pretty much basic thing that I didn't know about C++.

– 2012User
yesterday





Thank you. pretty much basic thing that I didn't know about C++.

– 2012User
yesterday




1




1





You can put an expression outside a function (e.g. float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).

– Ruslan
23 hours ago







You can put an expression outside a function (e.g. float z=x*y; does have an expression x*y in it, and may appear in namespace scope). What you can't put there is an expression statement (or any other type of statements).

– Ruslan
23 hours ago















@Ruslan Thanks for the clarification; I added the word statement in my answer.

– Michel Keijzers
19 hours ago





@Ruslan Thanks for the clarification; I added the word statement in my answer.

– Michel Keijzers
19 hours ago













and float z=x*y;

– Juraj
11 hours ago





and float z=x*y;

– Juraj
11 hours ago













@Juraj: Thanks; I added it

– Michel Keijzers
9 hours ago





@Juraj: Thanks; I added it

– Michel Keijzers
9 hours ago










2012User is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

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2012User is a new contributor. Be nice, and check out our Code of Conduct.













2012User is a new contributor. Be nice, and check out our Code of Conduct.












2012User is a new contributor. Be nice, and check out our Code of Conduct.
















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